Weak compactness and Orlicz spaces
Abstract
We give new proofs that some Banach spaces have Peczynski's property (V)
Full text
arXiv:0904.2970v1 [math.FA] 20 Apr 2009 Weak ompatness and Orliz spaes Pasal Lefèvre, Daniel Li, Hervé Queéle, Luis Ro dríguez-Piazza June 19, 2013 Abstrat. We give new proofs that some Banah spaes have Peªzy«ski's property (V) . Mathematis Sub jet Classiation. Primary: 46B20; Seondary: 46E30 Key-words. M -ideal; Morse-Transue spae; Orliz spae; Peªzy«ski's property (V) . 1 Intro dution. Reall that a Banah spae X is said to have Peªzy«ski's prop erty (V) if one has a go o d weak-ompatness riterion in the dual spae X∗ of X , namely: every subset A of X∗ is relatively weakly ompat whenever it has the following prop erty (easily seen neessary): lim n→+∞sup x∗∈A|x∗(xn)|= 0 for every weakly unonditionaly Cauhy sequene (xn)n in X ( i.e. suh that Pn≥1|x∗(xn)|<∞ for any x∗∈X∗ ). Equivalently, X has Peªzy«ski's property (V) if and only if for every Banah spae Z and every non-weakly ompat op erator T:X→Z , there exists a subspae X0 , isomorphi to c0 , suh that T is an isomorphism between X0 and T(X0) . Beside the reexive spaes (and in partiular the Lp spaes for 1< p < ∞ ), the spaes C(S) of ontinuous funtions on ompat spaes S have prop erty (V) ; in partiular L∞ has (V) . Another general lass of Banah spaes having prop erty (V) is that of Banah spaes whih are M -ideal in their bidual, i.e. those for whih the anonial deomp osition of their third dual is an ℓ1 deomp osition: X∗∗∗ =X∗⊕1X⊥ (see [8, 9℄). Note that every subspae of a Banah spae M -ideal of its bidual is itself M -ideal of its bidual; hene every suh subspae has prop erty (V) . On the ontrary, a non-reexive Banah spae that do es not ontain c0 annot have prop erty (V) . In partiular, L1 do es not have this prop erty. Thus, the Lp spaes have (V) for 1< p ≤ ∞ , whereas L1 do es not have it. For the 1
Orliz spaes, whih are, in a natural sense, intermediate between L1 and L∞ , D. Leung [12℄ proved, when the dual spae is weakly sequentially omplete, not only that these Orliz spaes have prop erty (V) , but that they atually have the lo al prop erty (V) , i.e. all their ultrap owers have prop erty (V) . D. Leung's pro of uses non trivial prop erties of Banah latties. In this pap er, we shall give an elementary pro of of the (weaker) result that the Orliz spae LΨ has prop erty (V) , when the omplementary funtion of Ψ saties the ∆2 ondition. Aknowledgement. This work was made during the stay in Lens, in May June 2005, of the fourth-named author, as Professeur invité of the Université d'Artois . We are very grateful to the referee for having simplied the pro of of Theorem 2, making it shorter and very more elegant and oneptual, by giving us the statement and the pro of of Prop osition 5. 