Cosmological solutions of the Einstein-Vlasov-scalar field system
vorgelegt von
Diplom-Mathematiker
David Tegankong
von der Fakult¨at II-Mathematik und Naturwissenschaften
der Technische Universit¨at Berlin
zur Erlangung des akademischen Grades
Doktor der Naturwissenschaften
- Dr. rer. nat. -
genehmigte Dissertation
Promotionsausschuss:
Vorsitzender: Prof. Dr. R. Nabben
Berichter: Priv.-Doz. Dr. A. D. Rendall
Berichter: Prof. Dr. A. Unterreiter
Tag der wissenschaftlichen Aussprache: 19. Mai 2005
Berlin 2005
D 83
1
To my wife Blandine Pulcherie Tamatcho and our child Marl`ene, Audrey and
Brice Tegankong.
i
Acknowledgements
I am grateful to my supervisors Pr. Alan D. Rendall and Pr. Norbert Noutchegueme
for helpful suggestions that both gave me during this work. A major part of
this work was carried out during two three-months stays at the Albert Einstein
Institute where I received pleasure of collaboration of Pr. Alan D. Rendall. So
I would like to give him many thanks.
I gratefully acknowledge the financial support of the VolkswagenStiftung,
Federal Republic of Germany, that allows me to do this work.
Besides, I thank Frau Hauschild and Frau Lampe for a warm welcome they
brought me during each of my visit at the Albert Einstein Institute in G¨olm.
ii
Contents
Abstract 1
Introduction 2
1 Equations and preliminary results 5
1.1 Equations . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 5
1.2 Auxiliary system and preliminary results . . . . . . . . . . . . . . 10
1.3 The reduced system . . . . . . . . . . . . . . . . . . . . . . . . . 16
2 Local existence and continuation of solutions 26
2.1 Iteration . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 26
2.2 Local existence . . . . . . . . . . . . . . . . . . . . . . . . . . . . 35
2.3 Continuation criteria . . . . . . . . . . . . . . . . . . . . . . . . . 41
3 Global existence and asymptotic behaviour of solutions in the
past 50
3.1 Global existence in the past . . . . . . . . . . . . . . . . . . . . . 50
3.2 On past asymptotic behaviour . . . . . . . . . . . . . . . . . . . . 54
4 Global existence and asymptotic behaviour of solutions in the
future 62
4.1 Global existence in the future . . . . . . . . . . . . . . . . . . . . 62
4.2 The future asymptotic behaviour . . . . . . . . . . . . . . . . . . 68
4.2.1 Integration of equations . . . . . . . . . . . . . . . . . . . 69
4.2.2 Geodesic completeness . . . . . . . . . . . . . . . . . . . . 70
Conclusion 75
Appendices 76
iii
Abstract
The aim of this thesis is to obtain as much information as possible, about global
solutions of the Cauchy problem for the Einstein-Vlasov-scalar field system with
spherical, plane and hyberbolic symmetries written in areal coordinates. The
sources of this system are generated by both a distribution function and a linear
scalar field subject to the Vlasov and wave equations respectively. This system
describes the evolution of self-gravitating collisionless matter and scalar waves
within the context of general relativity. We consider the cosmological case. That
is spacetimes possess a compact Cauchy hypersurface and then, data are given
on a compact 3-manifold.
We extend the local-in-time results obtained by G. Rein for the Einstein-
Vlasov system with collisionless matter alone. This extension concerns pointwise
estimates for hyperbolic equations by the method of characteristics. This means
that the system is transformed to a system of ordinary differential equations
which are integrated along characteristics. The constraint equation on the initial
data reduced to an ordinary differential equation of first order and is solved. In
the past direction, we show global existence results for general data. The proof
is based on a change of variables inspired by the work of M. Weaver. The nature
of singularity is analyzed. The curvature invariant called Kretschmann scalar
blows up as ttends to 0 so that there is a singularity at tequal zero.
We prove that there is no global solution in the future in the spherical
symmetry case. In the plane and hyperbolic symmetries, the area radius goes
to infinity and so we obtain global solutions in the expanding direction. In the
special case of plane symmetry without Vlasov contribution, we show that the
asymptotics are Kasner-like at early time. Moreover the spacetime obtained in
this case is future geodesically complete.
