On the maximum of r-Stirling numbers
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On he maximum o -S i ling numbe s
Is ´an Mez˝o 1
Depa men o Algeb a and Numbe Theo y, Ins i u e o Ma hema ics, Uni e si y
o Deb ecen, Hunga y
Abs ac
De e mining he loca ion o he maximum o S i ling numbe s is a well de eloped
a ea. In his pape we gi e same esul s o he so-called -S i ling numbe s which
a e na u al gene aliza ions o S i ling numbe s.
Key wo ds: S i ling numbe s, -S i ling numbe s, unimodali y, log-conca i y
2000 MSC: 11B73
1 In oduc ion
The S i ling numbe o he i s kind hn
migi es he numbe o pe mu a ions o
nelemen s o med by exac ly mdisjoin cycles. They sa is y he ecu ence
ela ion "n
0#=δ0n,"n
m#= (n−1)"n−1
m#+"n−1
m−1#,(1)
As an equi alen de ini ion, he numbe s hn
kin
k=0 a e he coe icien s o he
nex polynomial:
n
X
k=0 "n
k#xk=x(x+ 1)(x+ 2) ···(x+n−1).(2)
The S i ling numbe o he second kind, deno ed by nn
mo, enume a es he num-
be o pa i ions o a se wi h nelemen s consis ing o mdisjoin , nonemp y
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URL: h p://www.ma h.kl e.hu/algeb a/mezo.h m (Is ´an Mez˝o).
1P esen add ess: Uni e si y o Deb ecen, H-4010, Deb ecen, P.O. Box 12, Hunga y
P ep in submi ed o Ad ances in Applied Ma hema ics 18 Janua y 2008
se s. The ollowing ecu ence ela ion holds
(n
0)=δ0n,(n
m)=m(n−1
m)+(n−1
m−1).(3)
An al e na i e de ini ion can be gi en by he o mula
xn=
n
X
k=0 (n
k)x(x−1)(x−2) ···(x−k+ 1).(4)
An excellen in oduc ion o hese numbe s can be ound in [9].
A sequence a1, a2, . . . , anis said o be unimodal [25] i i s membe s ise o a
maximum and hen dec ease, ha is, he e exis an index ksuch ha
a1≤a2≤ ··· ≤ ak,
and
ak≥ak+1 ≥ ··· ≥ an.
A s onge p ope y, called log-conca i y, implies he unimodali y. The se-
quence a1, a2, . . . , anis called log-conca e when
a2
k≥ak+1ak−1(k= 2, . . . , n −1),(5)
and i is called s ongly log-conca e when he e is s ic inequali y in he abo e
exp ession.
New on’s inequali y [18] gi es a simple es o e i y he s ong log-conca i y.
Theo em 1 (New on’s inequali y) I he polynomial a1x+a2x2+···+anxn
has only eal oo s hen
a2
k≥ak+1ak−1
k
k−1
n−k+ 1
n−k(k= 2, . . . , n −1).
This immedia ely implies he s ic e sion o (5).
Conside ing (2), an immedia e consequence is ha he sequence hn
kin
k=1 is
s ic ly log-conca e o all n. Acco ding o he wo k o Hamme sley [11] and
E d˝os [8], much mo e is ue. Namely, he index Kno he maximal S i ling
numbe o he i s kind is unique o all ixed n > 2:
"n
1#<"n
2#<··· <"n
Kn−1#<"n
Kn#>"n
Kn+ 1#>··· >"n
n#.
2
Mo eo e , he maximizing index is de e mined by
Kn=
log(n+ 1) + γ−1 + ζ(2) −ζ(3)
log(n+ 1) + γ−3
2
+h
log(n+ 1) + γ−3
22
,
whe e [x] deno es he in ege pa o x,ζis he Riemann ze a unc ion, γ=
0.5772 . . . is he Eule -Masche oni cons an and −1.1< h < 1.5. As E d˝os
ema ked, his can be simpli ied when n > 188:
log n−1
2< Kn<[log n].(6)
The si ua ion changes o S i ling numbe s o he second kind. The e is no
exac closed o m o he maximizing index Kn. Wha is mo e, we do no know
whe he i is unique o no . Al hough K2is no unique, since n2
1o=n2
2o= 1,
in 1973 Wegne [23] conjec u ed ha o all n≥3 he index Knis unique.
