On the structure of the centralizer of a braid
Abstract
The mixed braid groups are the subgroups of Artin braid groups whose elements preserve a given partition of the base points. We prove that the centralizer of any braid can be expressed in terms of semidirect and direct products of mixed braid groups. Then we construct a generating set of the centralizer of any braid on n strands, which has at most k(k+1) 2 elements if n = 2k, and at most k(k+3) 2 elements if n = 2k + 1. These bounds are shown to be sharp, due to work of N.V.Ivanov and of S.J.Lee. Finally, we describe how one can explicitly compute this generating set.
Full text
a Xi :ma h/0305156 2 [ma h.GT] 12 Sep 2003
On he s uc u e o he cen alize o a b aid
Juan Gonz´
alez-Meneses1and Be Wies
Dp o. de Ma em´a ica Aplicada I, E.T.S. A qui ec u a, Uni e sidad de Se illa,
A da. Reina Me cedes, 2. 41012 Se illa, Spain; [email p o ec ed]
and
IRMAR (UMR 6625 du CNRS), Uni e si ´e de Rennes 1, Campus de Beaulieu,
35042 Rennes cedex, F ance; [email p o ec ed]ni - ennes1.
Abs ac The mixed b aid g oups a e he subg oups o A in b aid g oups
whose elemen s p ese e a gi en pa i ion o he base poin s. We p o e
ha he cen alize o any b aid can be exp essed in e ms o semidi ec
and di ec p oduc s o mixed b aid g oups. Then we cons uc a gene a ing
se o he cen alize o any b aid on ns ands, which has a mos k(k+1)
2
elemen s i n= 2k, and a mos k(k+3)
2elemen s i n= 2k+ 1. These
bounds a e shown o be sha p, due o wo k o N.V.I ano and o S.J.Lee.
Finally, we desc ibe how one can explici ly compu e his gene a ing se .
AMS Classi ica ion 20F36; 20E07, 20F65.
Keywo ds b aid, cen alize , Nielsen-Thu s on heo y.
1 In oduc ion and s a emen o he esul s
In 1971, Makanin [25] ga e an algo i hm o compu ing a gene a ing se o he
cen alize Z(β) o any gi en elemen βo he n-s ing b aid g oup Bn. His
me hod, howe e , ends o yield e y la ge, and highly edundan gene a ing
se s. One hin ha much smalle gene a ing se s could be ound came om
he expe imen al esul s o Gonz´alez-Meneses and F anco, which we e ob ained
wi h a adically imp o ed e sion o Makanin’s algo i hm, based on new heo-
e ical wo k [16]. Also, i has p obably been clea o specialis s o a long ime
ha Nielsen-Thu s on heo y could be used o imp o e upon Makanin’s esul s.
Howe e , he e seems o be no such esul in he li e a u e, and he aim o he
p esen pape is o ill his gap.
Al hough ou main in e es was o compu e, o any gi en β∈Bn, a small
gene a ing se o Z(β), we succeed in desc ibing his cen alize in e ms o
semidi ec and di ec p oduc s o mixed b aid g oups (see [26, 27]). These
1Pa ially suppo ed by MCYT, BFM2001-3207 and FEDER.
1
g oups a e de ined as ollows: le X={P1,...,Pn}be he base poin s o he
b aids in Bn. Gi en a pa i ion Po X, he mixed b aid g oup BPconsis s
o hose b aids whose associa ed pe mu a ion p ese es each cose o P.
The well known classi ica ion o mapping classes o a punc u ed su ace in o
pe iodic, educible and pseudo-Anoso ones, yields an analogous classi ica ion
o b aids. I βis educible, hen one can decompose i , in a ce ain sense, in o
a ubula b aid b
β, and some in e io b aids β[1],...,β[ ], all o hem ha ing less
han ns ands. The main esul o his pape is he ollowing:
Theo em 1.1 Le β∈Bn. One has:
(1) I βis pseudo-Anoso , hen Z(β)≃Z2.
(2) I βis pe iodic, hen Z(β)is ei he Bno isomo phic o a b aid g oup
on an annulus.
(3) I βis educible, hen he e exis s a spli exac sequence:
1−→ Z(β[1])× · · · × Z(β[ ])−→ Z(β)−→ Z0(b
β)−→ 1,
whe e Z0(b
β)is a subg oup o Z(b
β), isomo phic ei he o Z2o o a mixed
b aid g oup.
No ice ha Z≃B2=B{{1,2}} , also Bn=B{{1,...,n}}, and inally he b aid
g oup o e an annulus on ks ands is isomo phic o B{{1,...,k},{k+1}} ⊂Bk+1.
Hence all hese g oups can be seen as mixed b aid g oups. Then, by ecu ence
on he numbe o s ands we deduce he ollowing:
Co olla y 1.2 Fo e e y β∈Bn, he cen alize Z(β)can be exp essed in
e ms o semidi ec and di ec p oduc s o mixed b aid g oups.
Using he abo e s uc u e we shall cons uc , o any b aid β∈Bn, a gene a ing
se o Z(β) ha ing e y ew elemen s. Mo e p ecisely, we ob ain:
Theo em 1.3 I β∈Bn, hen he cen alize Z(β)can be gene a ed by a
mos k(k+1)
2elemen s i n= 2k, and a mos k(k+3)
2elemen s i n= 2k+ 1.
We will p esen an example, communica ed o us by S. J. Lee, showing ha he
abo e bound is sha p. Tha is, we will de ine, o e e y posi i e in ege n, a
b aid in Bnwhose cen alize canno be gene a ed by less han k(k+1)
2elemen s
i n= 2k, o less han k(k+3)
2elemen s i n= 2k+ 1. (The i s o obse e
2
ha he numbe o gene a o s o he cen alize may g ow quad a ically wi h
he numbe o s ands was N.V.I ano [21].)
Howe e , he abo e bound e e s o he wo s case, and one could be in e es ed
in he minimal numbe o gene a o s o a pa icula b aid. We shall gi e a
gene a ing se which is in some sense he smalles “na u al” gene a ing se o
he cen alize o a b aid. Howe e , we shall also gi e an example ha illus a es
he di icul y o inding he absolu ely minimum possible numbe o gene a o s.
Le us men ion ha , o he special case o educible b aids conjuga ed o a
gene a o σi, i s cen alize has al eady been desc ibed in [14].
The plan o he pape is as ollows: in sec ion 2 we se up no a ion and some
s anda d machine y, and gi e he men ioned example by S. J. Lee. In sec ion 3
we s udy Z(β) in he case whe e βis pe iodic, sec ion 4 deals wi h he pseudo-
Anoso case, and sec ion 5 he educible one, which is he mos in ol ed. In
sec ion 6 we de ine a gene a ing se which is no la ge han he s a ed uppe
bound. In sec ion 7 we desc ibe a gene a ing se which is as small as possible
while s ill e lec ing he geome ic s uc u e o he Nielsen-Thu s on decompo-
si ion. We also gi e an example o show ha by algeb aic icke y, e en smalle
se s can be ob ained. Finally in sec ion 8 we discuss how he gene a ing se
ha we de ined can be ound algo i hmically.
2 P e equisi es om Nielsen-Thu s on heo y
We deno e by D he closed disk o adius 2 cen e ed a 0 in he complex plane.
Fo any n∈N, he disk D, oge he wi h any choice o ndis inc poin s in i s
in e io , is deno ed Dn, and he dis inguished poin s a e called he punc u es.
We shall use di e en choices o he exac posi ion o he punc u es a di e en
imes - hey may be lined up on he eal axis, o egula ly dis ibu ed on a ci cle
o adius 1, o again one o hem may be in he cen e while he emaining n−1
a e dis ibu ed o e he ci cle o adius 1. In mos ins ances, he posi ion o
he punc u es is i ele an , and we shall lea e i unspeci ied.
We ecall ha he b aid g oup Bnis he g oup o iso opy classes o home-
omo phisms ixing (poin wise) he bounda y and pe mu ing he punc u es o
Dn. He e he iso opies mus ix poin wise he bounda y and he punc u es.
Al e na i ely, Bncould be de ined as he g oup o iso opy classes o disjoin
mo emen s o he punc u es, s a ing and ending wi h he con igu a ion o Dn.
Ye ano he de ini ion o Bnis as he se o iso opy classes o b aids wi h n
s ings in he cylinde D×[0,1], whe e he s a and end poin s o he s ings
3
a e exac ly he punc u e poin s in Dn× {0}and Dn× {1}. We shall use all
h ee poin s o iew.
We shall o en wo k wi h a ce ain quo ien o he g oup Bn, a he han wi h
Bni sel . We ecall ha he cen e o Bnis isomo phic o he in ege s, and
gene a ed by he ull wis ∆2(whe e ∆ is Ga side’s hal wis ). Geome ically,
he g oup p ojec ion Bn→Bn/h∆2iis gi en by smashing he bounda y cu e
o Dn o a punc u e, so ha Bn/h∆2iis na u ally a subg oup o he mapping
class g oup o he sphe e wi h n+ 1 punc u es. In o de o keep no a ion
manageable, we shall use he same le e s o elemen s o he b aid g oup Bn
and o hei image in he quo ien Bn/h∆2i. This abuse o no a ion should
no cause con usion.