We conclude the work by showing that the spatially homogeneous solutions
of the plane and hyperbolic symmetric Einstein-Vlasov-scalar field system exist
globally in the future and the corresponding spacetimes are geodesically com-
plete. Future asymptotics are Kasner-like in the plane symmetric case.
1
Introduction
The Einstein-Vlasov system governs the time evolution of a self-gravitating col-
lisionless gas in the context of general relativity. In the mathematical study of
general relativity, one of the main problems is to establish the existence and
properties of global solutions of the Einstein equations coupled to various mat-
ter fields such as collisionless matter described by the Vlasov equation (see [1],
[21] for reviews) or a scalar field (see [19] for the cosmological case and [6], [7]
and references therein for the asymptotically flat case). The aim of the present
investigation is to establish in the cosmological case the global in time existence
of solutions and their behaviour near the singularity and in the future. In this
case the whole universe is modelled and the ”particles” in the kinetic description
are galaxies or even clusters of galaxies.
In [15] and [16] G. Rein obtained cosmological solutions of the Einstein-
Vlasov system with surface symmetry written in areal coordinates. In [27] and
[30], these results were generalized to the case of non-vanishing cosmological
constant. In the present work, we extend the results of [15] to the case where
the source terms of the Einstein equations are generated by both a distribution
function fof particles, which is subject to the Vlasov equation, and a massless
scalar field φ, which is subject to the wave equation. The first result we establish
is a local in time existence theorem together with a continuation criterion. With
this, we prove global existence in time and study the asymptotic behaviour of
solutions when the time coordinate ttends to its limiting values, which might
correspond to the approach to the singularity or a phase of unending expansion.
There are several reasons why it is of interest to look at the case of a scalar
field. The first is that it is the simplest situation in which wave phenomena can
be examined in the context of the Einstein-Vlasov system. In surface symmetry
all wave propagation can be eliminated from the Einstein equations by the use of
suitable coordinate conditions. This is an analogue of the well-known statement
that there are no gravitational waves in spherical symmetry. Mathematically
it means that controlling solutions of the Einstein equations can be reduced to
controlling solutions of ordinary differential equations in time and in space. The
Vlasov equation, being a scalar hyperbolic equation of first order, can also easily
be solved in terms of its characteristics. This was the strategy used in [15] and
[16]. In the presence of a cosmological constant it is possible to follow the same
route.
The inclusion of a scalar field introduces waves into the system which cannot
2
be eliminated. Mathematically this means that it introduces a non-trivial hy-
perbolic equation, the wave equation. This work is concerned with symmetric
situations where there is a symmetry group acting on two-dimensional spacelike
orbits. This means that the wave equation reduces to an effective equation in
one space dimension. As a consequence part of the strategy used previously
can be carried over. That was based on pointwise estimates and not on integral
estimates (energy estimates) as is usual in the theory of hyperbolic equations.
Pointwise estimates for solutions of wave equations in terms of data can be ob-
tained in one space dimension but not in higher space dimensions (See e.g. the
discussion in [12], p. 14.)
Pointwise estimates for hyperbolic equations in one space dimension can be
obtained using the method of characteristics. This means that in fact ordinary
differential equations appear once again but this time they are integrated not at
a constant value of the spatial or time variable but along characteristics. This
method will be applied in the following, the characteristics in this case being
null curves of the spacetime geometry.
It should be mentioned that there are global existence results in the literature
where the Einstein-Vlasov system is considered in a context where hyperbolic
equations play an important role. In fact if we relax the assumptions from sur-
face symmetry, where there are three local Killing vectors, to the case where
there are only two local spacelike Killing vectors, then hyperbolic equations nec-
essarily occur. Some relevant papers are [20], [4], [32]. In those references no
direct local existence proof was given. Instead an indirect argument was used.
First a known local existence theorem for the Einstein-Vlasov equation without
symmetry was quoted. Then it was shown that coordinates could be introduced
which are well-adapted to making use of the symmetry when proceeding to ob-
tain global results. Apart from the methodological interest of having a direct
local existence proof, the direct proof gives stronger results concerning the dif-
ferentiability required of the initial data and obtained for the solutions. This is
very difficult to control in the indirect method and for this reason the latter has
only been applied to the case where everything is of infinite differentiability.