Acco ding o he pape [4], he e is no coun e example o 3 <n<106.
One hing is ce ain, he S i ling numbe s o he second kind o m a s ongly
log-conca e sequence [4,7,18,20].
The pape s [10,12,14–16,23] con ain a numbe o es ima ions o Kn. The mos
exac (wi hou any app oxima i e e m) was gi en by Wegne [23]:
Kn<n
log n−log log n(n≥3),(7)
n
log n< Kn(n≥18).
Asymp o ic p ope ies o he maximizing index we e p o ed in [19,21] and
e en by s a is ical ools in [13]:
Kn∼n
log n,
in he sense ha hei quo ien ends o 1 as n ends o in ini y.
We ema k ha his app oxima ion can be gi en using he esul in [4]. I is
shown ha
Kn∈ {be (n)−1c,de (n)−1e},
whe e (n) was de ined implici ly by he equa ion
(n)e (n)=n.
3
Since (n) is known as he Lambe W unc ion [5] we can use i s app oxima-
ion [5, p. 349]:
W(z) = log z−log log z+log log z
log z+O log log z
log z!2
(z > 3).
This means ha
e (n)=eW(n)=n
log nelog log n
log n··· ∼ n
log n.
2 No ion o -S i ling numbe s
In he p e ious sec ion we ha e in oduced he p oblems on he maximum o
S i ling numbe s and p esen ed he solu ions. Now we ex end he p oblem o
he na u al gene aliza ion o S i ling numbe s as ollows.
Fo any posi i e in ege he symbol hn
mi deno es he numbe o hose pe mu-
a ions o he se {1,2, . . . , n} ha ha e mcycles such ha he i s elemen
a e in dis inc cycles. The ecu ence ela ion is he same ha o o dina y
S i lings
"n
m#
= 0, n < ,
"n
m#
=δm , n = , (8)
"n
m#
= (n−1)"n−1
m#
+"n−1
m−1#
, n > .
A double gene a ing unc ion is gi en in [3]:
∞
X
n=0 n
X
k=0 "n+
k+ #xk!zn
n!=1
(1 −z) +x.(9)
Le us in oduce he -S i ling numbe s o he second kind. nn
mo deno es he
numbe o hose pa i ions o he se {1,2, . . . , n} ha ha e mnonemp y,
disjoin subse s, such ha he i s elemen s a e in dis inc subse s. The
4
usual ecu ence is again he same.
(n
m)
= 0, n < ,
(n
m)
=δm , n = , (10)
(n
m)
=m(n−1
m)
+(n−1
m−1)
, n > .
The iden i y (4) u ns o be
(x+ )n=
n
X
k=0 (n+
k+ )
x(x−1) ···(x−k+ 1).(11)
One can iden i y he o dina y S i lings o -S i lings ia
"n
m#="n
m#0
="n
m#1
,
(n
m)=(n
m)0
=(n
m)1
.
A nice, in oduc o y pape was w i en by B ode [3].
The ques ion a ises immedia ely: wha is ue om he esul s o he i s
sec ion wi h espec o -S i ling numbe s? In he ollowing sec ions we gi e
he answe .
3 Resul s o -S i ling numbe s o he i s kind
Theo em 2 The sequence hn+
k+ in
k=0 is s ongly log-conca e (and hus uni-
modal).