2 The Morse-Transue spae In this pap er, we shall onsider Orliz spaes dened on a probability spae (Ω,P) , that we shall assume non purely atomi. By an Orliz funtion, we shall understand that Ψ: [0,∞]→[0,∞] is a non-dereasing onvex funtion suh that Ψ(0) = 0 and Ψ(∞) = ∞ . To avoid pathologies, we shall assume that we work with an Orliz funtion Ψ having the following additional prop erties: Ψ is ontinuous at 0 , stritly onvex (hene stritly inreasing), and suh that Ψ(x) x−→ x→∞ ∞. This is essentially to exlude the ase of Ψ(x) = ax . The Orliz spae LΨ(Ω) is the spae of all (equivalene lasses of ) measurable funtions f: Ω →C for whih there is a onstant C > 0 suh that ZΩ Ψ|f(t)| CdP(t)<+∞ and then kfkΨ (the Luxemburg norm ) is the innimum of all p ossible onstants C suh that this integral is ≤1 . To every Orliz funtion is asso iated the omplementary Orliz funtion Φ = Ψ∗: [0,∞]→[0,∞] dened by: Φ(x) = sup y≥0xy −Ψ(y). The extra assumptions on Ψ ensure that Φ is itself stritly onvex. Throughout this pap er, we shall assume that the omplementary Orliz fun- tion satises the ∆2 ondition ( Φ∈∆2 ), i.e. , for some onstant K > 0 , and some x0>0 , we have: Φ(2x)≤KΦ(x),∀x≥x0. 2
This is usually expressed by saying that Ψ satises the ∇2 ondition ( Ψ∈ ∇2 ). This is equivalent to say that for some β > 1 and x0>0 , one has Ψ(x)≤ Ψ(βx)/(2β) for x≥x0 , and that implies that Ψ(x) x−→ x→∞ ∞ . In partiular, this exludes the ase LΨ=L1 . When Φ satises the ∆2 ondition, LΨ is the dual spae of LΦ . We shall denote by MΨ the losure of L∞ in LΨ . Equivalently (see [15℄, page 75), MΨ is the spae of (lasses of ) funtions suh that: ZΩ Ψ|f(t)| CdP(t)<+∞,∀C > 0. This spae is the Morse-Transue spae asso iated to Ψ , and (MΨ)∗=LΦ , isometrially if LΦ is provided with the Orliz norm, and isomorphially if it is equipp ed with the Luxemburg norm (see [15℄, Chapter IV, Theorem 1.7, page 110). We have MΨ=LΨ if and only if Ψ satises the ∆2 ondition, and LΨ is reexive if and only if both Ψ and Φ satisfy the ∆2 ondition. When the omplementary funtion Φ = Ψ∗ of Ψ satises it (but Ψ do es not satisfy this ∆2 ondition, to exlude the reexive ase), we have (see [15℄, Chapter IV, Prop osition 2.8, page 122, and Theorem 2.11, page 123): ( ∗ ) (LΨ)∗= (MΨ)∗⊕1(MΨ)⊥, or, equivalently, (LΨ)∗=LΦ⊕1(MΨ)⊥ , isometrially, with the Orliz norm on LΦ . For all the matter ab out Orliz funtions and Orliz spaes, we refer to [15℄, or to [11℄. It follows from the preeding equation ( ∗ ) that MΨ is an M -ideal in its bidual. Hene MΨ and all its subspaes have Peªzy«ski's prop erty (V) ([8, 9℄; see also [10℄, Chapter II I, Theorem 3.4, and the end of this paper). This result was shown by D. Werner ([19℄; see also [10℄, Chapter I I I, Example 1.4 (d), page 105), by a dierent way, using the ball intersetion prop erty (in these referenes, it is assumed moreover that Ψ do es not satises the ∆2 ondition, but if it satises it, the spae LΨ is reexive, and so the result is obvious). The pro of given in [8, 9℄ of the fat that Banah spaes whih are M -ideal in their bidual have prop erty (V) uses lo al reexivity and the notion of pseudobal l . We are going to give b elow a slightly dierent pro of, whih do es not use this last notion, and seems to us more transparent. Let us note that, however, a stronger property, namely Peªzy«ski's property (u) , was shown sine then to b e satised by the spaes M -ideal of their bidual (see [7℄ and, in a more general setting, [6℄; that follows also from [17℄). Theorem 1 (Godefroy-Saab, [8 , 9℄)℄ Every Banah spae whih is M -ideal in its bidual have property (V) . 3