The inclusion of a scalar field can be seen as a step towards certain ques-
tions of physical interest. In recent years cosmological models with accelerated
expansion have become a very active research topic in response to new astro-
nomical observations [25]. The easiest way to obtain models with accelerated
expansion is to introduce a positive cosmological constant, a possibility studied
mathematically in [28], [30] and [13]. A more sophisticated way is to introduce
a scalar field with potential (see [22], section 4.3., [23], [14]). We treat only
the case of a linear scalar field but it is likely that the approach developed here
will be useful in the nonlinear case. Scalar fields also play a role in theories of
gravity generalizing Einstein’s theory, such as the Jordan-Brans-Dicke theory.
In that case, in contrast to the one considered here, there is a direct coupling be-
tween the scalar field and the distribution function. The techniques developed
here could serve as a first step towards the study of these more complicated
situations, which have hardly been looked at mathematically yet. (See however
[2] and [5] where the coupling of the Vlasov equation to a scalar field of the
3
Jordan-Brans-Dicke type in the absence of Einstein gravity is considered).
A large part of our investigation will focus on the initial value problem
for the Einstein-Vlasov-scalar field system with surface symmetry. In the first
chapter, we split the wave equation in φinto a system of two partial differential
equations of first order. This permits us to bound the derivatives of φby the
solutions of the field equations and to introduce an auxiliary system. Next, we
solve each equation of the auxiliary system when the other unknowns are fixed.
Using the results of [15], and under some constraints on the initial data, the full
system is equivalent to the auxiliary system and is reduced to a subsystem. This
chapter ends with the solvability of the constraint equation on data. By iterating
the solutions of the auxiliary system, local in time existence and uniqueness of
solutions in both time directions and continuation criteria are established in the
second chapter.
The third chapter concentrated on the contracting direction. Solutions of the
Einstein-Vlasov-scalar field system with spherical, plane and hyperbolic sym-
metry exist on the whole interval ]0,1] for general initial data. The proof is
based on a change of variables inspired by [32] where the existence up to t= 0
for a certain class of T2-symmetric solutions of the Einstein-Vlasov system with
vanishing cosmological constant was studied. The structure of the initial sin-
gularity is analyzed as in [15]. We show that the spacetime has a curvature
singularity. Moreover the singularity is crushing for any solution in ]0,1]. An
idea from [24] which studied the singularity for solutions of the Einstein equa-
tions in Gowdy spacetimes, allows us to prove in the special case of the spherical,
plane and hyperbolic symmetric Einstein-scalar field system that the singularity
is velocity-dominated.
In the expanding direction in chapter four, a global existence result in the
cases of plane and hyperbolic symmetry is obtained. But this fails in the spher-
ical case. The spacetime is future geodesically complete in the special case of
plane symmetry without Vlasov contribution. The same result holds for spa-
tially homogeneous spacetimes which are solutions of the full system.
The present work is oganized as follows : chapter 1 is concerned with the
formulation of the surface symmetric Einstein-Vlasov-scalar field system written
in areal coordinates and the proof of some preliminary results. The results of
chapter 1 are used to obtain in chapter 2, local existence theorems with contin-
uation criteria in both time directions. Chapter 3 focuses on the existence of
solutions up to t= 0 and their behaviour near the initial singularity. In chapter
4, we prove a global existence result in the future and geodesic completeness.
4
Chapter 1
Equations and preliminary
results
1.1 Equations
Let us recall the formulation of the Einstein-Vlasov-scalar field system ; for the
moment we do not assume any symmetry of the spacetime.
