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Received: 28 May 2024 Accepted: 26 January 2025 DOI: 10.1112/jlms.70077 Journal of the London Mathematical Society RESEARCH ARTICLE Criteria for extension of commutativity to fractional iterates of holomorphic self-maps in the unit disc Manuel D. Contreras1Santiago DΓaz-Madrigal1 Pavel Gumenyuk2 1Camino de los Descubrimientos, s/n, Departamento de MatemΓ‘tica Aplicada II and IMUS, Universidad de Sevilla, Sevilla, Spain 2Department of Mathematics, Politecnico di Milano, Milan, Italy Correspondence Manuel D. Contreras, Camino de los Descubrimientos, s/n, Departamento de MatemΓ‘tica Aplicada II and IMUS, Universidad de Sevilla, Sevilla, 41092 Spain. Email: contrer[email protected] Funding information Ministerio de InnovaciΓ³n y Ciencia, Grant/Award Number: PID2022-136320NB-I00; INdAM (GNASAGA) [Correction added on 12 May, 2025, after first online publication: The copyright line was changed.] Abstract Let πbe a univalent non-elliptic self-map of the unit disc π»and let (ππ‘)be a continuous one-parameter semigroup of holomorphic functions in π»such that π1β ππ½π» commutes with π. This assumption does not imply that all elements of the semigroup (ππ‘)commute with π.In this paper, we provide a number of sufficient conditions that guarantee that ππ‘β¦π=πβ¦ππ‘for all π‘>0:This holds, for example, if πand π1have a common boundary (regular or irregular) fixed point different from their common DenjoyβWolff point π, or when π1has a boundary regular fixed point πβ πat which πis isogonal, or when (π β ππ½π»)β(π1βππ½ π»)has an unrestricted limit at π. In addition, we analyze how πbehaves in the petals of the semigroup (ππ‘). MSC 2020 30C55, 37F44, 30D05 (primary) Contents 1. INTRODUCTION AND MAIN RESULTS ......................... 2 2. NOTATION AND PRELIMINARIES............................ 7 2.1. Notation ....................................... 7 2.2. Holomorphic self-maps of the unit disc ....................... 7 Β© 2025 The Author(s). The Journal of the London Mathematical Society is copyright Β© London Mathematical Society. This is an open access article under the terms of the Creative Commons Attribution License, which permits use, distribution and reproduction in any medium, provided the original work is properly cited. J. London Math. Soc. (2) 2025;111:e70077. wileyonlinelibrary.com/journal/jlms 1of31 https://doi.org/10.1112/jlms.70077
2of31 CONTRERAS et al. 2.3. Holomorphic models for univalent self-maps .................... 8 2.4. Commuting holomorphic self-maps ......................... 9 2.5. One-parameter semigroups in the unit disc ..................... 11 3. THE STARTING EXAMPLE AND A CHARACTERIZATION OF SELF-MAPS COMMUTING WITH A SEMIGROUP .......................... 12 4. PROOF OF THEOREM 1.3................................. 13 5. PETALS AND COMMUTATIVITY I. AUXILIARY RESULTS ............... 15 6. PROOF OF THEOREM 1.4................................. 18 7. PETALS AND COMMUTATIVITY II. PROOF OF THEOREMS 1.8 AND 1.9 ....... 20 8. PETALS AND ISOGONALITY............................... 22 9. PROOF OF THEOREM 1.2................................. 28 10. COMMUTING ONE-PARAMETER SEMIGROUPS ................... 28 APPENDIX A: THE ELLIPTIC CASE ............................. 29 ACKNOWLEDGEMENTS................................... 30 REFERENCES......................................... 30 1 INTRODUCTION AND MAIN RESULTS This paper is motivated by the following natural and quite old problem in discrete holomorphic iteration: Given a holomorphic self-map of the unit disc, that is, πβπ§ππ
( π»), determine or at least analyze those πβπ§ππ
( π»)that commute with π,see[1, section 4.10]. This kind of questions has also been treated in the framework of fractional iteration of holomorphic self-maps, with the aim to study all continuous one-parameter semigroups in the unit disc (ππ‘)that commute with a given continuous one-parameter semigroup (ππ‘)in the sense that ππ‘β¦ππ =π π β¦ππ‘for all π‘,π β©Ύ0, see, for instance, [2]and[3]. In this paper, we tackle an intermediate situation, which has interesting implications in the discrete as well as in the fractional framework. Given πβπ΄( π»), a univalent self-map of the unit disc, the centralizer ξ(π) of πis defined as ξ(π) βΆ= {π β ξ(π»)βΆπβ¦π=πβ¦π}, ξ(π»)βΆ={πβΆπ»βπ»holomorphic injective}. The problem we are interested in is the following: Problem 1.1. Fix πβξ(π»)and a continuous one-parameter semigroup in the unit disc (ππ‘). Suppose π1βξ(π),withπ1β ππ½π». Does it necessarily follow that ππ‘βξ(π) for all π‘>0? If not, provide conditions on πand π1β and maybe on some finite number of ππ‘sβ under which the relation π1βξ(π) implies that the whole semigroup (ππ‘)is contained in ξ(π). First of all, it is worth mentioning that the assumption of πbeing univalent is completely natural and not restrictive. As we will see (Propositions 3.3 and A.1), univalence is a necessary condition for πto commute with a non-trivial continuous one-parameter semigroup. We would also like to underline that the context of this problem is really different from the other two mentioned above because of its lack of symmetry. In particular, for two continuous one-parameter semigroups in the unit disc, (ππ‘)and (ππ‘),wecanhaveπ1βξ(ππ‘)for all π‘>0and at the same time, π1βξ(ππ‘)for some π‘>0; see Example 3.1. The same example shows that, in general, the answer to the question in Problem 1.1 is negative. 14697750, 2025, 2, Downloaded from https://londmathsoc.onlinelibrary.wiley.com/doi/10.1112/jlms.70077 by Spanish Cochrane National Provision (Ministerio de Sanidad), Wiley Online Library on [29/05/2025]. See the Terms and Conditions (https://onlinelibrary.wiley.com/terms-and-conditions) on Wiley Online Library for rules of use; OA articles are governed by the applicable Creative Commons License
EXTENSION OF COMMUTATIVITY TO FRACTIONAL ITERATES 3of31 When πis elliptic, the above Problem 1.1 was implicitly solved by Cowen [4]. For the sake of completeness, at the end of the paper, we include a brief appendix with a very simple, and independent from Cowenβs work, solution for the elliptic case; see Proposition A.1. In the rest of the paper, we restrict ourselves to the non-elliptic case. In that non-elliptic case, it is not difficult to give a complete answer to Problem 1.1 in terms of the Koenigs function π»of the semigroup (ππ‘). Indeed, (ππ‘)βξ(π) if and only there exists πββsuch that π»β¦π=π»+π, see Proposition 3.3. The latter condition means exactly that π is affine with respect to π1(see Definition 2.6 and, in general, Section 2.4 for further details). Moreover, as a quite direct consequence of our results in [5], we can answer the question in Problem 1.1 positively if the semigroup (ππ‘)is hyperbolic or parabolic of zero hyperbolic step. However, when (ππ‘)is parabolic of positive hyperbolic step, giving any significant answer to Problem 1.1 that does not involve π»or the infinitesimal generator πΊ=1βπ» β²is really not that easy. In the following theorem, we summarize our positive answers to Problem 1.1 including the two ones described in the former paragraph (as items (a) and (b)). For the definition of isogonality at a boundary point involved in (e), see Section 8. Other useful definitions can be found in the preliminaries, see Section 2. Note that in our terminology every non-elliptic self-map is different from the identity map ππ½π». Furthermore, by a repelling fixed