P oo . Le us de ine he ollowing polynomial:
Pn, (x) :=
n
X
k=0 "n+
k+ #
xk.(12)
I is wo h o shi he indices by o a oid he edundan ze os, since hn
ki = 0
i n< . The exponen ial gene a ing unc ion o Pn, (x) is gi en in (9), whence
1
(1 −z) +x=
∞
X
n=0 +x−1 + n
n!zn=
∞
X
n=0
Pn, (x)
n!zn.
5
Compa ing he coe icien s,
Pn, (x) = n! +x−1 + n
n!= (x+ )(x+ + 1) ···(x+ +n−1).(13)
The e o e he oo s o Pn, (x) a e eal. Applying New on’s inequali y, he p oo
is comple e. 2
In wha ollows le K1
n, deno e he maximizing index o he sequence hn
ki n
k=0
( he uppe index 1 e e s o he kind). To ind he es ima ion o K1
n, we ha e
o ema k ha he numbe s hn
ki o a ixed n, a e he elemen a y symme ic
unc ions o he numbe s 1, . . . , n, while he numbe s hn
ki a e he elemen a y
symme ic unc ions o he numbe s , . . . , n (see [3,8]). Tha is, o a ixed n,
he (0-)S i ling numbe s a e he sums o he p oduc s o he i s nna u al
numbe s aken ka a ime and -S i ling numbe s a e he sums o he p oduc s
o he , . . . , n na u al numbe s aken ka a ime. This was de ailed in [3]:
"n
n−k#
=X
≤i1<i2<···<ik<n
i1i2···ik(n, k ≥0).(14)
Now we ci e a heo em o E d˝os and S one [8]:
Theo em 3 (P. E d˝os and A. H. S one) Le u1< u2<··· be an in ini e
sequence o posi i e eal numbe s such ha
∞
X
i=1
1
ui
=∞and
∞
X
i=1
1
u2
i
<∞.
Deno e by Σn,k he sum o he p oduc o he i s no hem aken ka a ime
and deno e by Kn he la ges alue o k o which Σn,k assumes i s maximum
alue. Then
Kn=n−"n
X
i=1
1
ui−
n
X
i=1
1
u2
i1 + 1
ui−1
+o(1)#.
I is ob ious om (14) ha
"n
k#
= Σn− ,n−k(15)
wi h he sequence u1= , u2= +1, . . . . As a consequence, we ge he pa allel
esul o (6):
Theo em 4 The la ges index o which he sequence hn
kin
k=0 assumes i s
6
maximum is gi en by he app oxima ion
K1
n, = +log n−1
−1−1
+o(1).
P oo . I we choose u1= , u2= +1, . . . hen, by (15), he maximizing index
K1
n, equals o
+"1
+1
+ 1 +···+1
n−1−
∞
X
i=1
1
( +i−1)( +i)+o(1)#
= +log n−1
−1−1
+o(1),
since i is well known ha
1
1+1
2+···+1
n= log n+γ+o(1).
The addi i e e m comes om he ac ha he i s nonze o symme ic
unc ion belongs o he index k= in he sequence hn
kin
k=0.2
Example 5 We gi e an elemen a y applica ion: he maximal elemen o he
sequence h30
ki330
k=0 belongs o he index
K1
30,3= 3 + log 30 −1
3−1−1
3+o(1)= 5.
Indeed,
"30
5#3
= 1.259 ·1031
is maximal, as one can see wi h any compu e algeb a sys em using he ecu -
ence ela ions (8).
4 Resul s o -S i ling numbe s o he second kind
To o mula e ou esul s, we p o e he ollowing heo em.
Theo em 6 The sequence nn+
k+ o n
k=0 is s ongly log-conca e.
P oo . As be o e, we de ine he polynomial
Bn, (x) :=
n
X
k=0 (n+
k+ )
xk.(16)
7
Using he ecu ence ela ion (10),
Bn, (x) =
n
X
k=0
(k+ )(n−1 +
k+ )
xk+
n
X
k=0
(k+ )(n−1 +
k−1 + )
xk
=1
x −1
n−1
X
k=0
(k+ )(n−1 +
k+ )
xk+ −1+xBn−1, (x)
=1
x −1
∂
∂x (x Bn−1, (x)) + xBn−1, (x).
