scieee Science in your language
[en] (orig)

A Monte Carlo comparison of three consistent bootstrap procedures

Abstract

Since bootstrap samples are simple random samples with replacement from the original sample, the information content of some bootstrap samples can be very low. To avoid this fact, some authors have proposed several variants of the classical bootstrap. In this paper we consider two of them: the sequential or Poisson bootstrap and the reduced bootstrap. Both of them, like ordinary bootstrap, can yield second order accurate distribution estimators, that is, the three bootstrap procedures are asymptotically equivalent. The question that naturally arises is which of them should be used in a practical situation, in other words, which of them should be used for finite sample sizes. To try to answer this question, we have carried out a simulation study. Although no method was found to exhibit best performance in all the considered situations, some recommendations are given.

Read accessible full text

A Monte Carlo comparison of three consistent bootstrap procedures

Author: Pino Mejías, Rafael; Jiménez Gamero, María Dolores; Enguix González, Alicia
Publisher: Taylor & Francis
Year: 2009
DOI: 10.1080/00949650701758357
Source: https://idus.us.es/bitstreams/2ae7dda5-e264-44f6-8499-a86e9818afca/download
Vol. 00, No. 00, Mon h 200x, 1–11
A Mon e Ca lo compa ison o h ee consis en boo s ap
p ocedu es
R. Pino Mej´ıas∗†, M.D. Jim´enez Game o†, A. Enguix Gonz´alez†
†Dp o. de Es ad´ıs ica e In es igaci´on Ope a i a, Uni e sidad de Se illa, Facul ad de
Ma em´a icas, C/ Ta ia s.n., 41.012 Se illa, Spain
(Recei ed 00 Mon h 200x; In inal o m 00 Mon h 200x)
Since boo s ap samples a e simple andom samples wi h eplacemen om he o iginal sample, he
in o ma ion con en o some boo s ap samples can be e y low. To a oid his ac , some au ho s
ha e p oposed se e al a ian s o he classical boo s ap. In his pape we conside wo o hem: he
sequen ial o Poisson boo s ap and he educed boo s ap. Bo h o hem, like o dina y boo s ap,
can yield second o de accu a e dis ibu ion es ima o s, ha is, he h ee boo s ap p ocedu es a e
asymp o ically equi alen . The ques ion ha na u ally a ises is which o hem should be used in a
p ac ical si ua ion, in o he wo ds, which o hem should be used o ini e sample sizes. To y o
answe his ques ion, we ha e ca ied ou a simula ion s udy. Al hough no me hod was ound o
exhibi bes pe o mance in all he conside ed si ua ions, some ecommenda ions a e gi en.
Keywo ds: Boo s ap, Poisson boo s ap, educed boo s ap, dis ibu ion es ima ion, ini e sample
pe o mance.
1 In oduc ion
The boo s ap, in oduced by E on [1], is a powe ul ool o nonpa ame ic es-
ima ion o sampling dis ibu ions and s anda d e o s. I may be desc ibed as
ollows. Le X= (X1, X2, . . . , Xn) be a andom sample om an unknown dis-
ibu ion F, and le Tn=Tn(X;F) be a s a is ic o in e es . Le Fnbe he em-
pi ical dis ibu ion unc ion o X1, X2, . . . , Xnand le X∗= (X∗
1, X∗
2, . . . , X∗
n)
be a andom sample d awn om Fn.X∗is called a boo s ap sample. The
boo s ap me hod es ima es he dis ibu ion o Tn h ough he condi ional
dis ibu ion o T∗
n=Tn(X∗;Fn), gi en X1, X2, . . . , Xn.