point, we mean a boundary regular fixed point different from the DenjoyβWolff point. Theorem 1.2. Let πβξ(π»)be non-elliptic and (ππ‘)be a continuous one-parameter semigroup in π»such that π1β ππ½π»and πβ¦π1=π 1β¦π. Assume that one of the following conditions holds: (a) πis affine with respect to π1, (b) π1is either hyperbolic or parabolic of zero hyperbolic step, (c) there exist πβ(0,+β)β§΅βsuch that ππβξ(π), (d) the limit lim π§βπ π(π§) β π§ π1(π§)βπ§, where πis the DenjoyβWolff point of π1(and hence also of π), exists unrestrictedly in π», (e) π1has a repelling fixed point at which πis isogonal, or (f) πand π1have a common boundary fixed point different from the DenjoyβWolff point. Then, ππ‘βξ(π) for all π‘>0. In general, conditions (b) and (d)β(f) in Theorem 1.2 are only sufficient ones. At the same time, it is worth remarking that these conditions involve πand π1, but do not depend on the knowledge of other elements of the semigroup (ππ‘), its Koenigs map, or infinitesimal generator. A priori, this is not the case for the necessary and sufficient condition (a), see Definition 2.6. However, in many cases, our next result allows to bypass this difficulty. 14697750, 2025, 2, Downloaded from https://londmathsoc.onlinelibrary.wiley.com/doi/10.1112/jlms.70077 by Spanish Cochrane National Provision (Ministerio de Sanidad), Wiley Online Library on [29/05/2025]. See the Terms and Conditions (https://onlinelibrary.wiley.com/terms-and-conditions) on Wiley Online Library for rules of use; OA articles are governed by the applicable Creative Commons License
4of31 CONTRERAS et al. Theorem 1.3. Let πβξ(π»)be parabolic of positive hyperbolic step, and let πβξ(π) β§΅ {ππ½π»}. Denote by πthe DenjoyβWolff point of πand let π
π,π(π§) βΆ= π(π§) β π§ π(π§) β π§,π§β π». Then, the following statements hold. (A) The sequence (π
π,π β¦πβ¦π)converges locally uniformly in π»to some function ππ,π βπ§ππ
(π»,β). (B) πis affine with respect to πif and only if the function ππ,π is constant in π». In fact, in such a case, ππ,π(π) = β limπ§βπ (π(π§)βπ§)β(π(π§)βπ§)for all πβπ». (C) Let (π, βπ,π§β¦π§+1),whereπ=ββΆ= {π§βΆ Im π§ > 0} or π=ββ, stand for the canonical holomorphic model of π.Thenππ,π β¦ββ1 πextends holomorphically to a map πΊβΆπβπβͺβwith πΊ(π€ + 1) = πΊ(π€) for all π€βπ. (D) The self-map g(π€) βΆ= π€ + πΊ(π€) is univalent in π,g(βπ(π»)) β βπ(π»),and π=β β1 πβ¦gβ¦βπ=β β1 πβ¦(βπ+π π,π). Coming back to Theorem 1.2, condition (f) is probably the most interesting and deepest result of the paper. In fact, according to the following theorem, this condition implies the stronger conclusion that πis an element of (ππ‘). We exclude from the statement hyperbolic automorphisms, because in this case, the result is essentially known: If πis a hyperbolic automorphism, then (ππ‘)is a hyperbolic one-parameter group and all the three conditions in Theorem 1.4 below hold, except that in condition (a) the words βfor some π‘0>0β have to be replaced by βfor some π‘0βββ; see, for example, [1, section 4.10] (see also [5]). Theorem 1.4. Let πβξ(π»)be a non-elliptic self-map different from a hyperbolic automorphism, and suppose that it has a boundary fixed point πdifferent from its DenjoyβWolff point. Let (ππ‘)be a continuous one-parameter semigroup such that π1βξ(π) β§΅ {ππ½π»}. Then the following conditions are equivalent: (a) π=π π‘0for some π‘0>0; (b) (ππ‘)βξ(π); (c) πis a boundary fixed point also for (ππ‘). Remark 1.5. If at least one of the self-maps πor π1β and hence both of themβ β are hyperbolic, then all the equivalent conditions (a), (b), and (c) in the above theorem are automatically satisfied. This follows from the fact that by [5, Propositions 6.6 and 6.9], in the hyperbolic case, we have ξ(π) = ξ(π1)={π π‘βΆπ‘β©Ύ0}. Remark 1.6. Let πand πbe two commuting holomorphic self-maps of π»and suppose that πhas a boundary fixed point π. It is known (see, e.g., [6]; see also Remark 3.2) that in general, πdoes not have to be a boundary fixed point for π, even if we additionally assume that πis regular, πis univalent, and πis embeddable in a continuous one-parameter semigroup. Therefore, the implications (b) β(c) and (b) β(a) in the theorem stated above can be regarded as an illustration β See [4, Corollary 4.1]. 14697750, 2025, 2, Downloaded from https://londmathsoc.onlinelibrary.wiley.com/doi/10.1112/jlms.70077 by Spanish Cochrane National Provision (Ministerio de Sanidad), Wiley Online Library on [29/05/2025]. See the Terms and Conditions (https://onlinelibrary.wiley.com/terms-and-conditions) on Wiley Online Library for rules of use; OA articles are governed by the applicable Creative Commons License
EXTENSION OF COMMUTATIVITY TO FRACTIONAL ITERATES 5of31 of a neat difference between commutativity with a self-map (and hence with all its natural iterates) and commutativity with all the fractional iterates. If a continuous one-parameter semigroup (ππ‘)is contained in the centralizer of a non-elliptic self-map π, then by Theorem 1.4 every boundary fixed point of πhas to be among boundary fixed points of (ππ‘). The converse is not true: We may have a continuous one-parameter semigroup (ππ‘)βξ(π) with many boundary fixed points, while πhas no boundary fixed point other than its DenjoyβWolff point; see, for example, Example 3.1 with (ππ‘)and (ππ‘)interchanged. This leads us to the following natural question (in which, in fact, we impose some weaker assumptions). Problem 1.7. Let πβξ(π»)be a non-elliptic self-map different from a hyperbolic automorphism and let (ππ‘)be a continuous one-parameter semigroup such that π1βξ(π) β§΅ {ππ½π»}. Further, suppose πβ{π π‘βΆπ‘β©Ύ0}. Is there any relationship between πand the boundary fixed points of (ππ‘) in this case? A natural way to attack this problem is through the concept of petal of a continuous oneparameter semigroup, concept intimately linked to the notion of boundary regular fixed point of such a semigroup. We refer the reader to Section 5for more details, or to the monograph [7, section 13] for a detailed exposition, which includes a number of related results. It is worth mentioning that this theory of petals plays also an important role in the proof of Theorem 1.4. We begin by showing that, as a general fact, πalways maps petals into petals and in a rather specific way. The degenerate case of (ππ‘)being a one-parameter group is excluded from the statement of the theorem below; it is covered separately, see Remark 7.1 in Section 7. Theorem 1.8. Let πβξ(π»)be non-elliptic and let (ππ‘) β π ππ(π»)be a continuous one-parameter semigroup in π»with DenjoyβWolff point πβππ»such that π1βξ(π) β§΅ {ππ½π»}. (A) Assume that Ξis a hyperbolic petal of (ππ‘)with associated boundary repelling fixed point πβ ππ». Then, one and only one of the following three statements holds: (i) π(Ξ) = Ξ. In this case, there exists π‘0>0such that π=π π‘0and, in particular, πis a repelling fixed point of π. (ii) Ξβ©π(Ξ)=β
and there exists a hyperbolic petal Ξβ²of (ππ‘)with associated repelling fixed point πβ²such that π(Ξ) β Ξβ²and β lim π§βπ π(π§)=π β². (iii) Ξβ©π(Ξ)=β