We consider a four-dimensional spacetime manifold M, with local coordi-
nates (xα) = (t, xi) on which x0=tdenotes the time and (xi) the space
coordinates. Unless otherwise specified in what follows Greek indices always
run from 0 to 3, and Latin ones from 1 to 3. On M, a Lorentzian metric gis
given with signature (−,+,+,+). The metric is assumed to be time-orientable,
i.e. that the two halves of the light cone at each point of Mcan be labelled
past and future in a way which varies continuously from point to point. With
this global direction of time, it is possible to distinguish between future-pointing
and past-pointing timelike vectors. The worldline of a particle of non-zero rest
mass mis a timelike curve in spacetime. The unit future-pointing tangent vec-
tor to this curve is the four-velocity vαof the particle. Its four-momentum pα
is given by mvα. Here we assume that all particles have the same mass m,
normalized to unity and no distinction need be made between four-velocity and
four-momentum. There is also the possibility of considering massless particles,
whose worldlines are null curves. In the case m= 1 the possible values of the
four-momentum are precisely all future-pointing unit timelike vectors. These
form a hypersurface (seven-dimensional submanifold)
PM := {gαβpαpβ=−1, p0>0},
in the tangent bundle TM called the mass shell and coordinatized by (t, xi, pi).
If the coordinates are such that the components g0ivanish then the component
p0is expressed by the other coordinates via
p0=p−g00q1 + gijpipj.
5
The distribution function f, which represents the density of particles with given
spacetime position and four-momentum, is a non-negative real-valued function
on PM. A basic postulate in general relativity is that a free particle travels
along a geodesic. Consider a future-directed timelike geodesic parameterized
by proper time. Then its tangent vector at any time is future-pointing unit
timelike. Thus this geodesic has a natural lift to a curve on PM, by taking its
position and tangent vector together. This defines a flow on PM. Denote the
vector field which generates this flow by X. The condition that frepresents
the distribution of a collection of particles moving freely in the given spacetime
is that it should be constant along the flow, i.e. that Xf = 0. This is the
Vlasov equation. In addition we consider a scalar field φwhich is a real-valued
function on M. The Vlasov equation can be coupled to the Einstein-scalar field
equations, giving rise to the Einstein-Vlasov-scalar field system. The unknowns
are a 4-manifold, a (time orientable) Lorentz metric gon M, a non-negative
real-valued function fon the mass shell defined by gand a real-valued function
φon M. The Einstein-Vlasov-scalar field system now reads:
∂tf+pi
p0∂xif−1
p0Γi
βγpβpγ∂pif= 0
Gαβ = 8πTαβ
Tαβ =−ZR3
fpαpβ|g|1
2dp1dp2dp3
p0
+ (∇αφ∇βφ−1
2gαβ∇νφ∇νφ)
where pα=gαβpβ,|g|denotes the modulus of determinant of the metric gαβ,
Γλ
αβ the Christoffel symbols,
Gαβ := Rαβ −1
2gαβR
the Einstein tensor, and Tαβ the energy-momentum tensor. Ris the scalar
curvature of gand
Rαβ =Rνα,νβ =∂νΓν
αβ −∂βΓν
αν + Γν
νρΓρ
αβ −Γν
ρβΓρ
αν
the Ricci tensor.
Lemma 1.1 For any scalar field φof class C2defined on M, we have :
∇α(∇αφ∇βφ−1
2gαβ∇νφ∇νφ) = gφ∇βφ
Proof: We have, using the properties of g:
∇α(∇αφ∇βφ) = ∇α(∇αφ)∇βφ+∇αφ∇α∇βφ
=gφ∇βφ+∇αφ∇α∇βφ
6
gαβ∇α(∇νφ∇νφ) = gαβ∇α(∇νφ)∇νφ+gαβ∇νφ(∇α∇νφ)
= (∇β∇νφ)∇νφ+∇νφ(∇β∇νφ)
=∇νφ∇β∇νφ+gλν∇λφ(∇βgνη∇ηφ)
=∇νφ∇β∇νφ+δη
λ∇λφ∇β∇ηφ
=∇νφ∇β∇νφ+∇λφ∇β∇λφ
= 2∇νφ∇β∇νφ
Therefore
∇α(∇αφ∇βφ−1
2gαβ∇νφ∇νφ) = gφ∇βφ+∇αφ∇α∇βφ−∇νφ∇β∇νφ=gφ∇βφ.