Pro of. Assume that X∗∗∗ =X∗⊕1X⊥ and let T:X→Y b e a non weakly ompat map. By Gantmaher's Theorem, T∗∗ :X∗∗ →Y∗∗ is not weakly ompat either. This means that T(4)(X(4))6⊆ Y∗∗ . Sine X(4) =X∗∗ ⊕(X∗)⊥ (anonial deomposition of the third dual of X∗ ), there exists some u∈(X∗)⊥ , with kuk= 1 suh that T(4)(u)6= 0 . Now the M -ideal prop erty of X gives X(4) = (X∗)⊥⊕∞X⊥⊥ . It follows that kx+auk= max{kxk,|a|},∀x∈X, ∀a∈C. By lo al reexivity, we an onstrut a sequene (xn)n≥1 in X equivalent to the anonial basis of c0 and suh that kT xnk ≥ δ > 0 for every n≥1 . For that, let 0< δ < kT(4)uk , εn>0 b e suh that (1 −εn)kT(4)uk> δ and Qn≥1(1 + εn)≤2 , Qn≥1(1 −εn)≥1/2 . Assume that x1,...,xn have b een onstruted in suh a way that kT xkk> δ and n Y k=1 (1 −εk) max{|a1|,...,|an|} ≤ ka1x1+···+anxnk ≤ n Y k=1 (1 + εk) max{|a1|,...,|an|} for every salars a1,...,an . Let Vn b e the linear subspae of X(4) generated by {u, x1,...,xn} . By Bellenot's version of the priniple of lo al reexivity ([1℄, Corollary 7), there exists an op erator An:Vn→X suh that kAnk , kA−1 nk are less or equal than (1 + εn+1) , An is the identity on the linear span of {x1,...,xn} and kT(4)uk−kT Anuk≤εn+1kT(4)uk. If xn+1 =Anu , it is now lear that n+1 Y k=1 (1 −εk) max{|a1|,...,|an+1|} ≤ ka1x1+···+an+1xn+1k ≤ n+1 Y k=1 (1 + εk) max{|a1|,...,|an+1|} for every salars a1,...,an+1 and kT xn+1k> δ . Hene 1 2max{|a1|,...,|an|} ≤ ka1x1+···+anxnk ≤ 2 max{|a1|,...,|an|} for every salars a1,...,an . Sine kT xnk> δ , this ends the pro of. 4
3 Peªzy«ski's prop erty (V) for LΨ . As we said, the following result is a partiular ase of that of D. Leung ([12℄), but we shall give an elementary pro of. Theorem 2 ([12 ℄) Suppose that the onjugate funtion Φ of Ψ satises the ∆2 ondition. Then, the spae LΨ has Peªzy«ski's property (V) . As it is well-known (and easy to prove), every dual spae with Peªzy«ski's prop erty (V) is a Grothendiek spae: every weak-star onvergent sequene in its dual is weakly onvergent. Hene, we have: Corollary 3 Suppose that the onjugate funtion Φ of Ψ satises the ∆2 ondition. Then the spae LΨ is a Grothendiek spae. Pro of of Theorem 2. We may assume that LΨ is a real Banah spae. The pro of arises diretly from the two following results, sine E=MΨ is a Banah lattie having prop erty (V) and LΨ= (MΨ)∗∗ . Lemma 4 Suppose that the Orliz funtion Ψ does not satisfy the ∆2 ondition. Then for every sequene (gn)n in the unit bal l of LΨ , there exist a sequene (fn)n in MΨ and a positive funtion g∈LΨ suh that |gn−fn| ≤ g . Prop osition 5 Let E be a Banah lattie that has property (V) . Suppose that for every sequene (x∗∗ n)n in BE∗∗ , there are a sequene (xn)n in E and a positive x∗∗ ∈E∗∗ suh that |x∗∗ n−xn| ≤ x∗∗ . Then E∗∗ has property (V) . Pro of of Lemma 4. Sine, by dominated onvergene, lim t→+∞ZΩ Ψ|gn|1I{|gn|>t}dP= 0, we an hoose, for every n≥1 , a p ositive numb er tn so big that: ZΩ Ψ|gn|1I{|gn|>tn}dP≤1 2n , and, moreover suh that: +∞ X n=1 P(|gn|> tn)<+∞. This last ondition implies, by Borel-Cantelli's lemma, that, almost surely, |gn| ≤ tn for n large enough. Equivalently, by setting: ˜gn=gn1I{|gn|>tn}, 5
we have, almost surely ˜gn= 0 for n large enough. It follows that almost surely supn|˜gn| is attained. Set now: An={ω∈Ω ; |˜g1(ω)|,...,|˜gn−1(ω)|<|˜gn(ω)| and |˜gk(ω)| ≤ |˜gn(ω)|,∀k≥n} ( ω∈An if and only if n is the rst time for whih supk|˜gk(ω)| is attained). The sets An are disjoint and sup n≥1|˜gn|= +∞ X n=1 |˜gn|1IAn. Hene, if we set: g= sup n≥1|˜gn|, we have g∈LΨ , sine, using the disjointness of the An 's: ZΩ Ψ(g)dP= +∞ X n=1 ZAn Ψ(|˜gn|)dP≤ +∞ X n=1 ZΩ Ψ(|˜gn|)dP≤ +∞ X n=1 1 2n= 1. That proves the lemma, by taking fn=gn−˜gn , whih is in L∞⊆MΨ . Pro of of Prop osition 5. Supp ose that T:E∗∗ →Y is not weakly ompat. Then there exists a sequene (x∗∗ n)n in BE∗∗ suh that (T x∗∗ n)n is not relatively weakly ompat. Cho ose (xn)n and x∗∗ as in the statement of the Prop osition, and set y∗∗ n=x∗∗ n−xn for all n . We have either: (a) (T xn)n is not weakly ompat, or (b) (T y∗∗ n)n is not weakly ompat. If (a) holds, T|E:E→Y is not weakly ompat; hene T|E xes a opy of c0 . If (b) holds, let I b e the losed lattie ideal generated by x∗∗ in E∗∗ , normed so that [−x∗∗, x∗∗] is the unit ball, and let i:I→E∗∗ b e the inlusion map. Sine (y∗∗ n)n lies in [−x∗∗, x∗∗] , T◦i is not weakly ompat. But I is lattie isomorphi to a C(K) spae, and hene has prop erty (V) . Thus T◦i xes a opy of c0 . So T xes a opy of c0 . Remark. We annot exp et that, for tn big enough, the funtions ˜gn ould have a small norm. For example, let G b e a standard gaussian random variable N(0,1) . For Ψ = Ψ2 ( Ψ2(x) = ex2−1 ), we have, for every t > 0 : ZΩ Ψ2|G|1I{|G|>t} εdP=1 √2πZ|x|>t (ex2/ε2−1) e−x2/2dx = +∞ for every ε < √2 ; that means that kG1I{|G|>t}kΨ2≥√2 for every t > 0 (reall that kGkΨ2=p8/3 : see [13℄, page 31). 6
4 Conluding remarks and questions 1. The full D. Leung's result that LΨ have the loal property (V) , i.e. every ultrap ower of LΨ have the property (V) (see [3℄) annot b e obtained straightforwardly from our pro of. Indeed, sine LΨ= (MΨ)∗∗ is 1 -omplemented in every ultrapower of MΨ , it would sue to prove that every suh ultrapower has prop erty (V) ; but if (MΨ)U∗ ontains (LΦ)U as a w∗ -dense subspae, it is bigger. The ultraprower (LΦ)U is not exatly known in general. In the partiular ase of Ψ = Ψ2 ( Ψ2(x) = ex2−1 ), we have ([4℄, Prop osition 4.1 and Prop osition 4.2): (LΦ2)U∼ =LΦ2(PU)⊕L1(µU). However, sine (LΨ)∗= (LΦ)∗∗ ∼ =LΦ⊕1L1(µ) , all the o dd duals of LΨ an b e written (LΨ)(2n+1) ∼ =(LΨ)∗⊕1L1(µn). Hene we get that all the even duals of LΨ have the prop erty (V) . 