Boo s ap samples a e simple andom samples o size nselec ed wi h eplace-
men om he o iginal sample. Thus, all boo s ap samples a e no equally
in o ma i e, when he in o ma ion con en o X∗is measu ed h ough he
numbe o dis inc o iginal obse a ions in i , νn. As Rao e al. [2] asse , his
∗Co esponding au ho . E-mail: [email p o ec ed]
2R. Pino Mej´ıas e al.
a iabili y is nei he necessa y no desi able. To a oid i , hese au ho s ha e
in oduced a sequen ial sampling me hod ha keeps cons an he in o ma ion
con en o boo s ap samples, he sequen ial o Poisson boo s ap (o iginally,
hey named i sequen ial boo s ap; he name Poisson boo s ap was gi en
la e by Babu e al. [3]). I consis s o sampling sequen ially (wi h eplace-
men om he o iginal sample) un il mdis inc o iginal obse a ions appea .
To keep he in o ma ion cons an , his me hod in oduces ano he sou ce o
a iabili y: he size o he sequen ial boo s ap samples.
To educe he a iabili y o νn, keeping he size o boo s ap samples ixed,
Jim´enez-Game o e al. [4] ha e in oduced a modi ied boo s ap ha consis s
o only conside ing hose boo s ap samples sa is ying k1≤νn≤k2, o some
1≤k1≤k2≤n. They call i he educed boo s ap, since i only uses a
po ion o he se o all possible boo s ap samples. The me hod is an ex ension
o he one in oduced by Mu˜noz-Ga c´ıa e al. [5], ha akes k2=n. No e ha
o dina y boo s ap is a pa icula case o educed boo s ap wi h k1= 1 and
k2=n.
Ano he me hod o educe he a iabili y o νn, keeping he size o boo -
s ap samples ixed, can be ound in S ombe g [6]. In o de o educe he
b eakdown poin o he boo s ap a iance es ima o , which is 1/n ega dless
o he b eakdown poin o he es ima o due o he ac ha P(νn=n)>0,
S ombe g [6] p oposed o use a ”limi ed eplacemen boo s ap”, in which
all boo s ap samples selec ing he same elemen mo e han m∗ imes a e
excluded, ha is, i only conside s hose boo s ap samples wi h Ni≤m∗,
1≤i≤n, whe e Ni=ca d{j:X∗
j=Xi}, 1 ≤i≤n. As be o e, no e ha
o dina y boo s ap is a pa icula case o limi ed eplacemen boo s ap wi h
m∗=n.
Singh [7] has shown ha he boo s ap es ima o o he dis ibu ion o he
sample mean is consis en and ha i can be mo e accu a e han he ap-
p oxima ion gi en by he cen al limi heo em when highe -o de popula ion
momen s exis . Babu and Singh [8] ha e ex ended hese esul s o unc ions
o mul i a ia e means and hei s uden ized e sions. Babu e al. [3] ha e
shown ha hey a e also ue o he sequen ial boo s ap when m=E(νn).
Jim´enez-Game o e al. [9] ha e also p o en hem o he educed boo s ap,
o ce ain choices o k1and k2. The e o e, he esul s in Babu e al. [3] and
Jim´enez-Game o e al. [9] e eal ha he usual boo s ap high a iabili y o
νnis no necessa y. To ou knowledge he e is no simila esul o he limi ed
eplacemen boo s ap o S ombe g [6] so, om now on we will no conside
his me hod.
In summa y, he abo e ci ed esul s ell us ha we ha e h ee me hods
o consis en ly es ima e he dis ibu ion unc ion o s a is ics in an impo an
class ( he unc ions o mul i a ia e means and hei s uden ized e sions), ha
is, all o hem beha e simila ly o la ge samples. The ques ion ha na u ally
Compa ison o boo s ap p ocedu es 3
a ises is which o hem should be used in a p ac ical si ua ion, ha is, o
ini e sample sizes. In o de o y o answe his ques ion, we ha e ca ied ou
a simula ion s udy. Al hough i is no exhaus i e (i is impossible o simula e
all cases), we can conclude some gene al ecommenda ions om he ob ained
esul s.