and there exists a parabolic petal Ξβ²of (ππ‘)such that π(Ξ) β Ξβ²and β lim π§βπ π(π§) = π.Inthiscase,πis an irregular contact point for π. (B) Assume that Ξis a parabolic petal of (ππ‘). Then the following two statements hold: (a) π(Ξ) β Ξ; (b) π(Ξ) = Ξ if and only if π=π π‘0for some π‘0>0. In the hyperbolic case, by the reason mentioned in Remark 1.5, only alternative (i) may occur, and moreover, (B) becomes trivial because a hyperbolic semigroup cannot have parabolic petals. In the parabolic case, based on Theorem 1.8, we are then able to give a quite complete answer to Problem 1.7 as follows. We again exclude from consideration the case (ππ‘) β π ππ(π»), in which the result, with some obvious modifications, holds trivially. 14697750, 2025, 2, Downloaded from https://londmathsoc.onlinelibrary.wiley.com/doi/10.1112/jlms.70077 by Spanish Cochrane National Provision (Ministerio de Sanidad), Wiley Online Library on [29/05/2025]. See the Terms and Conditions (https://onlinelibrary.wiley.com/terms-and-conditions) on Wiley Online Library for rules of use; OA articles are governed by the applicable Creative Commons License
6of31 CONTRERAS et al. Theorem 1.9. Let πβξ(π»)be a non-elliptic self-map with DenjoyβWolff point πβππ»and let (ππ‘) β π ππ(π»)be a continuous one-parameter semigroup in π»such that π1βξ(π) β§΅ {ππ½π»}. Suppose that πis not an element of (ππ‘). Then the following statements hold. (I) Both πand (ππ‘)are parabolic. Moreover, (ππ‘)has at most one parabolic petal. (II) Suppose (ππ‘)has a parabolic petal Ξβ. Then for each hyperbolic petal Ξof (ππ‘),thereexista finite collection Ξ1,Ξ 2,β¦, Ξ πof pairwise disjoint hyperbolic petals of (ππ‘)such that Ξ1=Ξ, π(Ξ π)βΞ π+1, π=1,β¦,πβ1, π(Ξ π)βΞ β. Moreover, π(ππ)=π π+1, π=1,β¦,πβ1, π(π π)=π, where ππ(π =1,β¦,π)stands for the repelling fixed point associated with Ξπ. (III) Suppose that (ππ‘)has no parabolic petal. Then for each hyperbolic petal Ξof (ππ‘), there exists asequence(Ξπ)of pairwise disjoint hyperbolic petals of (ππ‘)such that Ξ1=Ξ, π(Ξ π)βΞ π+1,πββ. Moreover, π(ππ)=π π+1,πββ,and lim πββ ππ=π, where ππ(π β β)stands for the repelling fixed point associated with Ξπ. Remark 1.10. The above two theorems imply that every repelling fixed point πof πβΆ=π 1is a contact point for πand that π(π) is also a boundary regular fixed point of π.Moreover,ifπ(π) β π, then the (forward) orbit of πwith respect to π(extended to a.e. point of ππ»by angular limits) either hits the DenjoyβWolff point within finite time, or it consists of pairwise distinct repelling fixed points of π, but tends to the DenjoyβWolff point in the limit. In part, this resembles the situation with two general commuting holomorphic self-maps π,π β π§ππ
(π»)studiedbyBracci [6]. In this general case, πcan have a repelling cycle consisting of repelling fixed points of π,but this possibility is ruled out if πis univalent and non-elliptic, see [6, Proposition 5.2]. At the same time, the results established in [6] do not seem to exclude some other situations not occurring in our case, such as a possibility that the orbit of πhits within finite time a common fixed point of π and πdifferent from their DenjoyβWolff point. Moreover, in contrast to the context of Theorem 1.9, it is not clear in general whether any two orbits starting from different repelling fixed points of π necessarily fall into the same category. Theorems 1.8 and 1.9 are proved in Section 7. Further, in Section 8, we consider the last two alternatives given in Theorem 1.8(A) and analyze in which case equality π(Ξ) = Ξβ²occurs. This will be used, along with several other results, in the proof of Theorem 1.2 given in Section 9. Finally, in Section 10, based on our findings, we substantially improve a result by Elin et al. [2, section 5] on sufficient conditions for two parabolic continuous one-parameter semigroups (ππ‘)and (ππ‘)to commute, given that π1β¦π1=π 1β¦π1. 14697750, 2025, 2, Downloaded from https://londmathsoc.onlinelibrary.wiley.com/doi/10.1112/jlms.70077 by Spanish Cochrane National Provision (Ministerio de Sanidad), Wiley Online Library on [29/05/2025]. See the Terms and Conditions (https://onlinelibrary.wiley.com/terms-and-conditions) on Wiley Online Library for rules of use; OA articles are governed by the applicable Creative Commons License
EXTENSION OF COMMUTATIVITY TO FRACTIONAL ITERATES 7of31 The part of the paper preceding Sections 7β10, the content of which we have already described, is organized as follows. In Section 2, we recall some preliminaries from holomorphic dynamics that will be needed to follow the paper. In Section 3, we present in detail an example related to Problem 1.1 and already mentioned above. In the same section, we establish a characterization for holomorphic self-maps πcommuting with a non-elliptic semigroup (ππ‘)in terms of the Koenigs function of (ππ‘). In the next section, Section 4, we prove Theorem 1.3, which yields another characterization in terms of the boundary behaviour of π1and πalong forward orbits under the discrete dynamics of π1. Section 5contains a brief survey on the theory of petals and some lemmata relating commutativity to petals, which we use in the proof of Theorem 1.4 given in Section 6,aswell as in the proof of Theorems 1.8 and 1.9. 2 NOTATION AND PRELIMINARIES Below we introduce some notation and basic theory used further in the paper. For more details and for the proofs of the results presented in this section, we refer the interested readers to the recent monographs [1, 7]. 2.1 Notation As usual, we denote the unit disc by π»βΆ= {π§ β ββΆ|π§|<1},andπ»ββΆ= π»β§΅{0}.WewriteββΆ= {π€ β ββΆImπ€>0}for the upper half-plane and βRe βΆ= {π§ β ββΆReπ€>0}for the right halfplane. Furthermore, denote by π§ππ
(π·, πΈ) the class of all holomorphic mappings of a domain π·ββ into a set πΈββ,andletξ(π·, πΈ) stand for the class of all univalent (i.e., injective holomorphic) mappings from π·to πΈ.Asusual,weendowπ§ππ
(π·, πΈ) and ξ(π·, πΈ) with the topology of locally uniform convergence. In case πΈ=π·,wewillwriteπ§ππ
(π·) and ξ(π·) instead of π§ππ
(π·,π·) and ξ(π·, π·), respectively. For a self-map πβΆπ·βπ·of a domain π·ββand πββ,we denote by πβ¦πthe πth iterate of π, and let πβ¦0βΆ= ππ½π·.Moreover,ifπis an automorphism of π·, then for every πββ, we denote by πβ¦βπ the πth iterate of πβ1. 2.2 Holomorphic self-maps of the unit disc The study of the dynamics of an arbitrary holomorphic self-map πof the unit disc π»is a classical and well-established branch of Complex Analysis. An important role is played by the fixed points, all of which β except for at most one β lie on the boundary and hence should be understood in the sense of angular limits: πβπ π»is a boundary fixed point of πβπ§ππ
(π»)if π(π) βΆ= β limπ§βπ π(π§) exists and coincides with π. It is known that the angular derivative πβ²(π) exists at every boundary fixed point π, but it can be infinite. In this latter case, πis referred to as a super-repelling fixed point; otherwise, that is, when πβ²(π) is finite, it is in fact a positive real number and the boundary fixed point πis said to be regular (BRFP for short). The central result in the area is the DenjoyβWolff Theorem, which states that if πis different from an elliptic automorphism (i.e., not an automorphism of π»possessing a fixed point in π»), then the sequence of the iterates (πβ¦π)converges locally uniformly in π»to a certain point πβπ».This 14697750, 2025, 2, Downloaded from https://londmathsoc.onlinelibrary.wiley.com/doi/10.1112/jlms.70077 by Spanish Cochrane National Provision (Ministerio de Sanidad), Wiley Online Library on [29/05/2025]. See the Terms and Conditions (https://onlinelibrary.wiley.com/terms-and-conditions) on Wiley Online Library for rules of use; OA articles are governed by the applicable Creative Commons License