We say ha an elemen β∈Bnis pe iodic i he elemen o Bn/h∆2i ep e-
sen ed by βis o ini e o de . Equi alen ly, βis pe iodic i he e exis s a k∈N
such ha in Bnwe ha e ha βkis equal o some powe o ∆2.
We say an elemen βo Bnis educible i he e exis s a nonemp y mul icu e
Cin Dn(i.e. a sys em o disjoin simple closed cu es in Dn, none o hem
iso opic o he bounda y o enclosing a single punc u e) which is s abilized by
β, i.e. such ha β(C) is iso opic o C. No e ha βmay pe mu e di e en
componen s o he mul icu e C.
The ollowing de ini ion is aken om [8] (see also [20]). To e e y educible
b aid β∈Bnone can associa e a canonical in a ian mul icu e: i s canonical
educ ion sys em, which by de ini ion is he collec ion o all iso opy classes c
o simple closed cu es which ha e he ollowing wo p ope ies: i s ly, cmus
be s abilized by some powe o β, and secondly any simple closed cu e which
has non-ze o geome ic in e sec ion numbe wi h cmus no be s abilized by
any powe o β. Fo ins ance, le us conside he punc u ed disk D6, whe e he
6 punc u es a e a anged uni o mly on he ci cle o adius 1 a ound 0. Then
he o a ion o he punc u es a ound he ci cle by an angle o 2π
3is a pe iodic
elemen o B6(o pe iod 3), i is also educible (e.g. he h ee simple closed
cu es enci cling punc u es 1 and 2, 3 and 4, and 5 and 6 espec i ely o m
an in a ian mul icu e), bu i s canonical educ ion sys em is emp y. This
example, howe e , is somewha un ypical: i a non-pe iodic b aid is educible,
hen i s canonical educ ion sys em is nonemp y (see [20]).
I Cis an in a ian mul icu e o a educible b aid β, hen we de ine he ubula
b aid induced by βand C o be he b aid on ewe s ings ob ained om β
by emo ing om Dnall he disks bounded by ou e mos cu es o C, and
collapsing each ou e mos cu e o C o a punc u e poin . I should be s essed
ha his b aid is only de ined up o conjugacy.
4
An al e na i e way o look a he same de in ion is he ollowing: le us conside
again βas an iso opy class o ndisjoin s ings in D×[0,1] wi h ex emal
poin s a he punc u e poin s o Dn× {0}and Dn× {1}, such ha each disk
D× { }in e sec s each s ing exac ly once. Now ou pic u e can be comple ed
by embedded cylinde s in D×[0,1] which a e disjoin om each o he and om
he s ings o he b aid, each o which in e sec s each disk D× { }in exac ly
one ci cle, and whose bounda y componen s a e exac ly he ou e mos cu es
o Cin D×{0}and D×{1}. We can in e p e he solid cylinde s bounded by
hese cylinde s as “ a s ings”, and he esul ing b aid wi h some a s ings is
exac ly he ubula b aid de ined abo e.
The in e io b aids induced by βand Ca e he b aids on ewe s ings in-
duced by βa he in e io o he discs bounded by he ou e mos cu es o C.
They can be hough o as he b aids ‘inside’ he ubes o he ubula b aid.
The e o e, o e e y educible b aid β, and e e y in a ian mul icu e C, we
can decompose βin o one ubula b aid and some in e io b aids – as many as
he numbe o ou e mos cu es in C.
Finally, we ha e he no ion o a pseudo-Anoso elemen o Bn, o which we e e
o [13] o [20]. Roughly speaking, β∈Bnis pseudo-Anoso i i is ep esen ed
by a homeomo phism o Dnwhich p ese es wo ans e se measu ed olia ions
on Dn(called he “s able” and he “uns able” olia ion), while scaling he
measu e o he uns able one by some ac o λwhich is g ea e han 1, and he
measu e o he s able one by 1
λ.
Thu s on’s heo em [32, 13] s a es ha e e y i educible elemen o Bnis ei he
pe iodic o pseudo-Anoso .
We end his sec ion wi h he p omised example, due o S. J. Lee, ha should
be help ul o unde s anding he ela ionship be ween he Nielsen-Thu s on
decomposi ion and he cen alize subg oup o a b aid β∈Bn. This example
was also ound independen ly by N. V. I ano and H. Hamidi-Teh ani [22].
Example 2.1 Suppose ha n= 2m, and deno e by σi he s anda d gene a o
o Bn, in which he i h and he (i+ 1)s punc u es pe mu e hei posi ions in
a clockwise sense. We de ine β=σ1σ2
3σ3
5···σm
2m−1.
The canonical educ ion sys em o βconsis s o mci cles, he i h one enclosing
he punc u es 2i−1 and 2i. The co esponding ubula b aid is he i ial b aid
o Bm, and he in e io b aids a e, espec i ely, σ1,σ2
1, . . . , σm
1(no ice ha
all o hem a e non-conjuga e, since conjuga e b aids ha e he same exponen
sum).
5
Le D(1),...,D(m)be he disks bounded by he abo e ci cles. As we shall see,
any b aid ha commu es wi h βhas o send each disk D(i) o i sel (since he
in e io b aids a e non-conjuga e). A gene a ing se o he cen alize subg oup
o βis gi en by
(i) o each i∈ {1,...,m}, he b aid σ2i−1, whose suppo is con ained in
D(i),
(ii) any gene a ing se o he pu e b aid g oup on ms ings Pm– all he
gene a o s he e ac as he iden i y on D(1) ∪...∪D(m), and can be seen
as a pu e ubula b aid on ms ings ( ubes), whe e he i h ube s a s
and ends a D(i).
I can be easily shown ha , in his case, Z(β)≃Zm×Pm. The essen ial
obse a ion now is he ollowing: i can be deduced by he p esen a ion gi en
in [6], ha he abelianiza ion o Pmis isomo phic o Zm(m−1)/2(see also [1]).
Hence, he abelianiza ion o Z(β) is isomo phic o Zm×Zm(m−1)/2. The e o e,
a leas m+m(m−1)
2=m(m+1)
2gene a o s a e needed o he cen alize o he
b aid β.
The case when n= 2m+ 1 is analogous. The b aid p oposed by S. J. Lee is:
β=σ2σ2
4σ3
6···σm
2m. This ime he i s s and is no enclosed by any cu e o
he canonical educ ion sys em o β, and one has: Z(β)≃Zm×Pm+1 . Hence,
in his case he minimal possible numbe o gene a o s is m+m(m+1)
2=m(m+3)
2.
By p o ing heo em 1.3, we will show ha he abo e examples a e he wo s
one can ind.
3 The pe iodic case
We ha e o s a by desc ibing he pe iodic elemen s o Bn. In o de o s a e
his classi ica ion esul , which is classical, we need o de ine wo b aids.
I Dnis he disk wi h npunc u es a anged egula ly on he ci cle o adius 1,
hen he b aid which we shall call δ(n)is ep esen ed by a clockwise mo emen
o all punc u es on his ci cle by an angle 2π
n. I no con usion is possible, we
shall simply w i e δ, wi hou indica ing he numbe o s ands (no e ha his
b aid is he Ga side elemen o he Bi man-Ko-Lee s uc u e o Bn[7]).
Simila ly, i we hink o Dnas ha ing one punc u e in he cen e, and n−1
punc u es a anged ci cula ly a ound i , hen we de ine γ(n)∈Bn o be he
b aid gi en by a ci cula mo emen o he n−1 punc u es by an angle o 2π
n−1,
6
while lea ing he cen al punc u e ixed. Again, o simplici y we shall o en
only w i e γins ead o γ(n).
The esul ha classi ies pe iodic b aids, which is due o Eilenbe g [11] and
de Ke ´ekj´a ´o [23] (see [10] o a mode n exposi ion) is:
Lemma 3.1 E e y pe iodic b aid in Bnis conjuga e o a powe o δ(n)o
γ(n).
Thus we only need o conside he cen alize subg oups o δk
(n)and γk
(n) o
all n, k ∈Z, since he cen alize s o conjuga e elemen s a e isomo phic by an
inne au omo phism o Bn. This p oblem has been sol ed by Bessis, Digne and
Michel [4], on he wide con ex o complex e lexion g oups. We shall explain
hei esul in he pa icula case o b aid g oups:
We suppose i s ha β=δk
(n)whe e, wi hou loss o gene ali y, k⩾0. Le
d= gcd(n, k). Fo u= 1,...,n, we will deno e Pu=ei2πu/n he punc u es o
Dn, so β=δk
(n)sends Pu o Pu+k o e e y u( he indices a e aken modulo
n). Hence he pe mu a ion induced by βhas do bi s (cycles) o leng h =n
d,
ha we deno e by C1,...,Cd. See in igu e 1 an example whe e n= 12, k= 9,
d= 3 and = 4: he b aid δ(12) and he h ee o bi s o δ9
(12) .
Figu e 1: The b aid δ∈B12 , and he h ee o bi s o δ9(in black, whi e and g ey).