The pape is o ganized as ollows. In Sec ion 2 we b ie ly e iew he me hods
o be compa ed. In Sec ion 3 we desc ibe he simula ions and display he
ob ained esul s. Sec ion 4 concludes gi ing some p ac ical ecommenda ions
in he ligh o he ob ained esul s.
2 The me hods
In his Sec ion we i s s udy he a iabili y educ ion p ope ies o he consid-
e ed me hods, and hen we e iew some p ope ies o he co esponding dis i-
bu ion es ima o s. He e we only e iew he second o de co ec ness p ope ies
because hey jus make he conside ed dis ibu ion es ima o s o ha e an edge
o e he app oxima ion by he limi ing no mal dis ibu ion.
2.1 Va iabili y educ ion p ope ies
As in he In oduc ion, le νndeno e he numbe o dis inc obse a ions in a
boo s ap sample. Then unde o dina y boo s ap,
E(νn) = n·1−µ1−1
n¶n¸≃0.632n,
a (νn) = nµ1−1
n¶n
+n(n−1) µ1−2
n¶n
−n2µ1−1
n¶2n
≃0.233n,
To educe he a iabili y o νn, he sequen ial boo s ap d aws obse a ions
om he o iginal sample wi h eplacemen un il he e a e m≃E(νn) dis-
inc obse a ions in he boo s ap sample. This way, he numbe o dis inc
obse a ions is no longe a andom a iable. Ne e heless, he me hod yields
boo s ap samples wi h andom size N. The expec a ion and he a iance o
Na e (see Rao e al. [2])
E(N) = nµ1
n+1
n−1+... +1
n−m+ 1¶=n+O(1),
4R. Pino Mej´ıas e al.
a (N) =
m
X
j=1
n(j−1)
(n−j+ 1)2=n(e−1) + O(1).
Nex esul gi es he expec a ion and he a iance o νn o he educed
boo s ap (see Appendix C o a p oo ).
P oposi ion 2.1 Le X∗be a boo s ap sample, νn=νn(X∗)and le k1, k2
be wo posi i e in ege s wi h 1≤k1≤k2≤n. Then,
E(νn|k1≤νn≤k2) = k2−(k2−k1)µ1−1
k2¶n−k1
and
a (νn|k1≤νn≤k2) = (k2−k1)(k2−k1−1) µ1−2
k2¶n−k1
+
+(k2−k1)µ1−1
k2¶n−k1
−(k2−k1)2µ1−1
k2¶2(n−k1)
.
(1)
F om (1) we ha e ha i k1=k1(n) and k2=k2(n) a e such ha (n−k1)/k2
con e ges o a eal limi l6= 0, as n→ ∞, hen a (νn|k1≤νn≤k2) =
O(k2−k1). Hence, as a (νn)≃0.233n, i k2−k1=o(n), he a iabili y
o νnin he educed boo s ap will be less han in he usual boo s ap. I
(n−k1)/k2→ ∞, as n→ ∞, his implies ha k2=o(n). As i is shown in
Jim´enez-Game o e al. [9], in his case he educed boo s ap is no consis en
and hus his choice o k1and k2is no ad isable. A simila si ua ion occu s
when (n−k1)/k2→0, as n→ ∞. Hence, o adequa e choices o k1and k2,
he educed boo s ap a iabili y o νnis less han ha o o dina y boo s ap.
2.2 Second o de accu acy o he dis ibu ion es ima o s
Le X1, X2, ..., Xnbe i.i.d. andom a iables ha ing common dis ibu ion unc-
ion F, mean µand a iance σ2. Le
¯
Xn=1
n
n
X
j=1
Xj, s2
n=1
n
n
X
j=1
(Xj−¯
Xn)2and ¯
X∗
n=1
n
n
X
j=1
X∗
j.
Th oughou his pape P∗will deno e he boo s ap condi ional p obabili y
law, gi en X1, X2, . . . , Xn.