2. We an dene the Hardy-Orliz spaes HΨ , in a natural way: it is the subspae of LΨ onsisting of the funtions on the unit irle T=∂D whih have an analyti extension in D ; equivalently, it is the subspae of LΨ whose negative Fourier o eients vanish. In [2℄, J. Bourgain proved that H∞ has prop erty (V) . Do es HΨ have prop erty (V) ? Note that the answer annot follow trivially from our Theorem 2 sine HΨ is omplemented in LΨ if and only if LΨ is reexive: indeed, the Riesz pro jetion from LΨ onto HΨ is b ounded if and only if LΨ is reexive ([18℄; see [16℄, Chapter VI, Theorem 2.8, page 196), and we have: Prop osition 6 Assume that Ψ∈ ∇2 . Then the Hardy-Orliz spae HΨ is omplemented in LΨ if and only if the Riesz projetion is bounded on LΨ . Hene HΨ is omplemented in LΨ if and only if LΨ is reexive. Pro of. Only the neessary ondition needs a pro of. Assume that there is a b ounded pro jetion P from LΨ onto HΨ . For every f∈MΨ , and for every g∈LΦ , the translations t7→ ft and t7→ gt are ontinuous. Hene we an dene ˜ P by setting: h˜ Pf, gi=ZThP(ft), gtidt. One has k˜ PfkΨ≤ kPkkfkΨ , so that ˜ P is bounded from MΨ into LΨ . On the other hand, it is immediate to see that for every trigonometri polynomial f , one has, if en(x) = einx : ˜ P(f) = X n∈Z ˆ f(n)\ P(en)(n)en. Sine P is a pro jetion, we have P(en) = en for n≥0 ; and sine P takes its values in HΨ , we have \ P(en)(k) = 0 for k < 0 ; in partiular \ P(en)(n) = 0 for n < 0 . 7
We get therefore: ˜ P(f) = X n≥0 ˆ f(n)en, that is ˜ P is the restrition to MΨ of the Riesz pro jetion. Hene the Riesz pro jetion is b ounded on MΨ . By taking its bi-adjoint, we get that it is b ounded on LΨ . In Ryan's pap er ([18℄), it is assumed that Ψ is an N -funtion, that is limx→0Ψ(x) x= 0 . But we may mo dify Ψ on [0,1] to get an N -funtion Ψ1 . Sine we work on a probability spae (Ω,P) , the new spae LΨ1 is equal, as a vetor spae, to LΨ , but with an equivalent norm. Hene Ryan's result remains true without this assumption. Note that, when the probability spae (Ω,P) is separable, sine we have assumed that Ψ∈ ∇2 , the reexivity of LΨ is equivalent to its separability (see [15℄, Chapter I I I, Theorem 5.1, pages 8788). 3. Prop erty (V) allows us to say that LΨ lo oks like Lp , 1< p ≤ ∞ . In some sense, it may b e seen as lose to L∞ when Ψ/∈∆2 , sine it is not reexive. However, from other points of view, it is loser to Lp with p < ∞ ; on the one hand, it is a bidual spae; on the other hand, one has: Prop osition 7 If Ψ∈ ∇2 , then LΨ never has the Dunford-Pettis property. Pro of. We are atually going to show that MΨ do es not have the Dunford- Pettis property. That will prove the prop osition, sine LΨ= (MΨ)∗∗ . Sine Ψ∈ ∇2 , there is some α > 1 and some c > 0 suh that Ψ(x)≥cxα . It follows that LΨ⊆Lα and the natural injetion i:LΨ→Lα is bounded, and hene weakly ompat, sine Lα is reexive. Take now an orthonormal sequene (rn)n≥1 in L2 with onstant modulus equal to 1 (for example, an indep endent sequene of random variables taking the values ±1 eah with probability 1/2 ). One has