8of31 CONTRERAS et al. point is called the DenjoyβWolff point of π.Moreover,ifπβππ», it is the unique boundary fixed point at which the angular derivative πβ²(π) is finite and belongs to (0,1]. In particular, for every BRFP πdifferent from the DenjoyβWolff point π,wehaveπβ²(π) β (1, +β). By this reason such points are referred to as repelling fixed points of π. According to the position of the DenjoyβWolff point πand to the value of the multiplier πβ²(π), holomorphic self-maps πβπ§ππ
( π»)different from elliptic automorphisms are divided into three categories. Namely, πis called: (a) elliptic if πβπ», (b) hyperbolic if πβπ π»and πβ²(π) < 1,and (c) parabolic if πβπ π»such that πβ²(π) = 1. The identity mapping ππ½π»and all elliptic automorphisms of π»are conventionally included in the category (a) of elliptic self-maps. Similarly, for an elliptic automorphism different from ππ½π»,its DenjoyβWolff point is defined to be its unique fixed point in π». Parabolic self-maps can have very different properties depending on the so-called hyperbolic step. Denote by ππ»the hyperbolic distance in π»,andletπβπ§ππ
(π»)be non-elliptic. Thanks to the SchwarzβPick Lemma, for the orbit (π§π)βΆ= (πβ¦π(π§0))of any point π§0βπ», there exists a finite limit π(π§0)βΆ=lim πβ+β ππ»(π§π,π§ π+1).Itisknown,see,forexample,[1, Corollary 4.6.9], that either π(π§0)>0for all π§0βπ»,orπβ‘0in π». The self-map πis said to be of positive or of zero hyperbolic step depending on whether the former or the latter alternative occurs. If πis hyperbolic, then it is always of positive hyperbolic step. However, there exist parabolic self-maps of zero as well as of positive hyperbolic step. 2.3 Holomorphic models for univalent self-maps An indispensable role in our study is played by the concept of a holomorphic model, which goes back to Pommerenke [8], Baker and Pommerenke [9], and Cowen [10] and which is discussed below for the special case of a univalent self-map. The terminology we use is mainly borrowed from [11]. Definition 2.1. Aholomorphic model of πβξ(π»)is any triple ξΉβΆ=(π,β,πΌ), where πis a Riemann surface, πΌis an automorphism of π,andβis a univalent map from π»into πsatisfying the following two conditions: (HM1) ββ¦π=πΌβ¦β,and (HM2) π=βπβ©Ύ0πΌβ¦βπ(β(π»)). The Riemann surface πis called the base space, and the map βis called the intertwining map of the holomorphic model ξΉ. Every πβξ(π»)β§΅{ππ½ π»}admits an essentially unique holomorphic model. More precisely, the following fundamental theorem holds. Theorem 2.2 [11, Theorem 1.1]. Every πβξ(π»)admits a holomorphic model. Moreover such a model is unique up to a model isomorphism; that is, if (π1,β 1,πΌ 1)and (π2,β 2,πΌ 2)are holomorphic models for π, then there exists a biholomorphic map πof π1onto π2such that 14697750, 2025, 2, Downloaded from https://londmathsoc.onlinelibrary.wiley.com/doi/10.1112/jlms.70077 by Spanish Cochrane National Provision (Ministerio de Sanidad), Wiley Online Library on [29/05/2025]. See the Terms and Conditions (https://onlinelibrary.wiley.com/terms-and-conditions) on Wiley Online Library for rules of use; OA articles are governed by the applicable Creative Commons License
EXTENSION OF COMMUTATIVITY TO FRACTIONAL ITERATES 9of31 β2=πβ¦β1,πΌ 2=πβ¦πΌ1β¦πβ1. The type of a univalent self-map (elliptic, hyperbolic, or parabolic) is reflected in, and actually can be fully determined from the kind of holomorphic model πadmits. For an open interval πΌββ, we define ππΌβΆ= βΓπΌ={π₯+ππ¦βΆπ₯ββ,π¦βπΌ}. Theorem 2.3 ([10], see also [11]). Let πβξ(π»)β§΅{ππ½ π»}. The following statements hold. (1) πis an elliptic automorphism with multiplier πβπ π»β§΅{1}if and only if πadmits a holomorphic modeloftheformξΉπβΆ= (π»,β,π§β¦ππ§),whereβ β π ππ(π»). (2) πis an elliptic self-map with multiplier πβπ»β(and hence it is not an automorphism) if and only if πadmits a holomorphic model of the form ξΉπβΆ= (β,β,π§β¦ππ§). (3) πis a hyperbolic self-map with multiplier πβ(0,1)if and only if πadmits a holomorphic model of the form ξΉπβΆ= (ππΌ,β,π§β¦π§+1),whereπΌ=(π,π)is a bounded open interval of length πβπ=πβ|log π|. (4) πis a parabolic self-map of positive hyperbolic step if and only if πadmits a holomorphic model of the form ξΉπβΆ= (ππΌ,β,π§β¦π§+1),whereπΌis an open unbounded interval different from the whole β. (5) πis a parabolic self-map of zero hyperbolic step if and only if πadmits a holomorphic model of the form ξΉπβΆ= (β,β,π§β¦π§+1). Remark 2.4. In the above theorem, we may assume the following: - incase(1),ββ²(π) > 0, where πis the DenjoyβWolff point of π; - incase(2),ββ²(π)=1, where πis the DenjoyβWolff point of π; - in cases (3) and (5), β(0) = 0; - incase(4),Reβ(0) = 0 and ππΌ=π (0,+β) =βor ππΌ=π (ββ,0) =ββ. Using the uniqueness part of Theorem 2.2, one can show (see, e.g., [1, Corollary 4.6.12] for details) that the above assumptions play the role of a normalization under which the holomorphic model ξΉπfor a given πβξ(π»)β§΅{ππ½ π»}is unique. Note that the normalization for cases (3) and (5) would also work in case (4), but we prefer to use another normalization, so that for parabolic self-maps of positive hyperbolic step, the base space ππΌof ξΉπcoincides with βor ββ. Moreover, replacing, if necessary, πwith π§β¦π( ξ π§) we may assume ππΌ=β. Definition 2.5. The unique holomorphic model ξΉπof a self-map πβξ(π»)β§΅{ππ½ π»}defined in Theorem 2.3 and normalized as in Remark 2.4 is called the canonical (holomorphic) model for π. The intertwining map βof the canonical model ξΉπis called the Koenigs function,andΞ©βΆ=β(π») is called the Koenigs domain of π. 2.4 Commuting holomorphic self-maps It is clear that if two holomorphic self-maps π,π β π§ππ
(π»)β§΅{ππ½ π»}commute, that is, πβ¦π=πβ¦π, and if one of them is elliptic, then the other is also elliptic and they share the DenjoyβWolff point. The situation is not so evident when we consider non-elliptic self-maps. In 1973, Behan [12], see 14697750, 2025, 2, Downloaded from https://londmathsoc.onlinelibrary.wiley.com/doi/10.1112/jlms.70077 by Spanish Cochrane National Provision (Ministerio de Sanidad), Wiley Online Library on [29/05/2025]. See the Terms and Conditions (https://onlinelibrary.wiley.com/terms-and-conditions) on Wiley Online Library for rules of use; OA articles are governed by the applicable Creative Commons License
16 of 31 CONTRERAS et al. Following the conventional terminology in dynamical systems, we call the above BRFP πthe πΌpoint of the corresponding hyperbolic petal Ξ. In case of a parabolic petal, by its πΌ-point we mean the DenjoyβWolff point π. In the rest of this section, we suppose πβξ(π»)is a non-elliptic self-map with DenjoyβWolff point πβπ π», that πis different from a hyperbolic automorphism, and that (ππ‘)is a continuous one-parameter semigroup of π»satisfying ππ½π»β π1βξ(π). Lemma 5.2. In the above assumptions, π(ξ)βξ,whereξstands for the backward invariant set of (ππ‘). In particular, the image π(Ξ) of any petal Ξof (ππ‘)is contained again in some petal of (ππ‘) (which may coincide with Ξ). Proof. Denote by βthe Koenigs function of (ππ‘). Using Abelβs equation (2.2), and taking into account that βis univalent, it is easy to see that β(ξ)=β π‘β©Ύ0 β(π»)+π‘ = β πββ β(π»)+π. (5.1) The second equality holds because, again by (2.2), β(π»)+π‘ 2ββ(π»)+π‘ 1whenever π‘2β©Ύπ‘1β©Ύ0. By the hypothesis πβξ(π1). Therefore, by [5, Theorem 3.4], there exists a univalent holomorphic map gβΆβ( π»)ββ(π»)such that ββ¦π=gβ¦πand g(π€ + 1) = g(π€) + 1 for any