I > 1 ( ha is i d < n), conside he once punc u ed disc D∗=D {0},
and he −shee ed co e ing θ=θ :D∗→D∗de ined by θ(aei ) = aei =
aei n/d . The o bi s C1,...,Cda e sen by θ o he poin s Q1,...,Qd, whe e
Qu=ei2πu/d . I we conside he hal -line L={aeiπ/d, a ∈]0,2]}(no ice ha
Lpasses be ween Qdand Q1), hen D∗ Lis a undamen al egion o θ(see
igu e 2).
7
Figu e 2: The co e ing map θ=θ4associa ed o δ9
(12) .
Now no ice ha e e y b aid in Bd(D∗) can be li ed, by θ−1, o a b aid in
Bnin a na u al way. The esul ing b aid is a 2πd
n-symme ic b aid, ha is, i
is in a ian unde a o a ion by an angle o 2πd
n. Bu hen i is also in a ian
unde a o a ion o angle 2πk
n; in o he wo ds, he esul ing b aid commu es
wi h β. Hence we ha e a na u al homomo phism: θ∗:Bd(D∗)→Bnwhose
image is con ained in Z(β). Then one has
Theo em 3.2 ([4]) The na u al homomo phism θ∗:Bd(D∗)→Z(δk
(n))is an
isomo phism.
In o he wo ds, e e y elemen in he cen alize o β=δk
(n)can be seen ( ia θ)
as a b aid on a once punc u ed disc, ha is, a b aid on an annulus. No ice ha
i = 1 ( ha is, i kis a mul iple o n), hen βis a powe o δn
(n)= ∆2
(n). In
his case θis he iden i y map, and he undamen al egion is he whole Dn.
Hence he cen alize o βis he whole Bn, as one should expec .
Since we a e in e es ed in minimising he se o gene a o s, we obse e ha i
d=n( hus = 1), hen Z(β) = Bnis gene a ed by wo elemen s, namely
A in’s σ1and Bi man-Ko-Lee’s δ. In a simila way, i 1 < d < n, hen he
b aid g oup Bd(D∗) is gene a ed by jus wo elemen s, namely δ(n)=θ∗(δ(d))
and he b aid θ∗(σ1) shown in igu e 3(a). No ice ha his case con ains he
abo e one, whe e θ∗is he iden i y. Finally, i d= 1 hen B1(D∗) is cyclic.
Thus we ha e:
P oposi ion 3.3 I kand na e cop ime, hen Z(δk
(n))is gene a ed by a single
elemen , namely δ(n). I , by con as , gcd(k, n)⩾2, hen Z(δk
(n))is gene a ed
by wo elemen s: δ(n)and he b aid θ∗(σ1).
8
Figu e 3: Gene a o s θ∗
3(σ1) and ¯
θ∗
3(σ1) o he cen alise s o δ4
(12) and γ4
(13) .
I is clea ha he gene a ing se gi en by p oposi ion 3.3 is indeed minimal.
Nex we s udy he cen alize o β=γk
(n), s ill ollowing he wo k in [4]. This
ime we call d= gcd(n−1, k), and = (n−1)/d. I d < n −1, he abo e map
θinduces a na u al homomo phism ¯
θ∗=¯
θ∗
:Bd(D∗)→Bn, whe e his ime
he cen al poin o Dis conside ed as a punc u e. Hence, he cen al s and o
e e y b aid coming om Bd(D∗) is i ial. We obse e ha he image o his
homomo phism is con ained in Z(β), and in ac one has:
Theo em 3.4 ([4]) The na u al homomo phism ¯
θ∗
:Bd(D∗)→Z(γk
(n))is an
isomo phism.
By con as , i d=n−1, hen βis a powe o γn−1= ∆2, so θ∗
= 1, Z(β) = Bn
and e e y hing wo ks as abo e. Hence we ha e
P oposi ion 3.5 I kand n−1a e cop ime, hen Z(γk
(n))is gene a ed by a
single elemen , namely γ(n). I , by con as , gcd(k, n−1) = d⩾2, hen Z(γk
(n))
is gene a ed by wo elemen s: γ(n)=¯
θ∗(δ(d))and he b aid ¯
θ∗(σ1).
See igu e 3(b) o an illus a ion o he b aid ¯
θ∗(σ1). We summa ize all he
esul s in his sec ion as ollows:
Co olla y 3.6 The cen alize o any pe iodic b aid in Bnei he equals Bn
o is isomo phic o Bd(D∗), o some d < n. In pa icula , i can be gene a ed
by a mos wo elemen s.
We end wi h a esul ha will be help ul la e :
Co olla y 3.7 I kis no a mul iple o n, hen Z(δk
(n))∼
=Z(γk
(n+1)).
9
Figu e 7: How o mo e β[i] om Ci,4 o Ci,2, when i= 4.
5.2 Cen alize o a b aid in egula o m
We will now s udy he cen alize o β, assuming ha βis in egula o m.
Recall ha he only non- i ial in e io b aids o βa e deno ed β[1],...,β[ ],
and ha b
βis he ubula b aid associa ed o βand R(β). In his sec ion we
will show ha he e is an exac sequence:
1→Z(β[1])× · · · × Z(β[ ])g
−→ Z(β)p
−→ Z0(b
β)→1,
whe e Z0(b
β) is a subg oup o Z(b
β). La e on we will see ha his sequence
spli s.
Fo i∈ {1,..., }, conside he cen alize Z(β[i]) in Bmi. We de ine a map
gi:Z(β[i])→BR(β)as ollows: gi en γ∈Z(β[i]), gi(γ) is he b aid α∈BR(β)
sa is ying bα= 1, αj,k = 1 o j6=i, and αi,k =γ o k= 1,..., i. We need
o show he ollowing:
P oposi ion 5.2 The map gide ined abo e is an injec i e homomo phism,
and i s image is con ained in Z(β).
P oo The map giis gi en by he diagonal homomo phism Z(β[i])→Z(β[i])×
...×Z(β[i]) ( i ac o s), ollowed by he homomo phism induced by an inclu-
sion o icopies o an mi- imes punc u ed disk in o idisjoin subdisks (each
con aining mipunc u es) o Dn. By he esul s o [28] we can deduce ha gi
is indeed an injec i e homomo phism.
I emains o show ha o e e y γ∈Z(β[i]) one has α=gi(γ)∈Z(β).
Since bαis i ial,
α−1βα =bα−1b
βbα=b
β. So we jus need o show ha he
in e io b aids o α−1βα and βcoincide. Fo j6=i, he b aids αj,k a e i ial
o e e y k, so α−1βαj,k =βj,k . Now, o k6= i, one has α−1βαi,k =
16
α−1
i,k βi,k αi,k+1 =γ−11γ= 1 = βi,k . Finally, since γcommu es wi h β[i],
one has α−1βαi, i=α−1
i, iβi, iαi,1=γ−1β[i]γ=β[i]=βi, i. The e o e
α−1βα =β, so he image o giis con ained in Z(β).
P oposi ion 5.3 The map g:Z(β[1])× · · · × Z(β[ ])−→ Z(β)de ined by
g(γ1,...,γ ) = g1(γ1)···g (γ )is an injec i e homomo phism.
P oo Gi en γ∈Z(β[i]), he only non i ial s ands in gi(γ) a e hose inside
he ubes Ci,1,...,Ci, i. Hence i i6=j,γ∈Z(β[i]) and δ∈Z(β[j]), hen
gi(γ) and gj(δ) commu e. Since e e y giis a homomo phism, his shows ha
gis also a homomo phism. Bu we know by he p e ious p oposi ion ha giis
injec i e o i= 1,..., . Using an a gumen simila o he p oo o p oposi ion
5.2, one can deduce ha gis also injec i e.
Now we will ela e Z(β) and Z(b
β). E e y b aid in Z(β) p ese es he canonical
educ ion sys em o β(see [20]), so i mus p ese e R(β). Tha is, Z(β)⊂
BR(β). Le p:BR(β)→Bmbe he homomo phism which sends α o bα, he
ubula b aid induced by αand R(β). I we ake α∈Z(β) hen β=α−1βα,
so p(β) = p(α−1βα) = p(α)−1p(β)p(α). Hence p(α) commu es wi h p(β) = b
β.
The e o e, i we es ic p o Z(β) we ge p:Z(β)→Z(b
β).
Un o una ely, nei he p:BR(β)→Bmno i s es ic ion p:Z(β)→Z(b
β) a e
su jec i e, bu we shall see ha he elemen s in he image o pin ei he case can
be easily cha ac e ised by he pe mu a ion hey induce. No ice ha pinduces
a bijec ion ep om R(β) o {P1,...,Pm}, he punc u es o Dm. We deno e by
τ he in e se o ep.
De ini ion 5.4 Le η∈Bm, and le πηbe he pe mu a ion induced by η
on he punc u es o Dm. We say ha πηis consis en wi h R(β)i , o i=
1,...,m,τ(Pi)and τ(πη(Pi)) enclose he same numbe o punc u es.
P oposi ion 5.5 An elemen η∈Bmis in he image o p:BR(β)→Bmi
and only i πηis consis en wi h R(β).