RΩrnf dP−→ n→+∞0 for every f∈L2 . By density, this remains true for every f∈L1 , and in partiular for every f∈LΦ , sine LΦ⊆L1 . Therefore, (rn)n≥1 weakly onverges to 0 in MΨ . Sine krnkα= 1 , i(rn)n do es not norm-onverge to 0 , and hene the weakly ompat map i:MΨ→Lα is not a Dunford-Pettis op erator. Therefore MΨ do es not have the Dunford-Pettis prop erty. A slightly dierent way to prove this is to use that for every Banah spae X whih has the Dunford-Pettis prop erty and whih do es not ontain ℓ1 , its dual X∗ has the Shur prop erty ([5, 14℄; see also [13℄, Chapitre 7, Exerie 7.2). But MΨ do es not ontain ℓ1 (b eause all its subspaes have property (V) ; or b eause its dual LΦ is separable). Hene LΦ would have the Shur prop erty. The same argument as ab ove shows that is not the ase. 4. We have required in this pap er that the omplementary funtion Φ satises the ∆2 ondition. Hene, in some sense, the spae LΨ is far from L1 . We may ask what happens when we are in the other side of the sale, namely when LΨ 8
is lose to L1 . But if Ψ satises the ∆2 ondition, then LΨ= (MΦ)∗ and MΦ , b eing M -ideal of its bidual, has property (V) , as said in the Introdution. It follows that LΨ is weakly sequentially omplete (and in fat has prop erty (V∗) ), and if we assume that Φ/∈∆2 (so as LΨ is not reexive), then LΨ do es not have prop erty (V) . Referenes [1℄ S. F. Bellenot, Lo al Reexivity of Normed Spaes, Op erators, and Fréhet Spaes, J. Funt. Anal. 59(1) (1984), 111. [2℄ J. Bourgain, H∞ is a Grothendiek spae, Studia Math. 75 (1983), 193216. [3℄ M. D. Contreras and S. Díaz, Some Banah Spae Prop erties of the Duals of the Disk Algebra and H∞ , Mihigan Math. J. 46 (1999), 123141. [4℄ D. Daunha-Castelle et J.-L. Krivine, Appliations des ultrapro duits à l'étude des espaes et des algèbres de Banah, Studia Math. 41 (1972), 315334. [5℄ H. Fakhoury, Sur les espaes de Banah ne ontenant pas ℓ1(N) , Math. Sand. 41 (1977), 277289. [6℄ G. Go defroy, N. J. Kalton, and P. D. Saphar, Unonditional ideals in Banah spaes, Studia Math. 104, no. 1 (1993), 1359. [7℄ G. Go defroy and D. Li, Banah spaes whih are M -ideals in their bidual have prop erty (u) , Ann. Inst. Fourier (Grenoble) 39, no. 2 (1989), 361371. [8℄ G. Go defroy et P. Saab, Quelques espaes de Banah ayant les propriétés (V) ou (V∗) de A. Peªzy«ski, C.R. Aad. Si. Paris, Série A 303 (1986), 503506. [9℄ G. Go defroy and P. Saab, Weakly unonditionally onvergent series in M - ideals, Math. Sand. 64 (1989), 307318. [10℄ P. Harmand, D. Werner and W. Werner, M -ideals in Banah Spaes and Banah Algebras, Leture Notes in Math. 1547, Springer (1993). [11℄ M. A. Krasnosel'ski and Ya. B. Rutiki, Convex funtions and Orliz spaes (translation), P. Noordho Ltd., Groningen (1961). [12℄ D. Leung, Weak ∗ onvergene in higher duals of Orliz spaes, Pro eedings Amer. Math. So . 103 (3) (1988), 797800. [13℄ D. Li et H. Queéle, Introdution à l'étude des espaes de Banah Analyse et Probabilités, Cours Sp éialisés 12, Soiété Mathématique de Frane (2004). 9