Compa ison o boo s ap p ocedu es 5
I E|X1|3<∞and Fsa is ies C am´e ’s condi ion, Theo em 1.D in Singh [7]
shows ha
sup
xn1/2¯¯¯P∗nn1/2(¯
X∗
n−¯
Xn)/sn≤xo−
−Pnn1/2(¯
Xn−µ)/σ ≤xo¯¯¯=o(1).
(2)
This implies ha he o dina y boo s ap app oxima ion o P{n1/2(¯
Xn−
µ)/σ ≤x}is be e han he no mal app oxima ion, which has an e o o
o de O(n−1/2). Theo em 3.1 in Babu e al. [3] gi es he analogue o he abo e
esul o he Poisson boo s ap, wi h m=E(νn). Co olla y 1 in Jim´enez-
Game o e al. [9] s a es condi ions on k1and k2(1 ≤k1≤k2≤n) o (2)
o hold o he educed boo s ap dis ibu ion es ima o . These condi ions a e
he ollowing:
Condi ion C.1.a Φ(w2)−Φ(w1)≥α,∀n≥n0, o some n0∈Nand some
ixed cons an α > 0 and w1+w2=o(1) o w1→ −∞ and w2→+∞,
Condi ion C.2.aw1,w2→0,
whe e w1= (k1−1−np)n−1/2σ0−1,w2= (k2−np)n−1/2σ0−1,σ02=pq−q2,p=
1−e−1,q= 1 −pand Φ deno es he s anda d no mal cumula i e dis ibu ion
unc ion. Since P(νn≤k) = Φ(w) + o(1) wi h w= (k−np)/√nσ0(Johnson
and Ko z [10, p. 318]), i k1and k2a e such ha some o he abo e condi ions
hold, hen he p opo ion o boo s ap samples no o be conside ed because
hey ha e a small numbe o di e en elemen s (νn< k1) is (almos ) he same
as he p opo ion o boo s ap samples no o be conside ed because hey ha e
a big numbe o di e en elemen s (νn> k2).
The abo e esul s can be ex ended o he mul i a ia e case and o s a is-
ics which can be exp essed as smoo h unc ions o mul i a ia e means. Le
X1, X2, ..., Xnbe ni.i.d. d-dimensional andom ec o s wi h common dis i-
bu ion unc ion F, mean µand a iance ma ix Σ, whe e dis a ixed posi i e
in ege . Le ¯
Xnbe he sample mean and le Σnbe he sample a iance ma ix.
Le Hbe a eal alued Bo el measu able unc ion on Rd. I His di e en iable
a y, we deno e by h(y) he ec o o i s o de pa ial de i a i es o Ha
y. Le τ2=h(µ)0Σh(µ) and τ2
n=h(¯
Xn)0Σnh(¯
Xn), whe e he p ime deno es
anspose.
I EkX1k3<∞,Fsa is ies C am´e ’s condi ion, His h ee imes con inu-
ously di e en iable in a neighbo hood o µ,h(µ)6= 0 and τ > 0, Co olla y 2
in Babu and Singh [8] shows ha
sup
xn1/2¯¯¯P∗hn1/2©H(¯
X∗
n)−H(¯
Xn)ª/τn≤xi−
−Phn1/2©H(¯
Xn)−H(µ)ª/τ ≤xi¯¯¯=o(1).
(3)

6R. Pino Mej´ıas e al.
Theo em 4.1 in Babu e al. [3] and Theo em 4(b) in Jim´enez-Game o e al.
[9] gi e he analogues o he abo e esul o he Poisson boo s ap (wi h
m=E(νn)) and he educed boo s ap (wi h k1and k2sa is ying condi ions
C.1.a and C.2.a), espec i ely.