P oo I ηis in he image o p, le α∈BR(β)wi h p(α) = η. Then, o e e y
i= 1,...,m,τ(Pi) and τ(πη(Pi)) a e he op and bo om ci cles o a ube
de e mined by α. Hence hey mus enclose he same numbe o punc u es ( he
numbe o s ands inside he ube).
Con e sely, suppose ha πηis consis en wi h R(β). Take i∈ {1,...,m}and
suppose ha τ(Pi) = Cj,k . Then ake he i h s and o ηand conside i as a
17
ube, enclosing he i ial b aid on mjs ands. Do his o e e y i= 1,...,m.
The esul ing b aid, ψ(η), is well de ined since πηis consis en wi h R(β), and
i belongs o BR(β). Mo eo e , p(ψ(η)) = ηby cons uc ion.
The homomo phism ψin oduced in his p oo will play a p ominen ˆole in
wha ollows: i η∈Bm, hen ψ(η) is he b aid in BR(β)whose ubula b aid
equals η, and whose in e io b aids a e all i ial.
All he elemen s in Bm ha shall be conside ed om now on will ha e pe -
mu a ions consis en wi h R(β). Hence, by abuse o no a ion, we will iden i y
Ci,k =ep(Ci,k) and Ci=ep(Ci) i i does no lead o con usion.
We s ill need o cha ac e ise he elemen s in he image o p:Z(β)→Z(b
β). We
jus know ha hei pe mu a ions mus be consis en wi h R(β), bu his is no
su icien . Recall ha he pe mu a ion induced by βon he componen s o R(β)
has o bi s, C1,...C . The key obse a ion now is ha e e y elemen α∈Z(β)
p ese es hese o bi s se wise, hough i could pe mu e hem. The e o e, o
i= 1,..., , one has α(Ci) = Cj o some j. In he same way, o any η∈Z(b
β)
one has α(Ci) = Cj o some j.
Lemma 5.6 Le α∈Z(β). I α(Ci) = Cj o some i, j ∈ {1,..., }, hen
β[i]=β[j].
P oo Since α(Ci) = Cj, he wo o bi s ha e he same leng h, which we shall
deno e ; hus = i= j. Now β is a b aid ha p ese es Ci,k and Cj,k
o e e y k, and is such ha (β )i,k =β[i]and (β )j,k =β[j]. Now since α
commu es wi h β, hen i also commu es wi h β . Suppose ha αsends Ci,1 o
Cj,k . Then β[j]= (β )j,k = (α−1β α)j,k = (αi,1)−1(β )i,1αi,1= (αi,1)−1β[i]αi,1.
The e o e β[i]and β[j]a e conjuga e, and since βis in egula o m, β[i]=β[j],
as we wan ed o p o e.
Lemma 5.6 imposes ano he condi ion o a b aid in Z(b
β) o be in p(Z(β)):
De ini ion 5.7 Le η∈Z(b
β). We say ha πηis consis en wi h βi i is
consis en wi h R(β)and, u he mo e, o e e y i, j ∈ {1,..., }such ha
η(Ci) = Cj, one has β[i]=β[j].
De ini ion 5.8 Z0(b
β)is he subg oup o Z(b
β)consis ing o hose elemen s
whose pe mu a ion is consis en wi h β.
18
Then lemma 5.6 can be es a ed as ollows: I α∈Z(β) hen p(α)∈Z0(b
β).
Mo eo e , we can p o e he ollowing:
P oposi ion 5.9 The homomo phism p:Z(β)−→ Z0(b
β)is su jec i e.
P oo Le η∈Z0(b
β). We shall cons uc a p eimage o ηunde pin wo
s eps. Since πηis consis en wi h β( hus wi h R(β)), we can, as a i s s ep,
conside he b aid ψ(η)∈Bn. We hen ha e p(ψ(η)) = η; bu ψ(η) does no
necessa ily commu e wi h β, since he in e io b aids o ψ(η)−1βψ(η) could
di e om hose o β. Ac ually, since he in e io b aids o ψ(η) a e all i ial,
conjuga ing βby ψ(η) jus pe mu es he in e io b aids o β. Mo e p ecisely,
he b aid ψ(η)−1βψ(η) equals β, excep ha , o each i∈ {1,..., }, i may
no be he ube Ci, iwhich con ains he non i ial in e io b aid β[i], bu some
o he ube om he amily Ci. Ou aim in he second s ep is hus o ill he
ubes o ψ(η) wi h mo e sui able in e io b aids, in o de o ob ain a b aid ha
commu es wi h β.
Fo e e y i∈ {1,..., }, we know ha ψ(η) sends Ci o some Cj. Le ki∈
{1,..., i}be such ha ψ(η) sends Ci,ki o Cj, j, and conside he b aid µ(i, ki)
de ined a he end o Subsec ion 5.1. I we conjuga e βby µ(i, ki) we mo e β[i]
om Ci, i o Ci,ki. I we u he conjuga e by ψ(η), hen β[i]goes o Cj, j.
Bu ηis consis en wi h β, so β[i]=β[j]. Hence, he in e io b aids in Cja e
p ese ed. We can do his o i= 1,..., , so we ob ain ha he b aid
Y
i=1
µ(i, ki)!ψ(η)
commu es wi h βand i s ubula b aid is η, so i is in p−1(η)∩Z(β). This
shows he esul .
We can inally b ing oge he all he esul s in his sec ion o s a e he ollowing:
Theo em 5.10 Le β∈Bnbe a non-pe iodic educible b aid in egula o m.
Then he sequence
1→Z(β[1])× · · · × Z(β[ ])g
−→ Z(β)p
−→ Z0(b
β)→1
is exac .
P oo By p oposi ion 5.3 gis injec i e, and by p oposi ion 5.9 pis su jec i e.
I jus emains o show ha im(g) = ke (p).
19
By cons uc ion, e e y elemen in he image o ginduces a i ial ubula b aid,
so im(g)⊂ke (p). Le hen α∈ke (p), ha is, bα= 1. Since α∈Z(β), we
ha e α−1βα =β, and since βi,k = 1 o k6= i, we mus ha e α−1
i,k 1αi,k+1 = 1,
so αi,k =αi,k+1 o k= 1,..., i−1. Hence αi,1=αi,2=· · · =αi, i o e e y
i. Mo eo e , we ha e β[i]=βi, i=α−1
i, iβi, iαi,1=α−1
i,1β[i]αi,1, so αi,1∈Z(β[i]).
The e o e, α=g1(α1,1)g2(α2,1)···g (α ,1) = g(α1,1, α2,1, . . . , α ,1). Tha is,
ke (p)⊂im(g).
5.3 Finding a sec ion o p
In his subsec ion we will p o e ha he exac sequence o heo em 5.10 spli s.
We ecall ha b
βis ob ained om βby collapsing he disks bounded by ou -
e mos cu es in he canonical educ ion sys em o β o single punc u es. In
pa icula , he canonical educ ion sys em o b
βmus be emp y. Hence, b
βis
ei he pe iodic o pseudo-Anoso . We will dis inguish hese wo cases, o de ine
a mul iplica i e sec ion o p, bu i s we will show an easy pa icula case.
Recall ha a b aid is pu e i i induces he i ial pe mu a ion o i s base poin s.
P oposi ion 5.11 I b
βis pu e, he e is a homomo phism h:Z0(b
β)→Z(β)
such ha p◦h= 1.
P oo We shall p o e ha in his case, he homomo phism ψcons uc ed in
he p oo o p oposi ion 5.5 is such a sec ion. Le η∈Z0(b
β). Since b
βis pu e,
Ci={Ci,1} o all i. Hence, i ηsends Ci o Cj hen i sends he ube Ci,1
(con aining β[i]) o he ube Cj,1(con aining β[j]=β[i], since βis in egula
o m). The e o e, illing e e y ube in ηwi h he i ial b aid, ha is, de ining
h(η) = ψ(η), yields indeed an elemen o Z(β).
Nex we s udy he gene al case, depending whe he b
βis pe iodic o pseudo-
Anoso .
P oposi ion 5.12 I b
βis pe iodic, he e is a homomo phism h:Z0(b
β)→Z(β)
such ha p◦h= 1.
P oo Recall ha we a e s udying βup o conjugacy. This implies ha we
can also s udy b
βup o conjugacy since, o e e y ξ∈Bm, i we conjuga e β
by ψ(ξ) we a e conjuga ing b
βby ξ. Mo eo e , a e conjuga ing by ψ(ξ), β
con inues o be in egula o m (up o enaming he ci cles in R(β)). The e o e
20
we can suppose, up o conjugacy, ha b
βis a igid o a ion o he disc, ha is,
a powe o δ(m)o γ(m).
Suppose i s ha b
β=δk
(m) o some k. We can suppose ha kis no a mul iple
o m, since in ha case b
βwould be a powe o ∆2
(m), hus i would be pu e,
and his case has al eady been s udied in p oposi ion 5.11. Recall he analysis
o pe iodic b aids in sec ion 3: he base poin s Q1,...,Qmo b
βwill be e enly
dis ibu ed along a ci cle o adius 1 a ound 0. Le d= gcd(m, k)< m and
=m/d. Then b
βsends Qi o Qi+k, and he e a e do bi s C1,...,Cdo leng h
. The o bi Ciwill con ain he poin s Quwhe e u≡i(mod d). Since we can
choose which ubes o βcon ain he in e io b aids, we will suppose ha hese
a e he ubes s a ing a Qm−d+1, Qm−d+2,...,Qm, ha is, he las dpoin s
o Dm.