Remark 1.2 Due to the Bianchi Identities, the Einstein equations imply the
conservation law ∇αTαβ = 0. Now since the contribution of fto the energy-
momentum tensor is divergence-free [8], we deduce that:
∇α(∇αφ∇βφ−1
2gαβ∇νφ∇νφ) = 0
which is equivalent to
gφ∇βφ= 0
i.e gφ= 0 or ∇βφ= 0. Consider the open set S={(t, r)|gφ(t, r)6= 0}.
Suppose that Sis non- empty. On S,∇βφ= 0 then ∇β∇βφ= 0 i.e gφ= 0,
which is a contradiction. Therefore Sis empty. This means that
gφ= 0,
which is the wave equation for φ.
Remark 1.3 The Vlasov equation in a fixed spacetime is a linear hyperbolic
equation for a scalar function and hence solving it is equivalent to solving the
equations for its characteristics. In coordinate components these are :
(dXi
ds =Pi
dP i
ds =−Γi
βγPβPγ
Let Xi(s, xα, pi),Pi(s, xα, pi)be the unique solution of the previous system with
initial conditions Xi(t0, xα, pi) = xiand Pi(t0, xα, pi) = pi. Then the solution
of the Vlasov equation can be written as :
f(xα, pi) = f0(Xi(t0, xα, pi), Pi(t0, xα, pi))
where f0is the restriction of fto the hypersurface t=t0. This function f0
serves as initial datum for the Vlasov equation.
7
In [18], a definition of spacetimes with spherical, plane and hyperbolic sym-
metry was given. The spacetime (M, g) is topologically of the form ]0,∞[×S1×
S, where Sis a 2-sphere, a 2-torus, or a hyperbolic plane, in the case of spherical,
plane or hyperbolic symmetry respectively. We now consider a solution of the
Einstein-Vlasov-scalar field system where all unknowns are invariant under one
of these symmetries and write the Einstein-Vlasov system in areal coordinates.
The circumstances under which coordinates of this type exist are discussed in
[3]. The metric gtakes the form
ds2=−e2µ(t,r)dt2+e2λ(t,r)dr2+t2(dθ2+ sin2
kθdϕ2) (1.1)
where
sinkθ=
sin θfor k= 1 (spherical symmetry);
1 for k= 0 (plane symmetry);
sinh θfor k=−1 (hyperbolic symmetry)
t > 0 denotes a time-like coordinate, r∈Rand (θ, ϕ) range respectively in the
domains [0, π]×[0,2π], [0,2π]×[0,2π], [0,∞[×[0,2π] respectively, and stand for
angular coordinates. The functions λand µare periodic in rwith period 1. It
has been shown in [15] and [16] that due to the symmetry, fcan be written as
a function of
t, r, w := eλp1and F:= t4[(p2)2+ sin2
kθ(p3)2],
i.e. f=f(t, r, w, F). In these variables, we have p0=e−µp1 + w2+F/t2.
The scalar field is a function of tand rwhich is periodic in rwith period 1.
We denote by a dot and by a prime the derivatives of the metric components
and of the scalar field with respect to tand rrespectively. We specify the
regularity properties which we require.
Definition 1.4 Let Ij]0,∞[be an interval and (t, r)∈I×R.
a) f∈C1(I×R2×[0,∞[) is regular if f(t, r + 1, w, F)=f(t, r, w, F)for
(t, r, w, F)∈I×R2×[0,∞[,f≥0and suppf(t, r, ., .)is compact uniformly in
rand locally uniformly in t.
b) µ∈C1(I×R)is regular, if µ0∈C1(I×R)and µ(t, r + 1) =µ(t, r).
c) λ∈C1(I×R)is regular, if ˙
λ∈C1(I×R)and λ(t, r + 1) =λ(t, r).
d) eµ(or φ1,φ2)∈C1(I×R)is regular, if eµ(t, r + 1) =eµ(t, r).
e) ρ(or p,j,q)∈C1(I×R)is regular, if ρ(t, r + 1) =ρ(t, r).
f) φ∈C2(I×R)is regular, if φ(t, r + 1) =φ(t, r).
