scieee Science in your language
[en] (orig)

Goldbach's conjecture proof By Wadï Mami

Author: Mami, Wadï
Publisher: Zenodo
DOI: 10.5281/zenodo.17546143
Source: https://zenodo.org/records/17546143/files/GoldbachConjectureProofV5.pdf
Goldbach’s conjec u e p o en
By me Wadï Mami
Email : wmami@s eg.com. n / didipos [email protected]
Da e : 30/10/2025
Goldbach's conjec u e is one o he oldes and bes -known unsol ed
p oblems in numbe heo y and all o ma hema ics. I s a es ha
e e y e en na u al numbe g ea e han 2 is he sum o wo p ime
numbe s.
----------------------------------------------------------------------------------------------
A p ime numbe mus be an odd numbe
The sum o 2 odd numbe s is an e en numbe
Then The sum o wo p ime numbe s is an e en numbe (A).
E dös Theo em : Fo e e y in ege n > 1, i exis s always a p ime
numbe be ween n and 2n
(Sou ce : Le Beau li e des Ma hs De Py hago e à la 57 dimension
DUNOD edi ion, au ho Cli o d A.Picko e )
By écu ence o E dös Theo em men ioned abo e and (A)
The e is always k e en numbe which is he sum o wo p ime
numbe s p and q. (B)
p o n n <= p < =2n (i)
q o n/2 n / 2<= q <= n (j)
(i) + (j) n + n /2 <= p+q <= 3n ie
3n/2 <= p+q <= 3n wich implies
k= p+q is an e en numbe because o (A) and n in ege > 1 and k is
be ween lowe limi 3n/2 and uppe limi 3n
(x) = 3x/2 and g(x) = 3x he wo (x) and g(x) a e linea unc ion he
a ea be ween hem ha in e sec o x>0 con ains poin s solu ions
which a e sum o p and q p ime numbe s and hei abscissa a e x
in ege > 1. (B)
We can s a e as we ha e (A) and (B) : e e y e en na u al numbe
g ea e han 2 is he sum o 2 p ime numbe s.
(wha needed o be demons a ed) Goldbach’s conjec u e p o en.
-- Minds, like pa achu es, unc ion bes when open. ,,,
(o o)
/ --------oOO--(_)--OOo--------------------
| Wadï Mami didipos man
| Gi hub : h ps://www.gi hub.com/didipos man