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Goldbach's conjecture proven By Wadï Mami

Mami, Wadï

Abstract

Goldbach's conjecture is one of the oldest and best-known unsolved problems in number theory and all of mathematics. It states that every even natural number greater than 2 is the sum of two prime numbers. ---------------------------------------------------------------------------------------------- A prime number must be an odd number The sum of 2 odd numbers is an even number Then The sum of two prime numbers is an even number (A). Erdös Theorem : For every integer n > 1, it exists always a prime number between n and 2n (Source : Le Beau livre des Maths De Pythagore à la 57 dimension DUNOD edition, author Clifford A.Pickover) By récurrence of Erdös Theorem mentioned above and (A) There is always k even number which is the sum of two prime numbers p and q. (B) p for k k <= p < =2k (i) q for k/2 k / 2<= q <= k (j) (i) + (j) k + k /2 <= p+q <= 3k ie 3k/2 <= p+q <= 3k wich implies as the sum p+q is a number then p+q = 3k is even as k is even then by correlation We can state then every even natural number greater than 2 is the sum of 2 prime numbers (what needed to be demonstrated) Goldbach’s conjecture proven.

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Goldbach’s conjecture proven By Wadï Mami Email : [email protected]om.tn / [email protected] Date : 30/10/2025 Goldbach's conjecture is one of the oldest and bestknown unsolved problems in number theory and all of mathematics. It states that every even natural number greater than 2 is the sum of two prime numbers. ---------------------------------------------------------------------------------------------- A prime number must be an odd number The sum of 2 odd numbers is an even number Then The sum of two prime numbers is an even number (A). Erdös Theorem : For every integer n > 1, it exists always a prime number between n and 2n (Source : Le Beau livre des Maths De Pythagore à la 57 dimension DUNOD edition, author Clifford A.Pickover) By récurrence of Erdös Theorem mentioned above and (A) There is always k even number which is the sum of two prime numbers p and q. (B) p for k k <= p < =2k (i) q for k/2 k / 2<= q <= k (j) (i) + (j) k + k /2 <= p+q <= 3k ie 3k/2 <= p+q <= 3k wich implies as the sum p+q is a number then p+q = 3k as k is even then by correlation We can state then every even natural number greater than 2 is the sum of 2 prime numbers (what needed to be demonstrated) Goldbach’s conjecture proven.