π€ββ(π»). Therefore, β(π(ξ))=g(β(ξ))=g(β πββ β(π»)+π)=β πββ g(β(π»)+π )=β πββ g(β(π»))+π. (5.2) Combining the fact that g(β(π»))ββ(π»)with the equalities (5.1)and(5.2), we see that β(π(ξ))ββ(ξ).Sinceβis univalent, this proves the inclusion π(ξ)βξ. Finally, the statement regarding the petals follows immediately from this inclusion because the map πis continuous and open. β‘ Note that the petals of (ππ‘)are pairwise disjoint. Therefore, in Lemma 5.2 proved above, the petal Ξβ²that contains π(Ξ) is unique. Lemma 5.3. Let Ξβ²be the petal of (ππ‘)defined as above, that is, π(Ξ) β Ξβ².Then π(π) βΆ= β lim π§βπ π(π§) = πβ², where πand πβ²stand for the πΌ-points of the petals Ξand Ξβ², respectively. Proof. Fix any point π§0βΞ. Then according [7, Proposition 13.4.2], there is a unique regular backward orbit (π§π‘)βΞof (ππ‘)starting from π§0and converging to πas π‘β+β. More precisely, for each π‘β©Ύ0there is a unique point π§π‘βΞsuch that ππ‘(π§π‘)=π§ 0and the map [0, +β) β π‘ β¦ π§π‘is continuous and injective, with limπ‘β+β π§π‘=πand sup π‘β©Ύ0 ππ»(π§π‘,π§ π‘+1) < +β. (5.3) 14697750, 2025, 2, Downloaded from https://londmathsoc.onlinelibrary.wiley.com/doi/10.1112/jlms.70077 by Spanish Cochrane National Provision (Ministerio de Sanidad), Wiley Online Library on [29/05/2025]. See the Terms and Conditions (https://onlinelibrary.wiley.com/terms-and-conditions) on Wiley Online Library for rules of use; OA articles are governed by the applicable Creative Commons License
EXTENSION OF COMMUTATIVITY TO FRACTIONAL ITERATES 17 of 31 Since πcommutes with π1and hence with ππfor any πββ,wehave ππ(π(π§π))=π (ππ(π§π))=π(π§ 0). Taking into account that π§πβΞand hence π(π§π)βΞ β²for all πβββͺ{0}, we see that the points π€πlie on the backward orbit of π€0βΆ= π(π§0)βΞ β². Therefore, π€πβπ β²as πβ+β. Thus, we see that π(π§π)βπ β²for a sequence (π§π)converging to πand such that the hyperbolic distance ππ»(π§π,π§ π+1), according to (5.3), is bounded. This leads, see, for example, [11, Theorem 1.4], to the desired conclusion that πhas angular limit at πequal to πβ².β‘ Lemma 5.4. If Ξis a parabolic petal of (ππ‘),thenπ(Ξ) β Ξ. Proof. By the definition of a parabolic petal, the πΌ-point πof the petal Ξcoincides with the Denjoyβ Wolff point πof the semigroup (ππ‘), which in turn coincides with the DenjoyβWolff point of π. Therefore, π(π) = π. According to Lemma 5.3, it follows that the petal Ξβ²containing π(Ξ) must be also parabolic. By [7, Theorem 13.5.7], (ππ‘)has at most two parabolic petals. If it has exactly one parabolic petal, then we are done. If there are two distinct parabolic petals, then (again according [7,Theorem 13.5.7]) the images ππ,π=1,2, of the two parabolic petals with respect to the Koenigs map βof (ππ‘)are of the form π1={π€βΆImπ€<π}and π2={π€βΆImπ€>π}for some πβ©Ύπ.As a consequence, the semigroup (ππ‘), and hence the self-map π1, are of zero hyperbolic step. Since πβξ(π1),by[5, Proposition 4.3], πis affine with respect to π1, that is, ββ¦π=β+πfor a suitable πββ. It follows that if Ξand Ξβ²were two different parabolic petals, then the translation by πor βπ would map π1into π2, which is clearly impossible. Thus, π(Ξ) β Ξβ²=Ξ.β‘ Corollary 5.5. In the notation of Lemma 5.3,π(Ξ) β Ξ if and only if π(π)=π. Proof. If Ξis a hyperbolic petal, then the corollary follows from Lemma 5.2 and the fact that any two distinct petals have distinct πΌ-points unless both petals are parabolic. So suppose Ξis a parabolic petal. Then π(Ξ) β Ξ by Lemma 5.4. Moreover, as we have seen in the proof of Lemma 5.4,π(π) = π because in this case, π=πis the DenjoyβWolff point for (ππ‘) and hence also for π. These two observations complete the proof. β‘ Lemma 5.6. Suppose thatπis not an element of (ππ‘).Then(ππ‘)can have at most one parabolic petal. Proof. Suppose that (ππ‘)has two distinct parabolic petals. Then, as in the proof of Lemma 5.4,we see that ββ¦π=β+π, where the constant πmust be real because each of the half-planes π1and π2 are mapped by the translation π€β¦π€+πinto itself. Moreover, β(π»)+π=β (π(π»))ββ(π»)and hence, by [5, Theorem 3.1 (B)], πβ©Ύ0. It follows that π=π π, which contradicts the hypothesis. β‘ We conclude this section with a lemma, which is definitely known for specialists and holds also for non-univalent self-maps, but lacking a reference we prefer to include a short proof making use of commutativity. Lemma 5.7. Let π1,π 2βξ(π»)be such that πβ¦π 1=π β¦π 2for some πββ.Ifπ1is non-elliptic, then π2=π 1. 14697750, 2025, 2, Downloaded from https://londmathsoc.onlinelibrary.wiley.com/doi/10.1112/jlms.70077 by Spanish Cochrane National Provision (Ministerio de Sanidad), Wiley Online Library on [29/05/2025]. See the Terms and Conditions (https://onlinelibrary.wiley.com/terms-and-conditions) on Wiley Online Library for rules of use; OA articles are governed by the applicable Creative Commons License
18 of 31 CONTRERAS et al. Proof. Since π1is univalent and non-elliptic, so is π3βΆ= πβ¦π 1.Let(π,β,π§β¦π§+1) stand for the canonical holomorphic model of π3. Clearly, both π1and π2commute with π3. Therefore, see, for example, [5, Theorem 3.4], ππ=β β1β¦gπβ¦β,π=1,2, with certain gπβξ(π) satisfying gπ(π€ + 1) = gπ(π€)+1for all π€βπ. The equality πβ¦π 2=π β¦π 1=π 3implies gβ¦π π(π€) = π€ + 1, π = 1, 2, for all π€βπ. In particular, g1,g2β π ππ(π). Using the one-to-one correspondence between the automorphisms of πand those of π»induced by a conformal mapping between πand π»and taking into account that the iterates of any π β π ππ(π»)have the same fixed points as π, it is not difficult to see that both g1 and g2are translations along β.Sincegβ¦π 1=gβ¦π 2, it follows that g1=g2.Thus,π2=π 1.β‘ 6PROOF OF THEOREM 1.4 Recall that by the hypothesis πβξ(π»)is non-elliptic and different from a hyperbolic automorphism and that π1βξ(π) β§΅ {ππ½π»}. In particular, it follows that the semigroup (ππ‘)is non-trivial and non-elliptic. Moreover, by Behanβs Theorem, πand (ππ‘)have the same DenjoyβWolff point π. Denote by (π,π»,(π§β¦π§+π‘) π‘β©Ύ0)the canonical holomorphic model of (ππ‘). πππππ ππ (a) β(b) is completely trivial. πππππ ππ (b) β(c). Since (ππ‘)βξ(π),byProposition3.3 we have π»β¦π=π»+πfor some πββ. The Koenigs function π»has angular limits at all points on ππ», possibly except for the Denjoyβ Wolff point, see, for example, [7, Corollary 11.1.7]. Let us check that π»(π) βΆ= β limπ§βπ π»(π§) = β. Suppose π»(π) β β. Then π»(π(ππ))=π»(ππ)+πβπ»(π)+πas πβ1 β. By the hypothesis, π is a boundary fixed point of π, that is, π(ππ) β π as πβ1 β. According to the LehtoβVirtanenβs Theorem (see, e.g., [7, Theorem 3.3.1]) it follows that π»(π) = lim πβ1βπ»(π(ππ))=π»(π)+π and hence π=0, that is, π=ππ½ π». The latter contradicts the hypothesis. Thus, π»(π) = β and, as a consequence, see, for example, [7, Proposition 13.6.1], πis a boundary fixed point of (ππ‘). πππππ ππ (c) β(a). By an old result of Heins [20, Lemma 2.1], π1cannot be a hyperbolic automorphism because it commutes with π, which is not a hyperbolic automorphism. Moreover, π1 is not a parabolic automorphism because by (c), it has a boundary fixed point πdifferent from its DenjoyβWolff point. It follows that the non-elliptic semigroup (ππ‘)cannot be extended to a group. According to the regularity of π, we distinguish two cases. Case I: πis a repelling fixed point of (ππ‘).LetΞbe the hyperbolic petal of (ππ‘)associated with π, as explained in Section 5.Since(ππ‘)is not a group, according to [7, Theorems 13.2.7, 13.4.12], there exists a univalent map gfrom π»onto Ξsuch that the formula Λ ππ‘βΆ= gβ1β¦ππ‘β¦g,π‘β©Ύ0, defines a hyperbolic group (Λ ππ‘)in π»with DenjoyβWolff point at βπ. By Corollary 5.5,π(Ξ) β Ξ. Therefore, Λ πβΆ=gβ1β¦πβ¦gis an element of ξ(π»).Moreover,π1βξ(π) implies Λ πβξ(Λ π1).SinceΛ π1is a hyperbolic automorphism and by [5, Remark 6.4], we conclude that there exists π‘0>0such that either Λ π=Λ ππ‘0or Λ π=Λ πβ1 π‘0. If the latter alternative would occur, then (ππ‘0β¦π)|Ξ=ππ½ Ξand hence, by the identity principle, ππ‘0β¦π=ππ½ π», which is impossible because π1β π ππ(π»). Therefore, Λ π=Λ ππ‘0. It immediately follows that ππ‘0|Ξ=π|Ξand hence, again by the identity principle, ππ‘0=πas desired. 14697750, 2025, 2, Downloaded from https://londmathsoc.onlinelibrary.wiley.com/doi/10.1112/jlms.70077 by Spanish Cochrane National Provision (Ministerio de Sanidad), Wiley Online Library on [29/05/2025]. See the Terms and Conditions (https://onlinelibrary.wiley.com/terms-and-conditions) on Wiley Online Library for rules of use; OA articles are governed by the applicable Creative Commons License