A class o s a is ics equen ly used as pi o s o app oxima e pi o s is he
s uden ized e sion o he abo e conside ed s a is ics. The esul in (3) is
also ue o his class o s a is ics. Le τ∗2
n=h(¯
X∗
n)0Σ∗
nh(¯
X∗
n), whe e Σ∗
n
is he sample a iance ma ix o he boo s ap sample. Fo a d-dimensional
andom ec o X0= (X(1), X(2), ..., X(d)), le Wbe he d(d+ 3)/2- ec o ob-
ained om Xby adjoining i he p oduc s X(i)X(j), 1 ≤i≤j≤d, ha is,
W0= (X(1), X(2), ..., X(d), X2
(1), X(1)X(2), ..., X(1)X(d), X2
(2), X(2)X(3), ..., X2
(d)).
I EkW1k3<∞,Fsa is ies C am´e ’s condi ion, His h ee imes con inuously
di e en iable in a neighbo hood o µ,h(µ)6= 0 and τ > 0, hen Theo em 4 in
Babu and Singh [8] shows ha
sup
xn−1/2¯¯¯P∗hn1/2©H(¯
X∗
n)−H(¯
Xn)ª/τ∗
n≤xi−
−Phn1/2©H(¯
Xn)−H(µ)ª/τn≤xi¯¯¯=o(1).
(4)
Theo em 4.3 in Babu e al. [3] and Theo em 5(b) in Jim´enez-Game o e al.
[9] gi e he analogues o he esul in (4) o he Poisson boo s ap (wi h
m=E(νn)) and he educed boo s ap (wi h k1and k2sa is ying condi ions
C.1.a and C.2.a), espec i ely.
As we said in he In oduc ion, Rao e al. [2] asse ed ha he a iabili y o
νnis no desi able. An example o his ac eme ges when one conside s s a is-
ics which a e a s uden ized e sion o a smoo h unc ion o sample means, as
he ones in ol ed in (4), since boo s ap samples wi h all hei componen s
equal yield a degene a e alue o he conside ed s a is ics. This undesi able
si ua ion may be a oided by using he sequen ial boo s ap o he educed
boo s ap wi h some k1>1.
3 Simula ions
In Sec ion 2 we ha e seen ha he o dina y boo s ap, he sequen ial boo s ap
wi h m=E(νn) and he educed boo s ap o adequa e choices o k1and k2
yield dis ibu ion es ima o s ha ing all o hem he same asymp o ic accu acy.
To s udy and compa e he ini e sample pe o mance o he co esponding es i-
ma o s we ha e ca ied ou a simula ion expe imen . The conside ed me hods
a e displayed in Table 1, whe e [x] deno es he g ea es in ege less o equal
han x. The Appendices A and B desc ibe he employed algo i hms o gen-
e a e educed boo s ap samples and Poisson boo s ap samples, espec i ely.
Compa ison o boo s ap p ocedu es 7
Table 1. Me hods.
me hod desc ip ion
1 o dina y boo s ap
2 educed boo s ap wi h k1= [np −2√npq] + 1, k2= [np + 2√npq]
3 educed boo s ap wi h k1= [np −√npq] + 1, k2= [np +√npq]
4 educed boo s ap wi h k1=k2= [np]+1
5 sequen ial boo s ap wi h m= [np]+1
To s udy he co esponding dis ibu ion es ima o s o he s a is ic
1(X) = √n¯
Xn−µ
sn
,
we ha e gene a ed M= 1000 samples o size n= 10 om a s anda d no mal
popula ion, N(0,1). Fo each me hod in Table 1 and om each sample Xm,
1≤m≤M, we ha e gene a ed B= 1000 boo s ap samples, X∗m,1, ..., X∗m,B.
We ha e conside ed he ollowing in e als
(−∞,−3),[−3,−2.9),[−2.9,−2.8),[−2.8,−2.7), ..., [2.9,3),[3,∞) (5)
and, o each me hod, we ha e calcula ed (I, m), he ac ion o 1(X∗m,b),
1≤b≤B, alling on in e al I. As a global measu e o he bias o each
dis ibu ion es ima o we ha e conside ed
BS =X
I∈I
bias2(I),
whe e Iis he se o he in e als in (5), bias(I) = 1
MPM
m=1 (I, m)− (I) and
(I) gi es he ac ion o T(Xm), 1 ≤m≤M, alling on he in e al I; and
as a global measu e o he mean squa ed e o o each dis ibu ion es ima o
we ha e conside ed
MS =X
I∈I
mse(I),
whe e mse(I) = 1
MPM
m=1 { (I, m)− (I)}2.
