18 Danish Scien i ic Jou nal No100, 2025
MATHEMATICAL SCIENCES
ASIMPTOTIC LINES OF ONE-SHEETED GIPERBOLOID
Abdumajido a Sh.
h ps://doi.o g/10.5281/zenodo.17249782
In oduc ion
Le us conside a su ace π· which is gi en by
equa ion a ound poin π
π=π(π’,π£).
I we in e sec wi h a plane π± passing h ough a
poin π on i , we ob ain a smoo h cu e πΎ passing
h ough poin π in he in e sec ion, which we call such
a cu e a plane sec ion. A plane sec ion πΎ lies in he
plane π± ,so i s o sion is necessa ily ze o.
W i ing he equa ion o he plane sec ion in e ms
o he na u al pa ame e π (i.e., a c leng h), and using
he F ene o mulas o i ( aking in o accoun ha he
o sion is equal o ze o), we w i e:
{π=ππ£
π£=βππ
He e, π is he uni angen ec o , π£ is he uni p in-
cipal no mal ec o , and π is he cu a u e o he cu e
πΎ a poin π(π’0,π£0).. Then o second quad a ic o m
we ha e πΌπΌ(π,π)=(π,π
σ°

)=(ππ£ξ¬¦,π)=πcosπ
He e π is he angle be ween he ec o s π
σ°

and π£ξ¬¦.
Now, i we de ine πΎ by equa ion
π=π(π‘)
(whe e is an a bi a y pa ame e ), hen since π‘ is
a unc ion o π , and conside ing he ollowing equali-
ies, ππ
ππ‘=πβ²=πππ
ππ‘,πβ³=πβ³(ππ
ππ‘)2+πβ²π2π
ππ‘2
we ha e:
πΌπΌ(πβ²,πβ²)=(πβ³,π
σ°

)=(ππ
ππ‘)2(π..,π
σ°

)=(ππ
ππ‘)2πcosπ
We ob ain ollowing equali y
πcosπ=πΌπΌ(πβ²,πβ²)
(ππ
ππ‘)2=πΌπΌ(πβ²,πβ²)
πΌ(πβ²,πβ²)
I can be seen ha he igh side o his equali y
depends only on he ec o πβ². I we ake ano he plane
sec ion πΎβ² o he han πΎ and hey ha e a common angen
(i.e., hey ha e he same di ec ion), hen he igh side
o equali y (1) is he same o hem. Now le he he
plane sec ion be pa allel o he no mal ec o . The e-
o e, equali y (1) becomes:
π=Β±πΌπΌ(πβ²,πβ²)
πΌ(πβ²,πβ²)
De ini ion 1. The numbe πΌπΌ(π
σ°
σ°

β²,π
σ°
σ°

β²)
πΌ(π
σ°
σ°

β²,π
σ°
σ°

β²) ob ained he e is
called he no mal cu a u e o he su ace π· a poin π
in he di ec ion π=Ο±β² and is deno ed by ππ(π) .
Thus, he absolu e alue o he no mal cu a u e
o he su ace in he di ec ion π is equal o he cu a u e
o he no mal sec ion ha de ines he no mal ec o ,
possibly di e ing in sign.
De ini ion 2. I ππ(π)=0 in some di ec ion π,
hen such a di ec ion is called an asymp o ic di ec ion.
Fo a gi en ec o π=(π₯,π¦), i is necessa y and
su icien ha πΏπ₯2+2ππ₯π¦+ππ¦=0 o he di ec ion
de ining he asymp o ic di ec ion. He e, L, M, N a e he
coe icien s o he second quad a ic o m.
De ini ion 3. I a cu e πΎ on a su ace is gi en by
he equa ion π’=π’(π‘),π£=π£(π‘), and i s angen ec o
a any poin de ines he asymp o ic di ec ion, hen such
a cu e is called an asymp o ic cu e.
Na u ally, i a s aigh line lies on a su ace, i is
an asymp o ic line.
We ind he asymp o ic lines o a hype bolic pa-
aboloid. The hype bolic pa aboloid is a su ace o he
second o de and is gi en by he ollowing second-o -
de equa ion: π§=π₯2βπ¦2
We w i e he pa ame ic equa ions o he hype -
bolic pa aboloid:
π₯=π’,π¦=π£,π§=π’2βπ£2
To calcula e he i s and second quad a ic o ms ,
we need o know he ec o s deno ed by
ππ’
σ°
σ°
σ°