EXTENSION OF COMMUTATIVITY TO FRACTIONAL ITERATES 19 of 31 Case II: πis a super-repelling fixed point of (ππ‘). According to [7, Corollary 13.6.7], we know that there is πββsuch that lim π§βπ Imπ»(π§)=π and lim π§βπ Re π»(π§) = ββ. (6.1) Note that both limits are unrestricted. Taking into account that πis a boundary fixed point of π, we therefore have π= lim πβ1βIm π»(π(ππ)). (6.2) If π1is hyperbolic or parabolic of zero hyperbolic step, then by [5, Proposition 4.3], πβξ(π1) implies π»β¦π=π»+πfor a suitable πββand, in view of (6.1)and(6.2), it follows that Im π = lim πβ1β(Im π»(π(ππ)) β Im π»(ππ))=πβπ=0. Therefore, πis a real number. Certainly πβ 0because πβ ππ½π».Moreover,ifπwere negative, we would obtain that πβπβ¦π=ππ½ π», which is impossible because ππ‘β π ππ(π»)for any π‘>0. Hence, π>0anditfollowsthatπ=π π‘0with π‘0βΆ= π. This completes the proof in the case when (ππ‘)is hyperbolic or parabolic of zero hyperbolic step. Fromnowonwesupposethatπ1is parabolic of positive hyperbolic step. For the sake of clarity, we will also assume that the base space for (ππ‘)is π=β. The proof in the other case, that is, for π=β β, is completely similar. Then the fact that πβξ(π1)implies, by [5, Proposition 7.2], that there exists πΉβπ§ππ
( π»,ββͺβ) such that π»β¦π(π§)=π»(π§)+πΉ (π2πππ»(π§))for all π§βπ». We notice that the function π€β¦π€+πΉ(π 2πππ€)is univalent in β, a fact that will be used later. By (6.1)and(6.2), we have lim πβ1βIm πΉ(π2πππ»(ππ))= lim πβ1β(Im π»(π(ππ)) β Im π»(ππ))=πβπ=0. (6.3) By (6.1), for any π=π 2πππ βππ»there exist a natural π=π(π)and a sequence (ππ)=(π π(π)) in (0,1) convergent to 1 such that Reπ»(πππ)=πβπfor all πβ©Ύπ. For this sequence (ππ),wehave lim πββ π2πππ»(πππ) =lim πββ π2ππ(πβπ)πβ2π Im π»(πππ) =ππ β2ππ.(6.4) Since π»(π»)ββ,wehaveπβ©Ύ0. Below we consider separately the cases π>0and π=0. Subcase II.a: π>0. In this case, πβ2ππ β (0, 1).LetπΆπbe the circle of radius πβ2ππ centred at the origin. Taking into account that πΆπβπ»and using (6.3)and(6.4), we deduce that Im πΉ(π§) = 0 for all π§βπΆ π. By the maximum principle for harmonic functions and the identity principle for holomorphic functions, it follows that πΉβ‘πfor some constant πββ. Hence, π»β¦π=π»+π.By essentially the same argument as in the case of zero hyperbolic case, we see that π>0and therefore, π=π π‘0with π‘0βΆ= π, as desired. Subcase II.b: π=0.SinceπΉβπ§ππ
( π»,ββͺβ), we have Im πΉ is a non-negative harmonic function in the unit disc. By [21, Corollary on p. 38], there exists πΈβπ»of measure zero such that 14697750, 2025, 2, Downloaded from https://londmathsoc.onlinelibrary.wiley.com/doi/10.1112/jlms.70077 by Spanish Cochrane National Provision (Ministerio de Sanidad), Wiley Online Library on [29/05/2025]. See the Terms and Conditions (https://onlinelibrary.wiley.com/terms-and-conditions) on Wiley Online Library for rules of use; OA articles are governed by the applicable Creative Commons License
20 of 31 CONTRERAS et al. the angular limit β lim π§βπ Im πΉ(π§) exists for every πβππ»β§΅πΈ.By(6.4), for every πβππ», the sequence (π2πππ»(ππ(π)π))converges non-tangentially to π. Therefore, by (6.3), we deduce that β lim π§βπ Im πΉ(π§) = 0, for all π β ππ»β§΅πΈ. (6.5) Now, let us consider the function in π§ππ
(β,β)given by πΊ(π€) βΆ= πΉ(π2πππ€), π€ β β. Similarly to the case π>0, it suffices to show that πΊis a real constant. Consider g(π€) βΆ= π€ + πΊ(π€). This function is a univalent holomorphic self-map of βwith gβ²(β) βΆ= β limπ€ββ g(π€)βπ€ = 1. Therefore, gadmits the following representation, see, for example, [22, Chapter V.4: (V.42), (V.44) (V.45)], g(π€) = π + π€ + β«β(1 πβπ€βπ 1+π 2)dπ(π), π€ β β,with a constant πββand a non-negative Borel measure πon βgiven by π([π, π]) = lim πβ0+ 1 πβ«π π Im g(π + ππ) dπ for any π,π β β,π<π, possibly except for a countably many points at which πhas atoms. Taking into account that by (6.5), limπβ0+Im g(π + ππ) = 0 for a.e. πββ, it remains to see that Im gis bounded in ββ§΅β1, where for πββwe denote by βπthe half-plane {π€βΆ Im π€ > π}. Note that gβ²(β) β 0and hence gis conformal at βwith g(β) = β. Recall that gis univalent in β. Then by a standard argument, see, for example, [23, pp. 303β304], we get that g(β1)βπ π
βΆ= {π€ βΆ arg π€ β (πβ2, 3πβ2), |π€|>π
} for some π
>0.Letπ
0βΆ= max{1, π
}. Since g(π€ + 1) = g(π€)+1for all π€ββ, it actually follows that βπ
0ββπββ€ππ
0+πβg(β1). Therefore, g(ββ§΅β1)=g(β)β§΅g(β1)βββ§΅βπ
0,andwearedone. β‘ 7 PETALS AND COMMUTATIVITY II. PROOF OF THEOREMS 1.8 AND 1.9 Before we start proving Theorem 1.8, let us analyze (in the remark below) the case (ππ‘) β π ππ(π»), which in the statement of the theorem is excluded from consideration. As it has been already mentioned in Section 2.5, in this case, we can (and do) extend (ππ‘)to a group by setting ππ‘βΆ= (πβπ‘)β1 for all π‘<0. Remark 7.1. Suppose (ππ‘) β π ππ(π»)is a continuous one-parameter group in π»with π1β ππ½π», and let πβξ(π»)be a non-elliptic self-map commuting with π1. Clearly, (ππ‘)cannonbeelliptic. The whole unit disc π»is the unique petal of (ππ‘), which is hyperbolic or parabolic depending on whether (ππ‘)is a hyperbolic or a parabolic group. Moreover, if (ππ‘)is hyperbolic, then by [20, Lemma 2.1], πis a hyperbolic automorphism having the same fixed points as (ππ‘), and hence π=π π‘0for some π‘0ββ.If(ππ‘)is parabolic, then πis not necessarily an automorphism of π»,but it has to be a parabolic self-map with the same DenjoyβWolff point as π1; see, for example, [1, Proposition 2.6.11]. In this case, π β π ππ(π»)ifandonlyifπ=π π‘0for some π‘0ββ. Proof of Theorem 1.8. First of all, since π1is not a hyperbolic automorphism (otherwise, we would have (ππ‘) β π ππ(π»)), by [20, Lemma 2.1], πcannot be a hyperbolic automorphism either. Therefore, by Behanβs Theorem, see [12]or[1, Theorem 4.10.3], the DenjoyβWolff point of π 14697750, 2025, 2, Downloaded from https://londmathsoc.onlinelibrary.wiley.com/doi/10.1112/jlms.70077 by Spanish Cochrane National Provision (Ministerio de Sanidad), Wiley Online Library on [29/05/2025]. See the Terms and Conditions (https://onlinelibrary.wiley.com/terms-and-conditions) on Wiley Online Library for rules of use; OA articles are governed by the applicable Creative Commons License