We will conside now some line segmen s in Dwhich sepa a e he poin s
Q1,...,Qmin o se s o dpoin s. Le Lbe he line segmen joining he
o igin wi h he bo de o D, passing be ween he poin s Qm−dand Qm−d+1 ,
and le L′be he segmen passing be ween Qmand Q1. No ice ha Land
L′de e mine a sec o which con ains he poin s Qm−d+1, . . . , Qm, co espond-
ing o he ubes o βwi h non i ial in e io b aids. Le ϕ:C→Cbe
he o a ion a ound he o igin by an angle o 2πk/m ( he angle induced by
b
β), and deno e Li=ϕi(L). Since gcd(m, k) = d, he segmen s L0,...,L −1
di ide Din o m/d = sec o s, each one o angle 2π/ and con aining he
poin s Qid+1,...,Qid+d o some i. Take he smalles in ege e > 0 such ha
ϕe(L) = L′. Then one has L0=Land Le=L′. We a e in e es ed in he union
o segmen s L=L1∪L2∪ · · · ∪ Le(see igu e 8 o an example).
Figu e 8: The segmen s L,L′, and he union o segmen s L, o b
β=δ6∈B15 .
Le hen η∈Z0(b
β). In o de o de ine h(η), i su ices o de ine i s in e io
b aids. This is done as ollows: ecall ha , since ηcommu es wi h b
β, i can
be iso oped o a symme ic b aid (wi h espec o he o a ion ϕ), so we ake
a symme ic ep esen a i e o η. Fo e e y base poin Qio b
β(co esponding
21
o a ci cle Cj,u ), conside he s and o ηs a ing a Qi( he i h s and o
η). Then we de ine he in e io b aid h(η)j,u = (β[j])L(η,i), whe e L(η, i)∈Z
is he algeb aic numbe o imes ha he i h s and o ηc osses L. This is
well de ined by heo em 3.2 (i you ake wo dis inc ep esen a i es o ηas a
symme ic b aid, hey a e iso opic h ough symme ic b aids, so he s ands
ne e ouch he o igin and he in e sec ion numbe L(η, i) is p ese ed).
In o he wo ds, we de ine h(η) as ollows: we s a wi h i ial in e io b aids,
and we ollow he mo emen o he s ands o η. Each ime a s and c osses a
segmen o Lin he posi i e sense, we mul iply i s in e io b aid by β[j](whe e
jis he index o he o bi Cjo ha s and). And e e y ime a s and c osses
Lin he nega i e sense, we mul iply i s in e io b aid by β−1
[j].
We ha e hus de ined a map h:Z0(b
β)→BR(β). To show ha his a homo-
mo phism, i su ices o see ha he in e io b aids o ηξ a e he p oduc o
hose o ηand ξ, o η, ξ ∈Z0(b
β). Suppose ha he i h s and o ηgoes
om Qi(co esponding o Cj,u ) o Qi′(co esponding o Cj′,u′). Hence η
sends Cj o Cj′, and since η∈Z0(b
β), i ollows ha β[j]=β[j′]. One also has,
by de ini ion, L(ηξ, i) = L(η, i) + L(ξ, i′). The e o e (ηξ)j,u = (β[j])L(ηξ,i)=
(β[j])L(η,i)(β[j])L(ξ,i′)=ηj,uξj′,u′, so his a homomo phism.
We mus inally show ha , wi h his de ini ion, h(η)∈Z(β), o e e y η∈
Z0(b
β). We will de ine i s some special b aids. Fo e e y i, j ∈ {1,...,d}
such ha i < j and β[i]=β[j], de ine he symme ic b aid Si,j =Sj,i =
θ∗
(σi···σj−2σj−1σj−2···σi) (see igu e 3 in sec ion 3 o ecall he de ini ion o
θ∗
, and igu e 9 he e o an example). The b aid Si,j commu es wi h b
β(since
i is symme ic), and i pe mu es he o bi s Ciand Cj, p ese ing he o he s.
Hence Si,j ∈Z0(b
β). Mo eo e , i s s ands do no c oss L, so by de ini ion o h
one has h(Si,j) = ψ(Si,j) ( he in e io b aids a e i ial).
Figu e 9: The b aid S1,3, o b
β=δ6∈B15 (assuming ha β[1] =β[3] ).
Bu h(Si,j) commu es wi h β, since he only ubes i pe mu es a e hose o
22
he o bi s Ciand Cj; among hese ubes, he only wo wi h non- i ial in e io
b aids a e exchanged, and hei co esponding in e io b aids a e equal (β[i]=
β[j]). Hence he in e io b aids o βa e p ese ed by ψ(Si,j) = h(Si,j), so
h(Si,j)∈Z(β).
Take hen an a bi a y η∈Z0(b
β). We mus show ha h(η)∈Z(β). Suppose
ha ηsends Ci o Cj o some i, j. Then β[i]=β[j], so Si,j is de ined, and he
b aid ηSi,j p ese es he o bi Ci. We can con inue his way, un il we ob ain a
b aid ηSi1,j1···Sik,jk ha commu es wi h b
βand p ese es e e y o bi Ci, o
i= 1,...,d. Since h(Si,j)∈Z(β) o e e y i, j, and his a homomo phism, in
o de o show ha h(η)∈Z(β) i su ices o show ha h(ηSi1,j1···Sik,jk)∈
Z(β). The e o e, we can suppose ha ηp ese es e e y o bi Ci.
Deno e α=h(η). We need o show ha he in e io b aids o α−1βα coincide
wi h hose o β. Since ηp ese es all o bi s, we will conside jus he ubes
o C1, he o he ones being analogous. Suppose ha αsends he ci cle C1,u
o C1, . Then i mus send C1, o C1, −u o e e y ( he indices a e aken
modulo ).
We will iden i y he poin s Q1,...,Qmwi h hei co esponding ci cles Ci, .
Fo e e y = 1,..., , le b be he s and o ηs a ing a C1, . Since η
is symme ic, we ha e ϕ(b ) = b +1 . Suppose ha b c osses imes he
segmen Li, whe e i∈ {0,..., −1}. Then b +1 will c oss imes he segmen
ϕ(Li) = Li+1 . The e o e, i b c osses l imes L, and i i c osses l0 imes L0
and le imes Le, hen b +1 c osses l−le+l0 imes L.
I 6= and 6=u, hen b nei he s a s no ends a C1, . Then i c osses L0
and Le he same numbe o imes. Hence, b and b +1 c oss L he same
numbe o imes, say l. The e o e, i 6= , u, one has (α−1βα)1, −u=
(α1, )−1β1, α1, +1 =β−l
[1] 1βl
[1] = 1 = β1, −u.
I u= = , hen b s a s a ends a C1, . Hence, as abo e, i c osses L0
and Le he same numbe o imes, so b =b and b +1 =b1c oss L he
same numbe o imes, say l. We hen ha e (α−1βα)1, −u= (α−1βα)1, =
(α1, )−1β1, α1,1=β−l
[1] β[1]βl
[1] =β[1] =β1, =β1, −u. Hence, i u= , we ha e
al eady seen all he possible cases. We will hen suppose ha u6= .
I = , hen b s a s (bu does no end) a C1, . Hence, i c osses Leone
mo e ime (in he posi i e sense) han i c osses L0. The e o e, i b =b c osses
l imes L, hen b +1 =b1c osses i l−1 imes. One has: (α−1βα)1, −u=
(α−1βα)1, −u= (α1, )−1β1, α1,1=β−l
[1] β[1]βl−1
[1] = 1 = β1, −u=β1, −u.
Finally, i =u hen b ends (bu does no s a ) a C1, . In his case, i
c osses Leone less ime (in he posi i e sense) han i c osses L0. Hence, i
23
b =buc osses l imes L, hen b +1 =bu+1 c osses i l+ 1 imes. One hen
has: (α−1βα)1, −u= (α−1βα)1, = (α1,u)−1β1,uα1,u+1 =β−l
[1] 1βl+1
[1] =β[1] =
β1, =β1, −u.
The e o e, in e e y possible case we ha e (α−1βα)1, −u=β1, −u, o e e y
. This means ha he in e io b aids o (α−1βα) and o βcoincide, ha is,
α=h(η) commu es wi h β, as we wan ed o show.
This comple es he p oo o p oposi ion 5.12 in he case b
β=δk
(m), and i only
emains o deal wi h he case when b
β=γk
(m). As abo e, we can suppose ha
kis no a mul iple o m−1, since in ha case b
βwould be pu e, and his
case has al eady been ea ed in p oposi ion 5.11. Hence, he only ixed poin
in he pe mu a ion induced by b
βis he o igin. The e o e, e e y ηcommu ing
wi h b
βmus ix he o igin. This means ha , o e e y η∈Z0(b
β), we can ill
i s cen al ube wi h he i ial b aid, and he o he ubes in he same way as
abo e (de ining L, and coun ing he numbe o imes each s and c osses L).