F om his we ge a ecu ence ela ion o he polynomials Bn, (x):
Bn, (x) = x ∂
∂xBn−1, (x) + Bn−1, (x)!+ Bn−1, (x).(17)
This equa ion implies he iden i y
exx Bn, (x) = x∂
∂x (exx Bn−1, (x)) .(18)
Mo eo e , by he de ini ion (16), Bn−1, (x)>0 i x≥0. We p o e he emain-
ing pa by induc ion. Since B1, (x) = x+ , i s oo is eal (and nega i e).
Now assume ha all o he oo s o Bn−1, (x) a e eal and nega i e.
So Rolle’s heo em gi es ha on he igh hand side o (18) he e a e n−1
nega i e oo s beside he oo x= 0 wi h mul iplici y . Because he unc ion
on he le hand side mus ha e exac ly n+ ini e oo s, he missing one can
no be complex. Since Bn, (x)>0 i x≥0, i mus be nega i e, oo. New on’s
heo em comple es he p oo . 2
Rema k 7 The Bell polynomials a e de ined as
Bn(x) =
n
X
k=0 (n
k)xk.
The Bell numbe s a e Bn=Bn(0). The e o e he de ini ion (16) can be con-
side ed as a gene aliza ion o hese numbe s and polynomials in he special
case Bn(x) = Bn,0(x).
We con inue wi h he ollowing lemma which is a pa ial gene aliza ion o he
so-called Bon e oni-inequali y (see [23,24]).
Lemma 8 We ha e
(m+ )n
m!−(m−1 + )n
(m−1)! <(n+
m+ )
<(m+ )n
m!,
8
o all n≥m > 0.
P oo . Equa ion (11) yields ha
(m+ )n=
m
X
k=0 (n+
k+ )
m!
(m−k)!.
Hence
(m+ )n
m!=
m−1
X
k=0 (n+
k+ )
1
(m−k)! +(n+
m+ )
,
he e o e he inequali y on he igh hand side is alid. Applying (11) again,
we ge
(n+
m+ )
>(m+ )n
m!−
m−1
X
k=0 (n+
k+ )
1
(m−1−k)!
=(m+ )n
m!−(m−1 + )n
(m−1)! .
2
Since he sequence nn
ko n
k= is s ongly log-conca e, he e exis an index K2
n,
o which
··· <(n
K2
n, −1) ≤(n
K2
n, )
>(n
K2
n, + 1)
>···
Now we gi e es ima ions o he maximizing index K2
n, o -S i ling numbe s
o he second kind.
Theo em 9 Le K2
n, be he g ea es maximizing index shown abo e. Then
K2
n, <n−
log(n− )−log log(n− )(n≥ + 3),
n−
log(n− )< K2
n, (n≥ + max {18,log 2/log (1 + 1/ )}).
P oo . I is con enien again o shi he indices. To p o e he uppe es ima ion,
we apply equa ion (32) o [3]:
(n+
k+ )
=
n
X
j=0 n
j!(j
k)1
n−j,
9
[21] B. C. Rennie, A. J. Dobson, On S i ling numbe s o he second kind,
J. Combin. Theo y 7 (1969) 116-121.
[22] A. Rucinski, T. Luczak, S. Janson, Random G aphs ol. 2., John Wiley,
New Yo k, 1992, 215-231.
[23] H. Wegne , H. ¨
Ube das Maximum bei S i lingschen Zahlen zwei e A ,
J. Reine Angew. Ma h. 262/263 (1973) 134-143.
[24] H. Wegne , S i ling numbe s o he second kind and Bon e oni’s
inequali ies, Elem. Ma h. 60 (2005) 124-129.
[25] H. S. Wil , Gene a ing unc ionology, Academic P ess, Ha cou B ace
Jo ano ich, 1994.
16