EXTENSION OF COMMUTATIVITY TO FRACTIONAL ITERATES 21 of 31 coincides with the DenjoyβWolff point πof the semigroup (ππ‘). In particular, it follows that (ππ‘) is non-elliptic. Proof of (A). By Lemma 5.2, there exists a petal Ξβ²of (ππ‘)such that π(Ξ) β Ξβ².Being connected components of ξβ¦, petals are pairwise disjoint. Therefore, either π(Ξ) β Ξ,or π(Ξ) β© Ξ = β
. In the former case, by Corollary 5.5,π(π) = π in the sense of angular limits. Moreover, taking into account that πβ π, by Theorem 1.4 we have that in this case, π=π π‘0for some π‘0>0and as a consequence π(Ξ) = ππ‘0(Ξ) = Ξ.Thus,ifπ(Ξ) β Ξ, then alternative (i) in Theorem 1.8(A) holds. Now suppose π(Ξ) β© Ξ = β
.IfΞβ²is a hyperbolic petal of (ππ‘), then according to Lemma 5.3, alternative (ii) in Theorem 1.8(A) holds. If Ξβ²is a parabolic petal of (ππ‘), then again by Lemma 5.3, π(π) = π in the sense of angular limits. In this case, taking into account that πβ πand that πβ²(π) β β,by[24, Lemma 8.2], the angular derivative πβ²(π) is β, and thus, alternative (iii) holds. This completes the proof of Theorem 1.8(A). Proof of (B). By hypothesis, Ξis a parabolic petal for (ππ‘). Hence, statement (a) is just Lemma 5.4. Since one of the implications in statement (b) is clear, see Section 5, it remains to prove that if π(Ξ) = Ξ, then πis contained in (ππ‘). To this end, consider the canonical holomorphic model (π,π»,(π§β¦π§+π‘) π‘β©Ύ0)for the semigroup (ππ‘). It is known, see, for example, [7, Theorem 13.5.7], that Ξ βΆ=π»(Ξ)is a half-plane of the form Ξ ={π§βΆImπ§>π}or Ξ ={π§βΆImπ§<π}. Note that (π,π»,π§β¦π§+1)is the canonical model for π1. Recall also that πβξ(π1). Therefore, according to [5, Theorem 3.4], π=π» β1β¦gβ¦π»for some gβξ(π) satisfying g(π§ + 1) = g(π§)+1 for all π§βπ.(7.1) If π(Ξ) = Ξ, then g(Ξ ) = Ξ and hence, taking into account (7.1), we conclude that g(π§) = π§ + π for all π§βΞ and some constant πββ. Clearly, this equality hold for all π§βπ. Note that g(π»(π»))= π»(π(π»))βπ»(π»).Sinceπ1is not an automorphism of π»,by[5, Theorem 3.1 (B)], we have πβ©Ύ0, and of course, πβ 0because πβ ππ½π». Therefore, π=π π‘0with π‘0βΆ= π > 0.β‘ Proof of Theorem 1.9. Let (π,π»,(π§β¦π§+π‘) π‘β©Ύ0)stand for the canonical holomorphic model of (ππ‘). As in the proof of Theorem 1.8, we see that πis not a hyperbolic automorphism. Proof of (I). The semigroup (ππ‘)cannot be elliptic, because π1β ππ½π»commutes with the nonelliptic self-map π. Furthermore, (ππ‘)cannot be hyperbolic because otherwise having πβξ(π1) and π1β π ππ(π»)would imply π=π π‘0for some π‘0β©Ύ0, see, for example, [5, Remark 6.4]; but this directly contradicts the hypothesis. Therefore, (ππ‘)is parabolic, and by [4, Corollary 4.1] so is π. Moreover, by Lemma 5.6,(ππ‘)can have at most one parabolic petal. Proof of (II). Let Ξβbe the unique parabolic petal of (ππ‘).Itisknown,see,forexample, [7, Theorem 13.5.7], that Ξ βΆ=π»(Ξ β)is a half-plane of the form Ξ ={π§βΆImπ§>π} or Ξ ={π§βΆImπ§<π}. Below we give a proof for the former alternative. The other case can be treated in a similar way. If (ππ‘)is parabolic of zero hyperbolic step, then by [5, Proposition 4.3], we have π»β¦πβ¦π»β1 = (π€ β¦ π€ + π), where πβ[0,+β)because πisnotanelementof(ππ‘).Notealsothatby[5, Theorem 3.1 (B)], π β (ββ, 0) because π1is not an automorphism. Moreover, π(Ξβ)βΞ βby Lemma 5.4 and hence, Ξ +πβΞ . As a consequence, Im π > 0. Since for each hyperbolic petal Ξ,itsimage π»(Ξ) is a horizontal strip, see, for example, [7, Theorem 13.5.5 (2)], it follows that there exists πββsuch that π»(Ξ)+ππβΞ and, as a result, we have πβ¦π(Ξ)βΞ β. Choose the smallest of 14697750, 2025, 2, Downloaded from https://londmathsoc.onlinelibrary.wiley.com/doi/10.1112/jlms.70077 by Spanish Cochrane National Provision (Ministerio de Sanidad), Wiley Online Library on [29/05/2025]. See the Terms and Conditions (https://onlinelibrary.wiley.com/terms-and-conditions) on Wiley Online Library for rules of use; OA articles are governed by the applicable Creative Commons License
22 of 31 CONTRERAS et al. such πs. To complete the proof of assertion (II) for the case of zero hyperbolic step, it now suffices to appeal to Lemmas 5.2 and 5.3. Suppose (ππ‘)is of positive hyperbolic step. We may suppose π=β. The argument for the case π=β βis similar. By [5, Theorem 3.4], there exists gβξ(β)satisfying π»β¦π=gβ¦π»and such that g(π€ + 1) = g(π€)+1for any π€ββ. As in the previous case, gcannot be of the form π€β¦π€+π with πββ. Therefore, see, for example, [5, Lemma 9.3 (II)], exp (2ππg(π))=π(π 2πππ), where πβ π§ππ
(π»),π(0) = 0,|πβ²(0)|<1. Since the iterates of such a self-map πβΆπ»βπ»converge to 0, see, for example, [1, Theorem 3.1.13], it follows that for any π€ββ,Im gβ¦π(π€) β +β as πβ+β. Therefore, any point π§βπ», πβ¦π(π§) = π»β1(gβ¦π(π»(π§)))βπ» β1(Ξ ) = Ξβ for πββlarge enough. As a consequence, for any hyperbolic petal Ξthere exists πββsuch that πβ¦π(Ξ) β© Ξββ β
. Relying on the fact that petals are pairwise disjoint and applying Lemma 5.2 with πβ¦πin place of π, we therefore conclude that πβ¦π(Ξ) β Ξβ. Now we can complete the proof of (II) in the same manner as in the previous case: Pass to the smallest πββsatisfying πβ¦π(Ξ) β Ξβand appeal to Lemmas 5.2 and 5.3. Proof of (III). Suppose that (ππ‘)has no parabolic petal and let Ξbe some hyperbolic petal of (ππ‘). Applying inductively Lemmas 5.2 and 5.3, we conclude that there exists a sequence of hyperbolic petals (Ξπ)with πΌ-points ππsuch that Ξ1=Ξ,π(Ξπ)βΞ π+1,andπ(ππ)=π π+1 for all πββ. In order to see that Ξπsare pairwise disjoint,β we suppose on the contrary that Ξπ+π =Ξ π for some π,π β β. Then πβ¦π(Ξπ)βΞ π, and hence by Theorem 1.8(A) applied to Ξand πreplaced by Ξπand πβ¦πwe would have that πβ¦π=π π‘0for some π‘0>0. By Lemma 5.7, this would further imply that πitself is contained in (ππ‘), which contradicts the hypothesis of the theorem. To complete the proof, it remains to notice that according to [6, Theorem 1.4], πβ² 1(ππ)β©½πβ² 1(π1)for all πββand, as a consequence, the CowenβPommerenke inequality [24, Theorem 4.1 (iii)] +β β π=1 |πβπ π|2 πβ² 1(ππ)β1 β©½2Re(1 π1(0) β1 )<+β implies |πβπ π|β0as πβ+β.β‘ 8PETALS AND ISOGONALITY Given πβξ(π»)non-elliptic and (ππ‘) β π ππ(π»)a continuous one-parameter semigroup in the disc such that π1βξ(π) β§΅ {ππ½π»}, in Theorem 1.8, it was shown that πmaps petals of (ππ‘)into petals of (ππ‘). In fact, if such a petal Ξis parabolic, we always have π(Ξ) β Ξ. However, this is no longer the case when Ξis hyperbolic. Apart from the same possibility, that is, apart from the case π(Ξ) β Ξ, and in general, we can have the other two following situations: βSituation A: π(Ξ) β Ξβ²and Ξβ²is a hyperbolic petal. βSituation B: π(Ξ) β Ξβ²and Ξβ²is a parabolic petal. In the following two results, we analyze when πmaps Ξonto Ξβ²in both situations. β An alternative way to prove this fact is to combine [6, Proposition 5.2] with Lemma 5.3. 14697750, 2025, 2, Downloaded from https://londmathsoc.onlinelibrary.wiley.com/doi/10.1112/jlms.70077 by Spanish Cochrane National Provision (Ministerio de Sanidad), Wiley Online Library on [29/05/2025]. See the Terms and Conditions (https://onlinelibrary.wiley.com/terms-and-conditions) on Wiley Online Library for rules of use; OA articles are governed by the applicable Creative Commons License