This de ines a homomo phism h:Z0(b
β)→Z(β) which is a sec ion o p. The
p oo is he same as abo e.
I emains o s udy he case when b
βis pseudo-Anoso .
P oposi ion 5.13 I b
βis pseudo-Anoso , hen he e is a homomo phism
h:Z0(b
β)→Z(β)such ha p◦h= 1.
P oo In his case, we know ha Z(b
β) is a ee abelian g oup o ank 2, gen-
e a ed by a pseudo-Anoso and a pe iodic b aid. Hence, Z0(b
β) is an abelian
g oup o ank one o wo. No ice ha ∆2
(m)∈Z0(b
β), because his b aid com-
mu es wi h b
βand because π∆2is i ial, and hus consis en wi h β. Hence
Z0(b
β) con ains a leas one pe iodic elemen . On he o he hand, b
βbelongs
i sel o Z0(b
β), since πb
βis clea ly consis en wi h β. Hence in Z0(b
β) he e a e
also pseudo-Anoso b aids. Since all powe s o a pe iodic b aid a e pe iodic,
and all powe s o a pseudo-Anoso b aid a e pseudo-Anoso , i ollows ha
Z0(b
β) has in ac ank wo. Mo e p ecisely, Z0(b
β) = hηi × hρi, whe e ηis
pseudo-Anoso and ρis pe iodic. In pa icula , we ha e b
β∈ hηi × hρi, and he
h ee b aids b
β,ηand ρa e mu ually commu ing.
Ou aim is o de ine wo commu ing b aids h(ρ) and h(η) in Z(β) which a e
p eimages o ρ espec i ely ηunde p. The de ini ion o h(ρ) is e y simple: we
ake an a bi a y p eimage o ρunde p– his is possible since pis su jec i e
by p oposi ion 5.9. I emains o cons uc h(η).
24
Lemma 5.14 Suppose α∈BR(β), ha is, he b aid αp ese es he se o
ou e mos cu es in he canonical educ ion sys em o β. Suppose also ha
µ, ν ∈Z(bα). Suppose ha ιµ∈BR(β)is a b aid wi h i ial ubes (i.e. bιµ= 1)
such ha ψ(µ)·ιµ∈Z(α). Finally, suppose ha µand νinduce he same
pe mu a ion. Then we ha e as well ha ψ(ν)·ιµ∈Z(α).
In o he wo ds, i wo ubula b aids commu e wi h bα, i hey induce he same
pe mu a ion, and i some “ illing” o one o hem commu es e en wi h α, hen
he same illing o he o he will also commu e wi h α.
P oo o lemma 5.14 Conjuga ing αby ψ(ν)·ιµ∈Z(α) yields a ce ain
b aid α′; we ha e o check ha α′=α. Fi s ly, we ha e an equali y o
ubula b aids b
α′=bα, because ν, he ubula b aid o ψ(ν)·ιµ, commu es
wi h bα. Mo eo e , since µand νinduce he same pe mu a ions, we ha e o
i= 1,...,m ha he i h ube o α′con ains he same b aid as he i h ube o
(ψ(µ)·ιµ)−1·α·(ψ(µ)·ιµ). Since ψ(µ)·ιµcommu es wi h α, his is in u n
he same as he i h ube o α. In summa y, αand α′ha e he same ubula
b aids, and co esponding ubes con ain he same in e io b aids, which implies
ha α=α′.
Nex we ha e o hink in de ail abou he o bi s uc u e o b
β. Le us choose
a bi a ily a punc u e Po he disk Dm(on which b
βac s), and le O(b
β, ρ) be
he o bi o ha punc u e unde he ac ion o he subg oup hb
βi × hρio Z0(b
β).
Le O(b
β, ρ, η) be he o bi o Punde he ac ion o he g oup hρi × hηi(no e
ha his g oup is also isomo phic o Z2, and con ains b
β).
We a e going o suppose wi hou loss o gene ali y ha O(b
β, ρ, η) con ains all
punc u es o Dm, and we shall speci y how he ubes o ηco esponding o his
o bi shall be illed – indeed, i he e a e o he o bi s, hen hese can be ea ed
in same way, independen ly.
Special case: Le us s a by conside ing he simple special case ha
O(b
β, ρ, η) = O(b
β, ρ), i.e. ha he ac ion o ηp ese es he (b
β, ρ)-o bi . In
his case we ha e
Lemma 5.15 The e exis in ege s kand lsuch ha ηand b
βk·ρlinduce he
same pe mu a ions on O(b
β, ρ).
P oo o lemma 5.15 One can choose kand lsuch ha b
βkρl(P) = η(P),
simply because η(P) is in he o bi o Punde he ac ion o b
βand ρ. Now i
25
⩽S+ 1
2−m−1
2+b+m
2
=S(S+ 1)
2+b+m−1 = S(S+ 1)
2+b+u+
⩽S(S+ 1)
2+S+ =S(S+ 3)
2+ .
I = 0 hen b= 0 and k=S, so |G′|⩽S(S+3)
2=p(n).
I = 1 hen n= 2S+2 and k=S+1. Then |G′|⩽S(S+3)
2+1 = (S+1)(S+2)
2=
p(n).
I = 2 hen n= 2S+ 3 and k=S+ 1. Then |G′|⩽S(S+3)
2+ 2 = S2+3S+4
2<
(S+1)(S+4)
2=p(n).
Finally, i ⩾3 hen n= 2S+ + 1 so k⩾S+ /2. Hence
p(n)⩾(S+ /2)(S+ /2 + 1)
2=S2+ ( + 1)S+ ( + 2)/4
2
⩾S(S+ 3)
2+S/2 + /2>S(S+ 3)
2+ ⩾|G′|.
The e o e, in e e y case |G′|⩽p(n), and heo em 1.3 is p o ed.
Recall ha , in example 2.1, we de ined b aids o any numbe o s ands whose
cen alize could no be gene a ed by less han p(n) elemen s. The e o e, he
bound gi en by heo em 1.3 is he bes possible one.
7 Small gene a ing se s
We saw in he p e ious sec ion an uppe bound o he numbe o gene a o s
o he cen alize o a b aid β, in e ms o i s numbe o s ings. Bu one could
ob ain a be e bound i mo e in o ma ion abou βis gi en. In his sec ion we
will de ine a new gene a ing se G o Z(β), which is in mos cases smalle han
he se G′de ined be o e. I is also he smalles possible “na u al” gene a ing
se , in he sense ha each gene a o belongs o one o he + 1 ac o s in he
semidi ec p oduc decomposi ion in heo em 1.1(c). Thus in a philosophical
sense, Gis he “ igh ” gene a ing se , e en hough i is no in gene al he
smalles possible one, as we shall see a he end o his sec ion.
I βis pe iodic o pseudo-Anoso , we al eady know a minimal gene a ing se ,
wi h a mos wo elemen s. We also know a minimal gene a ing se o any
32
mixed b aid g oup (see he p oo o p oposi ion 6.1). Hence we can de ine Gby
induc ion on he numbe o s ands, when βis a educible, non-pe iodic b aid.
We can also suppose ha βis in egula o m. We ecall ha he in e io b aids
a e deno ed β[1],...,β[ ], and he ubula b aid b
β.
De ini ion 7.1 We will say ha i, j ∈ {1,..., }a e pe mu able i he e exis s
some η∈Z0(b
β)such ha η(Ci) = Cj.
Rema k ha pe mu abili y is an equi alence ela ion, and he de ini ion o
Z0(b
β) says ha i iand ja e pe mu able hen β[i]=β[j].
Le hen {i1,...,i } ⊂ {1,..., }be cose ep esen a i es o pe mu abili y.
Le Gikbe a minimal se o gene a o s o Z(β[ik]), and G0be a minimal
se o gene a o s o Z0(b
β). Then we de ine G=gi1(Gi1)∪ · · · ∪ gi (Gi )∪
h(GH). No ice ha G⊂G′, and hey coincide i and only i he e is no pai
o pe mu able indices.
P oposi ion 7.2 Gis a gene a ing se o Z(β).
P oo F om he exac sequence o heo em 5.10 i ollows ha , i Giis a se o
gene a o s o Z(β[i]), hen a se o gene a o s o Z(β) is G′=g1(G1)∪ · · · ∪
g (G )∪h(G0). Hence, we jus need o show ha i j∈ {1, . . . , } {i1,...,i },
hen e e y elemen in gj(Gj) can be w i en as a p oduc o elemen s in G.
Take hen jas abo e. The e mus be some ikpe mu able wi h j, so β[j]=β[ik]
and he e is some η∈Z0(b
β) such ha η(Cik) = Cj. No ice ha Gjis a se o
gene a o s o Z(β[j]) = Z(β[ik]), so e e y γ∈Gjcan be w i en as a p oduc
o elemen s in Gik. Hence he b aid α=h(η)−1gik(γ)h(η) can be w i en as
a p oduc o elemen s in G. Mo eo e , one has bα=d
h(η)−11d
h(η) = 1, and
he only non i ial in e io b aids in αa e hose co esponding o Cj. Since
he in e io b aids h(η)ik,l o e e y la e jus powe s o β[ik]=β[j], and γ
commu es wi h β[j], i ollows ha o e e y l,αj,l =γ. The e o e α=gj(γ),
so e e y elemen in gj(Gj) can be w i en as a p oduc o elemen s in G, hus
Gis a gene a ing se o Z(β).