={1,0,2π’} ππ£
σ°
σ°
σ°

={1,0,β2π£} ππ’π’
σ°
σ°
σ°
σ°
σ°

={0,0,2}
ππ’π£
σ°
σ°
σ°
σ°
σ°

={0,0,0} ππ£π£
σ°
σ°
σ°
σ°
σ°

={0,0,β2}
The coe isien s o he i s and second quad a ic
o ms a e πΈ=1+4π’2,πΉ=β4π’π£,πΊ=1+4π£2,
πΏ= 2
β1+4π’2+4π£2,π=0,π= β2
β1+4π’2+4π£2
We cons uc he di e en ial equa ion o asymp-
o ic lines: ππ’2βππ£2=0
I s solu ions a e:
π’1=π‘+π1, π’2=βπ‘+π
Thus, he equa ions o he asymp o ic lines o he
hype bolic pa aboloid in space a e:
πΎ1:{π₯=π‘+π1
π¦=π‘
π§=2π1π‘+π12 πΎ2:{π₯=π‘+π2
π¦=π‘
π§=2π2π‘+π2
2
Asymp o ic lines o a one-shee hype boloid
A one-shee hype boloid is a quad a ic su ace o
second o de , gi en by he ollowing equa ion:
π₯2
π2+π¦2
π2βπ§2
π2=0
Pa ame ic equa ions o he one-shee hype boloid
π₯=πππ π’πβπ£,π¦=ππ πππ’πβπ£,π§=ππ βπ£,
O , in ec o o m:
π={ππππ π’πβπ£,ππ πππ’πβπ£,ππ βπ£}
To compu e he i s and second quad a ic o ms,
we calcula e he pa ial de i a i es:
ππ’={βππ πππ’πβπ£,ππππ π’πβπ£,0}, ππ’π’
={βππππ π’πβπ£,βππ πππ’πβπ£,0}, ππ£
={ππππ π’π βπ£,ππ πππ’π βπ£,ππβπ£},
ππ£π£ ={ππππ π’πβπ£,ππ πππ’πβπ£,ππ βπ£},ππ’π£
={βππ πππ’π βπ£,ππππ π’π βπ£,0}
The calcula ion o he i s quad a ic o ms yields
πΈ=ππ’2
σ°
σ°
σ°
σ°

=π₯π’
2+π¦π’
2+π§π’
2πΉ=ππ’π£
σ°
σ°
σ°
σ°
σ°

=π₯π’π₯π£+π¦π’π¦π£+π§π’π§π£πΊ=ππ£2
σ°
σ°
σ°
σ°

=π₯π£
2+π¦π£2+π§π£
2
Danish Scien i ic Jou nal No100, 2025 19
πΈ=π2π ππ2π’πβ2π£+π2πππ 2π’πβ2π£=π2πβ2π£,πΉ
=βπ2π πππ’πππ π’πβπ£π βπ£
+π2π πππ’πππ π’πβπ£π βπ£=0
, πΊ=π2πππ 2π’π β2π£+π2π ππ2π’π β2π£+
π2πβ2π£=π2π β2π£+π2πβ2π£=π2πβ2π£
The calcula ion o he second quad a ic o ms
yields
πΏ=
β£
β£
β£
β£
π₯π’π’ π¦π’π’ π§π’π’
π₯π’π¦π’π§π’
π₯π£π¦π£π§π£
β£
β£
β£
β£
βπΈπΊβπΉ2,π=
β£
β£
β£
β£
π₯π’π£ π¦π’π£ π§π’π£
π₯π’π¦π’π§π’
π₯π£π¦π£π§π£
β£
β£
β£
β£
βπΈπΊβπΉ2,π
=
β£
β£
β£
β£
π₯π£π£ π¦π£π£ π§π£π£
π₯π’π¦π’π§π’
π₯π£π¦π£π§π£
β£
β£
β£
β£
βπΈπΊβπΉ2
πΏ=βπ3πβ3π£, π=0, π=2π3πβπ£
The di e en ial equa ion o he asymp o ic lines is
de i ed as ollows
πΏππ’2+2πππ’ππ£+πππ£2=0
βπ3πβ3π£ππ’2+2π2πβπ£ππ£2=0
πβ2π£ππ’2=2ππ£2
{ππ’
ππ£}2=2
πβ2π£
β«ππ’=β« β2
πβπ£ππ£=β« 2β2
ππ£+πβπ£ππ£=2β2β« ππ£ππ£
π2π£+1
=πππ£
(ππ£)2+1
The in insic coo dina e equa ions o he asymp-
o ic lines can be exp essed in he o m
π’1=2β2ππππ‘πππ£
π’2=β2β2ππππ‘πππ£
The spa ial equa ions o he asymp o ic lines o he
one-shee hype boloid can be w i en in he o m
πΎ1:π₯=ππππ (2β2ππππ‘πππ‘)πβπ‘,π¦
=ππ ππ(2β2ππππ‘πππ‘)πβπ‘,π§=ππ βπ‘
πΎ2:π₯=ππππ (2β2ππππ‘πππ‘)πβπ‘,π¦
=βππ ππ(2β2ππππ‘πππ‘)πβπ‘,π§
=ππ βπ‘
Re e ences:
1. A. Na mano . Di e ensial geome iya a
opologiya. (1), (2018).
2. M.A.Sobi o , A.Y. Yusupo . Di e ensial ge-
ome iya ku s., (2) (1959), 158
3. A.Ya.Na mano , A.S.Sha ipo ,
J.O.A slono . Di e ensial geome iya a opologiya
ku sidan masalala oβplami. (2014)