EXTENSION OF COMMUTATIVITY TO FRACTIONAL ITERATES 23 of 31 Proposition 8.1. Assume we are in Situation A and let πand πβ²be the πΌ-points of Ξand Ξβ², respectively. Then the following conditions are equivalent: (a) π(Ξ) = Ξβ²; (b) πis isogonal at π; (c) the spectral values of (ππ‘)at πand πβ²coincide. Moreover, if the above equivalent conditions hold, then πis affine with respect to π1and hence, (ππ‘)βξ(π). Proposition 8.2. In Situation B we always have π(Ξ) β Ξβ². The proof of these two propositions require some backgrounds which we expose thereafter. We begin by recalling the definition of isogonality, which we extend to the case of infinite angular limit. Definition 8.3. A univalent function πβΆπ»ββis said to be isogonal or semi-conformal at a point πβπ π»if the following two angular limits exist: π(π) βΆ= β lim π§βπ π(π§) β ββͺ{β} and β lim π§βπ arg π0(π§) π§βπ, where arg is to be understood as a continuous map from ββ§΅{0}to ββ(2πβ€)and π0(π§) βΆ= {π(π§)βπ(π) if π(π) β β, 1βπ(π§) if π(π) = β. Further, a univalent function Ξ¨βΆβRe ββis said to be isogonal at πβπβRe if the composition πβΆ=Ξ¨β¦π»π, where π»πis the Cayley map of π»onto βRe with π»π(0) = 0,π»π(1) = π,isisogonal at π=1. Remark 8.4. If πβξ(π»)and πis a contact point of π, then an elementary argument shows that the isogonality condition requires that the image of the radial segment [0, π] under πapproaches the point π(π) β ππ»orthogonally to ππ». Therefore, in this case, the isogonality at πis equivalent to β lim π§βπ Arg 1βπ(π)π(π§) 1βππ§ =0, (8.1) where Arg π€ stands for the unique value of the argument of π€β 0contained in (βπ,π]. Passing this remark to the right half-plane with the help of the Cayley map, we can say that a univalent self-map πβξ(βRe)with a boundary fixed point at 0 is isogonal at 0 if and only if β lim π€β0 Arg π(π€) π€=0. (8.2) 14697750, 2025, 2, Downloaded from https://londmathsoc.onlinelibrary.wiley.com/doi/10.1112/jlms.70077 by Spanish Cochrane National Provision (Ministerio de Sanidad), Wiley Online Library on [29/05/2025]. See the Terms and Conditions (https://onlinelibrary.wiley.com/terms-and-conditions) on Wiley Online Library for rules of use; OA articles are governed by the applicable Creative Commons License
24 of 31 CONTRERAS et al. Definition 8.5. Let πβππ»be a repelling fixed point of a continuous one-parameter semigroup (ππ‘)with associated infinitesimal generator πΊ. The triple (βRe,Ξ¨,π π‘)is called a pre-model for (ππ‘) at πif the following conditions are met: (i) for each π‘β©Ύ0,ππ‘is the automorphism of βRe given by ππ‘(π§)βΆ=π ππ‘π§, where πβΆ=πΊ β²(π); (ii) the map Ξ¨βΆβRe βπ»is holomorphic and injective, β lim π€β0 Ξ¨(π€) = π,andΞ¨is isogonal at 0, that is, β lim π€β0 Arg 1βπΞ¨(π€) π€=0; (8.3) (iii) Ξ¨β¦ππ‘=π π‘β¦Ξ¨for all π‘β©Ύ0. Remark 8.6. It is known [25, Theorem 3.10] that every continuous one-parameter semigroup, at each repelling fixed point π, admits a pre-model unique up to the transformation Ξ¨(π€) β¦ Ξ¨(ππ€), where πis an arbitrary positive constant. Moreover, Ξ¨(βRe)coincides with the hyperbolic petal Ξ(π) associated with π.ThemapΞ¨can be expressed via the Koenigs function βof (ππ‘).Namely,if the strip β(Ξ(π)) is π(π,π)={π€βΆπ<Imπ€<π}, then the intertwining map Ξ¨in the pre-model for (ππ‘)at πis given by Ξ¨(π€) βΆ= ββ1(πβπ 2π log π€ + π+π 2π+π ),π€ββRe, where π is an arbitrary real constant. As the following result shows, it is also possible to talk about pre-models associated with parabolic petals. Theorem 8.7 [7, Proposition 13.4.10 and its proof]. Let (ππ‘)be a parabolic semigroup in the unit disc with DenjoyβWolff point πβπ π»and let Ξbe a parabolic petal of (ππ‘).Then,thereexist Ξ¨βξ(βRe,π»)with Ξ¨(βRe)=Ξand β lim π€β0 Ξ¨(π€) = π and a parabolic group (ππ‘)in βRe with DenjoyβWolff point at 0 such that, for all π‘β©Ύ0, Ξ¨β¦ππ‘=π π‘β¦Ξ¨. Definition 8.8. In the notation of the above theorem, the triple (βRe,Ξ¨,π π‘)is called a pre-model for (ππ‘)associated with the parabolic petal Ξ. Lemma 8.9. Let πbe a univalent self-map of βRe.If π(0) = 0 in the sense of angular limits and if πis isogonal at 0, then for any π½>0, lim π₯β0+ π(π½π₯) π(π₯) =π½. (8.4) 14697750, 2025, 2, Downloaded from https://londmathsoc.onlinelibrary.wiley.com/doi/10.1112/jlms.70077 by Spanish Cochrane National Provision (Ministerio de Sanidad), Wiley Online Library on [29/05/2025]. See the Terms and Conditions (https://onlinelibrary.wiley.com/terms-and-conditions) on Wiley Online Library for rules of use; OA articles are governed by the applicable Creative Commons License
EXTENSION OF COMMUTATIVITY TO FRACTIONAL ITERATES 25 of 31 Proof. Since πis isogonal at 0 with π(0) = 0, the univalent function π(1βπ§ 1+π§ ),π§βπ», satisfies at π=1the VisserβOstrowski condition; see, for example, [26, Proposition 4.11 on p. 81]. It followsβ that lim π₯β0+ π₯πβ²(π₯) π(π₯) =1. As a consequence, log π(π½π₯) π(π₯) = π½ β« 1 π‘π₯ πβ²(π‘π₯) π(π‘π₯) dπ‘ π‘βΆ π½ β« 1 dπ‘ π‘= log π½ as π₯β0 +, as desired. β‘ Recall that a sequence (π§π)βπ»converging to some point πβππ»is said to converge to π non-tangentially if the limit set Slope[(π§π), π β +β] of Arg(1 β ππ§π)as πβ+βis compactly contained in the open interval (βπβ2,πβ2). Further, we say that (π§π)converges to πtangentially, if Slope[(π§π), π β +β] β {βπβ2,πβ2}. Clearly, (π§π)converges to πnon-tangentially if and only if it has no subsequence converging tangentially. Lemma 8.10. Suppose πβξ(π»)is isogonal at some point πβππ»and that π(π) β ππ».If(π§π)βπ» converges to πtangentially, and if (π€π)given by π€πβΆ= π(π§π)for all πββconverges to π(π),then the convergence of (π€π)is also tangential. Proof. Composing πwith suitable conformal mappings we may replace π»with βRe and suppose π(π)=π=0.Fixsomeπβ(0,πβ2)and set πβΆ=1 2(π + πβ2).Since(π§π)ββRe converges to 0 tangentially, there exists π>0such that π΄π,π βΆ= {π§ βΆ |Arg π§|<π, |π§|<π}does not contain any point of (π§π). The isogonality of πat 0 implies, see, for example, [26, Proposition 4.10 on p. 81], that there exists π>0such that π΄π,π βπ (π΄π,π).Sinceπis univalent by hypothesis, it follows that π΄π,π does not contain any point of (π€π). Taking into account that πβ(0,πβ2)in this argument is arbitrary, we conclude that if (π€π)converges to 0, then the convergence must be tangential. β‘ Lemma 8.11. Let π·1,π· 2,π· 3β{π»,βRe}and let π3βΆ= π2β¦π1,whereπ1βΆπ· 1βπ· 2and π2βΆπ· 2βπ· 3are two (holomorphic) univalent functions. The following two statements hold. (A) If π1is isogonal at some π1βππ· 1with π2βΆ= π1(π1)βππ· 2and if π2is isogonal at π2with π3βΆ= π2(π2)βππ· 3,thenπ3is isogonal at π1with π3(π1)=π 3. (B) Conversely, if π3is isogonal at some π1βππ· 1and if π3βΆ= π3(π1)βππ· 3, then: (i) π1is isogonal at π1, (ii) π2βΆ= π1(π1)belongs to ππ·2, (iii) π2is isogonal at π2, and (iv) π2(π2)=π 3. Proof. First of all, without loss of generality, we may suppose π·1=π· 2=π· 3=π». Proof of (A). Taking into account Remark 8.4, we have to show that for any sequence (π§π)βπ» converging to π1non-tangentially, π3(π§π)βπ 3and Arg ((1 β π3π3(π§π))β(1 β π1π§π))β0.This β In [27] one can find another proof of this fact (not assuming global univalence of π), see [27, Lemma 8.1] applied to π§ β¦ 1βπ(1βπ§), as well as some closely related results connecting asymptotic behavior of the hyperbolic derivative to isogonality and to existence of finite angular derivative. 14697750, 2025, 2, Downloaded from https://londmathsoc.onlinelibrary.wiley.com/doi/10.1112/jlms.70077 by Spanish Cochrane National Provision (Ministerio de Sanidad), Wiley Online Library on [29/05/2025]. See the Terms and Conditions (https://onlinelibrary.wiley.com/terms-and-conditions) on Wiley Online Library for rules of use; OA articles are governed by the applicable Creative Commons License