The gene a ing se we ha e jus de ined is, un o una ely, no always he small-
es possible one:
Example 7.3 Conside he i e s ing b aid β=σ3σ4σ2σ3σ1σ2σ2σ3σ4σ1σ2σ3
– he canonical educ ion sys em o his b aid has wo ound ci cles, one con-
aining punc u es numbe 1, 2 and 3, he o he punc u es numbe 4 and 5; he
33
ubula b aid is jus a ull wis o he wo a s ings: b
β=σ2
1. Mo eo e , he
in e io b aids o each ube is i ial. Acco ding o heo em 1.1, he cen alize
o his b aid is
Z(β)∼
=(B3×B2)⋊PB2∼
=(B3×Z)⋊ Z
and he gene a ing se cons uc ed in his sec ion has ou elemen s: wo o
B3, and one o each ac o Z. We now claim ha his gene a ing se is no as
small as possible.
Indeed, B3×Zcan be gene a ed by only wo elemen s (and hus Z(β) can be
gene a ed by h ee elemen s). To see his, ecall ha he 3-s ing b aid g oup
is isomo phic o he g oup o he (2,3)- o us kno . Thus B3has a p esen a ion
hy, z |y3z−2= 1i(wi h y=σ1σ2and z=σ1σ2σ1). Mo eo e , he ac o Zis
gene a ed by σ4. Now he wo gene a o s (y, σ4) and (z, σ4) gene a e B3×Z,
because (1, σ4) can be w i en as (y, σ4)3(z, σ4)−2.
8 Some algo i hmic aspec s
The aim o his sec ion is o p esen he essen ial ing edien s o an algo i hm
which, o any gi en b aid, inds a gene a ing se o i s cen alize subg oup ha
ma ches he desc ip ion o he p e ious sec ions. Since, o any b aid βand
any k∈Z, he cen alize subg oups o βand β∆2kcoincide, we can always
assume ha βis posi i e.
We s a by men ioning ha algo i hms ha pe o m he Nielsen-Thu s on
classi ica ion, and gi e he in a ian oli a ions in he pseudo-Anoso case (in
he o m o ain acks), a e a ailable – no ably, he e a e Bes ina-Haendel’s
[5] and o Los’ [24] algo i hms; and compu e implemen a ions a e a ailable on
he web [9, 19].
We ecall b ie ly he idea o he wo au oma ic s uc u es on b aid g oups ha
a e ele an o us: o he i s one, gi en by Ga side [17] and Thu s on [33]
(and e ined by El-Ri ai and Mo on [12]), we hink o Dnhas ha ing he n
punc u es lined up on he eal line in he disk D. Fo he second one, gi en by
Bi man, Ko, and Lee [7], we hink o Bnas ha ing he npunc u es egula ly
spaced on he ci cle o adius 1. Apa om ha , he s uc u es a e exac ly
analogue. In he Ga side-Thu s on s uc u e, he e is a canonical way o w i e
βas a p oduc o di iso s o ∆, namely by pushing each c ossing be ween wo
s ings in o a ac o as a o he le as possible. This no mal o m is called
he le g eedy no mal o m. Fo ins ance, in his no mal o m all ac o s which
34
a e equal o ∆ (no jus di iso s o i ) a e g ouped oge he a he e y le o
he p oduc decomposi ion. Analogously, Bi man-Ko-Lee w i e each b aid as a
p oduc o di iso s o δin a le -g eedy way. I βis a posi i e b aid, hen i s
supe summi se is he subse o all elemen s αo i s conjugacy class which
sa is y he ollowing condi ions:
(i) αis posi i e,
(ii) he w i ing o αin le g eedy no mal o m has as ew ac o s as possible
among all elemen s sa is ying (i),
(iii) he w i ing o o αin le g eedy no mal o m has as many ac o s on he
le as possible equal o ∆ (o δ), among all elemen s sa is ying (i) and
(ii).
Two posi i e elemen s o Bna e conjuga e i and only i hei supe summi
se s coincide. Gi en β∈Bn he e is an algo i hm, gi en in [15] (which is an
imp o emen o he algo i hm in [12]), o compu e i s supe summi se . I is
as ollows: i s we epea edly cycle β(i.e. mo e he i s ac o di e en om
∆, espec i ely δ, o he end and calcula e he le g eedy o m o he esul ing
b aid), un il his p ocess uns in o a loop. A his poin we a e gua an eed o
ha e achie ed condi ion (ii) abo e. Then we epea edly decycle (i.e. mo e he
las ac o o he on and calcula e he le g eedy o m o he esul ing b aid)
un il we un in o a loop. Then all elemen s o his loop belong o he supe
summi se . A e wa ds, all o he elemen s o he supe summi se can be
ound ecu si ely by conjuga ing al eady known elemen s by (sui able) di iso s
o ∆ ( espec i ely δ), and e aining he esul i i belongs o he supe summi
se .
This algo i hm o compu ing he supe summi se is necessa y o ou pu -
poses. Now suppose we a e gi en a b aid β∈Bnand we wan o compu e i s
cen alize . Fi s we need o de e mine i βis pe iodic, educible o pseudo-
Anoso , and hen we can use he esul s in his pape .
Rema k 8.1 Ve y ecen ly, V. Gebha d [18] p esen ed a be e algo i hm o
he conjugacy p oblem in b aid g oups. He de ined he ul a summi se , which
is in gene al much smalle han he supe summi se desc ibed he e.
Pe iodic elemen s
Deciding whe he a gi en elemen βo Bnis pe iodic is e y easy: one calcula es
he n−1s and he n h powe o β. Then βis pe iodic i and only i one o
he wo esul s is a powe o ∆2.
35
I βn−1= ∆2k o some k∈N, hen βis conjuga e o γk
(n)(as can be easily seen
om lemma 3.1), and a conjuga ing elemen can be ound explici ly using ei he
o he wo s anda d algo i hms. Simila ly, i βn= ∆2k, hen βis conjuga e
o δk
(n), and ei he algo i hm yields an explici conjuga ing elemen . In ei he
case, one can ind explici ly a gene a ing se o he cen alize subg oup wi h
only wo elemen s, using p oposi ions 3.3 o 3.5.
Finding educing cu es o educible elemen s
A e es ablishing ha an elemen βo Bnis no pe iodic, we need o check
whe he i is educible, and i i is, we wan o ind explici ly an in a ian
mul icu e. This is, in ac , a s anda d pa o Bes ina-Haendel’s [5] and o
Los’ [24] algo i hms.
We wan o poin ou one pa icula y elegan al e na i e, which is due o Be-
na de e, Gu ie ez and Ni ecki [3] (see also [2]). We hink o Dnas ha ing
he npunc u es lined up ho izon ally, and we look a Ga side-Thu s on’s le
g eedy no mal o m. The key obse a ion om [3] is he ollowing: suppose
ha Cis an in a ian mul icu e o a b aid β, and ha he no mal o m o β
is β=β1·...·βk, whe e β1,...,βk∈Bna e di iso s o ∆. Mo eo e , suppose
ha all componen s o Ca e ound (i.e. ac ual geome ic ci cles in Dn). Then
we ha e no only ha β1·...·βn(C) = C, bu also ha all componen s o all
he mul icu es β1·...·βi(C) a e ound o i= 1,...,k.
As ema ked in [3] his implies as a co olla y ha in a ian mul icu es a e
isible as ound cu es in he supe summi se o β, and in pa icula he
educibil y o a b aid is easily de ec able om he supe summi se . To p o e
he co olla y we no e ha βhas a conjuga e in which all componen s o he
cu e sys em Ca e ound; mo eo e , βand i s conjuga e ha e he same supe
summi se . Now cycling and decycling his conjuga e does no change he ac
ha he e is a ound in a ian cu e sys em, by he key obse a ion abo e. A
he end o he cycling/decycling p ocedu e we ha e ound elemen s o he supe
summi se which con ain he desi ed ound in a ian cu es.
Now i is shown in [3] how o de e mine i a gi en b aid p ese es a sys em o
disjoin ound cu es. And he e is a ini e numbe o hese sys ems. Mo eo e ,
since o each elemen o he supe summi se we know how i can be conjuga ed
o ob ain β, we can ind explici ly all cu es ha belong o a educ ion sys em
o β. We can hen easily de e mine, by i s de ini ion, which o hese cu es
belong o he canonical educ ion sys em o β. Tha is, we can compu e he
canonical educ ion sys em o β.
36
By he esul s in his pape , Z(β) is hen a semi-di ec p oduc o wo g oups
ha can be compu ed by induc ion on he numbe o s ings. Hence, i only
emains o s udy he case when βis pseudo-Anoso .
Pseudo-Anoso elemen s: commu a ion wi h δk
(n)
Suppose ha ou b aid β ails he es s o pe iodici y and educibili y, hence i
is known o be pseudo-Anoso . We need o check i i commu es wi h a pe iodic
b aids o he han powe s o ∆2.