We ha e epea ed he abo e expe imen o n= 20,50,100,200,500,1000
and also o he s a is ics
(X) = √nH(¯
Xn)−H(µ)
|h(¯
Xn)|sn
,
wi h H(x) = exp(x) (s a is ic 2) and H(x) = x2(s a is ic 3). Fo s a is ic 3,
8R. Pino Mej´ıas e al.
Table 2. Resul s o s a is ic 1wi h da a om a N(0,1) popula ion.
sample size
me hod 10 20 50 100 200 500 1000
1BS ×1030.61 0.98 0.63 1.26 1.11 0.66 1.05
MS ×1032.07 2.00 1.61 2.24 2.09 1.64 2.01
2BS ×1030.54 0.96 0.64 1.28 1.10 0.66 1.06
MS ×1032.07 2.00 1.63 2.23 2.07 1.64 2.04
3BS ×1030.53 0.96 0.64 1.28 1.10 0.65 1.03
MS ×1032.07 2.00 1.61 2.25 2.07 1.63 2.01
4BS ×1038.44 3.69 2.58 3.34 2.85 2.30 2.59
MS ×10310.96 4.68 3.56 4.30 3.80 3.26 3.55
5BS ×1030.64 0.98 0.63 1.26 1.12 0.66 1.06
MS ×1031.94 2.00 1.60 2.23 2.10 1.65 2.03
Table 3. Resul s o s a is ic 2wi h da a om a N(0,1) popula ion.
sample size
me hod 10 20 50 100 200 500 1000
1BS ×1031.00 0.92 0.99 0.92 0.99 1.26 0.53
MS ×1032.98 2.02 1.98 1.90 1.98 2.23 1.51
2BS ×1031.17 0.85 0.99 0.92 0.97 1.24 0.54
MS ×1033.29 2.01 1.99 1.90 1.94 2.21 1.51
3BS ×1031.19 0.85 0.99 0.91 0.98 1.27 0.53
MS ×1033.34 2.00 2.00 1.88 1.95 2.23 1.51
4BS ×1039.62 6.59 3.67 3.92 3.36 2.21 2.21
MS ×10312.53 7.61 4.65 4.87 4.31 3.17 3.18
5BS ×1030.66 0.99 0.98 0.94 0.98 1.24 0.53
MS ×1032.50 2.10 1.98 1.91 1.96 2.21 1.49
Table 4. Resul s o s a is ic 3wi h da a om a N(5,1) popula ion.
sample size
me hod 10 20 50 100 200 500 1000
1BS ×1031.02 0.63 1.45 0.69 0.86 0.84 0.92
MS ×1032.52 1.66 2.42 1.65 1.83 1.82 1.89
2BS ×1031.19 0.65 1.42 0.70 0.84 0.82 0.90
MS ×1032.76 1.68 2.40 1.67 1.83 1.79 1.88
3BS ×1031.17 0.65 1.45 0.71 0.86 0.84 0.89
MS ×1032.73 1.69 2.41 1.68 1.84 1.82 1.86
4BS ×1036.39 3.40 3.70 2.30 2.79 2.18 2.15
MS ×1038.93 4.38 4.67 3.27 3.75 3.14 3.11
5BS ×1030.96 0.62 1.45 0.69 0.83 0.82 0.89
MS ×1032.27 1.65 2.42 1.66 1.79 1.80 1.87
o a oid h(µ) = 0, he da a comes om a N(5, 1) popula ion. The ob ained
esul s a e displayed in Tables 2, 3 and 4. Tables 5, 6 and 7 p esen he esul s
o a simila expe imen wi h da a om a mix u e o wo no mal popula ions,
0.2N(0,1) + 0.8N(5,22).