We shall hink o Dnas ha ing i s npunc u es uni o mly dis ibu ed o e he
ci cle o adius 1, and we conside Bi man-Ko-Lee’s le -g eedy no mal o m.
We wan o decide algo i hmically whe he βis conjuga e o a b aid αwi h
he p ope y ha αcommu es wi h δk
(n) o some posi i e in ege k < n. I i
is, we wan o know he conjuga ing b aid explici ly. The ollowing esul yields
such an algo i hm.
P oposi ion 8.2 Suppose ha a pseudo-Anoso b aid βhas a conjuga e
which commu es wi h δk
(n) o some in ege k. Then he e exis s an elemen α
o he supe summi se o βwhich has he p ope y ha α, and in ac e e y
ac o o he le g eedy no mal o m o α, commu es wi h δk
(n).
P oo Le β′be a conjuga e o βwhich commu es wi h δk
(n). I β′=β′
1·...·β′
is he le -g eedy no mal o m o β′, hen each ac o β′
iis a di iso o δ(n)which
is 2πk
n-symme ic. This ollows om he ac ha he e y de ini ion o he le -
g eedy no mal o m is comple ely o a ion symme ic. Mo e p ecisely, he ac
ha wo consecu i e ac o s β′
iβ′
i+1 de e mine a le -g eedy no mal o m is no
modi ied by o a ing hem. Hence, he p oduc (δ−k
(n)β′
1δk
(n))···(δ−k
(n)β′
δk
(n)) is in
le -g eedy no mal o m. Since his p oduc equals δ−k
(n)β′δk
(n)=β′, whose le -
g eedy no mal o m is β′
1···β′
k, we ob ain ha δ−1
(n)β′
iδ(n)=β′
i, o i= 1,..., .
Using he same a gumen induc i ely, we see ha he cycling and decycling
p ocedu e only e e c ea es b aids in le g eedy no mal o m in which all ac o s
a e 2πk
n-symme ic.
Now we no ice ha i is e y easy o decide i a gi en di iso o δ(in he
Bi man-Ko-Lee con ex ) is in a ian unde a gi en o a ion. Hence one can
de e mine i a b aid commu es wi h an (explici ly compu able) conjuga e o
δk
(n)by looking a he elemen s o i s supe summi se .
37
Pseudo-Anoso elemen s: commu a ion wi h γk
(n)
Now we wan o de e mine i a gi en pseudo-Anoso b aid commu es wi h a
conjuga e o γk
(n), o a gi en posi i e in ege k < n −1. This is only possible
i he e is some index i∈ {1,...,n}such ha βp ese es Pi, as can be easily
seen by looking a he co esponding pe mu a ions.
Call Pi={{Pi},{P1,...,Pi−1, Pi+1,...,Pn}}, a pa i ion o {P1,...,Pn}.
Then βshould belong o BPi. The e is a na u al map i:BPi→Bn−1which
consis s o o ge ing he i h s ing. No ice ha , i a b aid αcommu es wi h
γk
(n)(whe e P1is conside ed o be he cen al poin o D(n)) hen 1(α) com-
mu es wi h 1(γk
(n)) = δk
(n−1) .
Hence we ha e a necessa y condi ion ha mus be sa is ied. I βp ese es a
punc u e Pi, hen we conjuga e i o some α ha p ese es P1, and we es
whe he a conjuga e o 1(α) commu es wi h δk
(n−1) o some k < n −1. I his
does no happen, o i= 1,...,n, hen no conjuga e o βcommu es wi h γk
(n).
This necessa y condi ion is o cou se no su icien . A su icien and es able
condi ion is now gi en by he ollowing esul . Recall ha , by co olla y 3.7,
he e is an isomo phism χ= (¯
θ∗)−1θ∗ om Z(δk
(n−1)) o Z(γk
(n)), gi en by
adding a i ial s ing a he cen e o Dn−1. No ice ha , i ζ∈Z(γk
(n)), hen
χ( 1(ζ)) = ζ. Then one has:
P oposi ion 8.3 Suppose ha α∈Bnp ese es P1, and eα= 1(α)com-
mu es wi h δk
(n−1) . Then he ollowing wo s a emen s a e equi alen .
(i) αis conjuga e o an elemen ζo Bnwhich commu es wi h γk
(n), and he
conjuga ing homeomo phism p ese es P1.
(ii) αis conjuga e o χ(eα).
P oo The implica ion (ii)⇒(i) is immedia e, by choosing ζ:= χ(eα).
Fo he implica ion (i)⇒(ii), we suppose ha (i) holds, ha is, he e is an
elemen η∈BP1such ha η−1αη =ζ, whe e ζ∈Z(γk
(n)). We can apply 1 o
all hese elemen s, deno ing eη= 1(η) and e
ζ= 1(ζ). This yields (eη)−1eαeη=e
ζ,
whe e eα, e
ζ∈Z(δk
(n−1)).
I we show ha eη∈Z(δk
(n−1)), hen we can apply χ o all ac o s, ob aining
χ(eη)−1χ(eα)χ(eη) = χ(e
ζ) = ζ, hence χ(eα) is conjuga e o ζwhich is conjuga e
o α, and he esul ollows.
38
Le us hen show ha eηcommu es wi h δk
(n−1) . No ice ha ζis a pseudo-
Anoso b aid ha commu es wi h γk
(n). Hence i p ese es a p ojec i e olia ion
Fζ, which is in a ian unde a o a ion by an angle o 2πk
n−1. Bu in his case e
ζ
also p ese es Fζ, wi h he same s e ch ac o , hence i is also pseudo-Anoso .
Since eαis conjuga ed o e
ζ, hen i is pseudo-Anoso as well, and we call Feα
i s co esponding p ojec i e olia ion (which is also in a ian unde he same
o a ion, since eαcommu es wi h δk
(n−1) ). Since (eη)−1eαeη=e
ζ, we ha e ha eη
sends Feα o Fζ.
Now conside he b aid d=eη−1δk
(n−1)eη. I is conjuga e o δk
(n−1) , and hence
pe iodic. Mo eo e , i p ese es Fζ, so i commu es wi h e
ζ. Bu he pe iodic
elemen s in he cen alize o e
ζ o m a cyclic g oup con aining δk
(n−1) , and δk
(n−1)
is he only elemen ha ing exponen sum (n−2)k. Since dhas exac ly he same
exponen sum, i ollows ha d=δk
(n−1) . Hence eηcommu es wi h δ(n−1) , and
he esul ollows.
An algo i hm o es ing whe he a b aid βis conjuga e o a b aid which com-
mu es wi h γk
(n)is now easy o cons uc : o each o he npunc u es es
whe he he punc u e is ixed by β, and whe he o ge ing his punc u e yields
a b aid which is conjuga e o a b aid eα ha commu es wi h δk
(n). (We know
how o do his, by he esul s o he p e ious subsec ion). Fo each punc u e
ha does sa is y his p ope y, es whe he χ(eα) (which is ob ained om eα
by adding a “ i ial” s ing in he cen e), is conjuga e o β. I , o one o he
punc u es, his is he case, hen he answe is “yes”, o he wise “no”.
Pseudo-Anoso elemen s: inding oo s
I emains o desc ibe a las s ep o compu ing a gene a ing se o Z(β),
when βis pseudo-Anoso . We assume ha we ha e al eady compu ed he
subg oup hρio pe iodic b aids commu ing wi h β. Then we can mul iply
βby a sui able powe o ρ, o ob ain a b aid b ha p ese es he singula
lea es o he p ojec i e olia ions co esponding o β. Then we know ha
Z(β) = hαi × hρi, whe e αis he smalles possible oo o b.
The las p oblem, he e o e, is o de e mine whe he a gi en pseudo-Anoso
b aid bhas a k h oo , o gi en k, and o compu e ha oo . This p oblem
has been sol ed in [31] (gene alised o all Ga side g oups in [30]). Mo eo e ,
since he numbe o possible alues o kis ini e (we a e assuming ha bis
posi i e), we ha e an algo i hm o compu ing α, hus a gene a ing se o
Z(β).
39
Acknowledgemen s We a e g a e ul o a numbe o people o discussions
and aluable ideas ha g ea ly con ibu ed o his esea ch. The examples o
Nikolai V. I ano [21, 22], which we lea ned abou h ough discussions wi h
Mus a a Ko kmaz, we e an impo an inspi a ion and g ea ly helped us cla i y
ou ideas. I was hus om I ano ( ia Ko kmaz) ha we lea ned ha he num-
be o gene a o s may ha e o g ow quad a ically wi h he numbe o s ings,
con adic ing a conjec u e in [16]. We a e e y g a e ul o Sang Jin Lee who
la e , bu independen ly o I ano , came up wi h his examples, conjec u ed ha
hey ep esen he wo s case, and kindly communica ed hese ideas o us by
email. (Hessam Hamidi-Tehe ani ound he same examples as Lee immedia ely
a e lis ening o I ano ’s alk, bu we didn’ lea n his un il e y ecen ly.) We
also hank Da id Bessis o use ul discussions, and Joan Bi man o elling us
abou he e e ences [2] and [3].
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41