All compu a ions in his pape ha e been pe o med using p og ams w i en
in he R language (R De elopmen Co e Team [11]).
Compa ison o boo s ap p ocedu es 9
Table 5. Resul s o s a is ic 1wi h da a om a 0.2N(0,1) + 0.8N(5,22) popula-
ion. sample size
me hod 10 20 50 100 200 500 1000
1BS ×1031.05 0.83 0.99 1.18 0.65 1.06 1.24
MS ×1032.51 1.83 1.96 2.16 1.62 2.02 2.21
2BS ×1030.91 0.86 0.92 1.17 0.66 1.02 1.22
MS ×1032.46 1.87 1.90 2.14 1.64 1.98 2.19
3BS ×1030.93 0.86 0.93 1.16 0.67 1.03 1.24
MS ×1032.47 1.87 1.92 2.12 1.63 2.01 2.21
4BS ×1038.95 3.22 3.80 3.47 2.05 3.12 3.10
MS ×10311.71 4.21 4.78 4.43 3.02 4.09 4.05
5BS ×1031.06 0.82 0.98 1.20 0.64 1.02 1.25
MS ×1032.34 1.83 1.94 2.18 1.61 2.00 2.22
Table 6. Resul s o s a is ic 2wi h da a om a 0.2N(0,1) + 0.8N(5,22) popula-
ion. sample size
me hod 10 20 50 100 200 500 1000
1BS ×1030.67 0.92 0.72 0.99 1.00 1.11 0.74
MS ×1032.75 2.17 1.73 1.97 1.98 2.07 1.71
2BS ×1030.75 1.02 0.80 1.08 1.00 1.09 0.72
MS ×1033.04 2.31 1.82 2.06 1.95 2.05 1.69
3BS ×1030.78 0.98 0.82 1.07 1.00 1.10 0.73
MS ×1033.00 2.28 1.83 2.04 1.97 2.06 1.71
4BS ×10316.18 6.77 3.54 3.15 3.44 3.38 2.24
MS ×10319.51 7.89 4.54 4.11 4.39 4.36 3.21
5BS ×1030.95 0.90 0.72 0.98 1.02 1.09 0.73
MS ×1032.88 2.14 1.74 1.97 1.98 2.06 1.71
Table 7. Resul s o s a is ic 3wi h da a om a 0.2N(0,1) + 0.8N(5,22) popula-
ion. sample size
me hod 10 20 50 100 200 500 1000
1BS ×1031.03 0.60 0.96 0.79 1.08 1.37 0.80
MS ×1032.87 1.71 1.96 1.76 2.03 2.35 1.75
2BS ×1031.07 0.61 0.98 0.79 1.07 1.34 0.81
MS ×1033.03 1.74 1.97 1.76 2.04 2.32 1.77
3BS ×1031.07 0.62 0.97 0.78 1.07 1.33 0.81
MS ×1033.03 1.73 1.96 1.74 2.05 2.30 1.77
4BS ×10311.66 4.19 3.51 3.34 3.05 4.01 3.07
MS ×10314.65 5.19 4.48 4.30 4.01 4.97 4.03
5BS ×1031.44 0.55 0.97 0.81 1.05 1.36 0.81
MS ×1033.11 1.65 1.97 1.79 2.01 2.34 1.78
4 Conclusions
Looking a Tables 2–7 we see ha me hod 4 has he bigges bias o all he
conside ed cases. Fo he es o he me hods in Table 1, we obse e ha he e
is no me hod beha ing much be e han he o he s o all s a is ics, all sample
sizes and all dis ibu ions. As expec ed, he di e ences in BS and MS dec ease
as he sample size inc eases. Al hough he pe o mance o me hods 1, 2, 3, 5