Lemma 1.5 Let f=f(t, r, w, F )be regular on I×R2×[0,∞[,Ij]0,∞[an
interval; λand µregular on I×R. Then the nontrivial components of the
energy-momentum tensor are:
T00(t, r) = e2µπ
t2Z+∞
−∞ Z+∞
0p1 + w2+F/t2f(t, r, w, F)dFdw+1
2(˙
φ2+e2(µ−λ)φ02)
T11(t, r) = e2λπ
t2Z+∞
−∞ Z+∞
0
w2
p1 + w2+F/t2f(t, r, w, F)dFdw+1
2(e2(λ−µ)˙
φ2+φ02)
8
T01(t, r) = −eλ+µπ
t2Z+∞
−∞ Z+∞
0
wf(t, r, w, F)dFdw +˙
φφ0
T22(t, r) = π
2t2Z∞
−∞ Z∞
0
F
p1 + w2+F/t2f(t, r, w, F)dFdw+1
2t2(e−2µ˙
φ2−e−2λφ02)
T33(t, r, θ) = T22(t, r) sin2
kθ.
Proof: Set Tαβ =Tf
αβ +Tφ
αβ where Tf
αβ and Tφ
αβ are respectively the contri-
bution of fand φto the energy-momentum tensor. Concerning the calculation
of components Tf
αβ, we refer to [15]. We calculate only the components
Tφ
αβ := ∇αφ∇βφ−1
2gαβ∇νφ∇νφ. We have
∇νφ∇νφ=gνα∇νφ∇αφ=g00(∇0φ)2+g11(∇1φ)2=−e−2µ˙
φ2+e−2λφ02. Thus
Tφ
00 =˙
φ2−1
2g00∇νφ∇νφ=1
2(˙
φ2+e2(µ−λ)φ02)
Tφ
01 =∇0φ∇1φ=˙
φφ0
Tφ
11 =φ02−1
2g11∇νφ∇νφ=1
2(e2(λ−µ)˙
φ2+φ02)
Tφ
22 =−1
2g22∇νφ∇νφ=1
2t2(e−2µ˙
φ2−e−2λφ02)
Tφ
33 =Tφ
22 sin2
kθ.
The remaining components being zero.
Following [15], we can now write the complete Einstein-Vlasov-scalar field
system as :
∂tf+eµ−λw
p1 + w2+F/t2∂rf−(˙
λw +eµ−λµ0p1 + w2+F/t2)∂wf= 0 (1.2)
e−2µ(2t˙
λ+ 1) + k= 8πt2ρ(1.3)
e−2µ(2t˙µ−1) −k= 8πt2p(1.4)
µ0=−4πteλ+µj(1.5)
e−2λ(µ00 +µ0(µ0−λ0)) −e−2µ(¨
λ+ ( ˙
λ+1
t)( ˙
λ−˙µ)) = 4πq (1.6)
e−2λφ00 −e−2µ¨
φ−e−2µ(˙
λ−˙µ+2
t)˙
φ−e−2λ(λ0−µ0)φ0= 0 (1.7)
where (1.7) is the wave equation in φand :
ρ(t, r) = e−2µT00(t, r) = π
t2Z+∞
−∞ Z+∞
0p1 + w2+F/t2f(t, r, w, F)dFdw
+1
2(e−2µ˙
φ2+e−2λφ02)
(1.8)
9
p(t, r) = e−2λT11(t, r) = π
t2Z+∞
−∞ Z+∞
0
w2
p1 + w2+F/t2f(t, r, w, F)dFdw
+1
2(e−2µ˙
φ2+e−2λφ02)
(1.9)
j(t, r) = −e−(λ+µ)T01(t, r) = π
t2Z+∞
−∞ Z+∞
0
wf(t, r, w, F)dFdw −e−(λ+µ)˙
φφ0
(1.10)
q(t, r) = 2
t2T22(t, r) = 2
t2sin2
kθT33(t, r, θ)
=π
t4Z∞
−∞ Z∞
0
F
p1 + w2+F/t2f(t, r, w, F)dFdw +e−2µ˙
φ2−e−2λφ02
(1.11)
We are going to study the initial value problem corresponding to this system
with unknowns f,λ,µ,φand prescribe initial data at time t= 1:
f(1, r, w, F) = ◦
f(r, w, F), λ(1, r) = ◦
λ(r), µ(1, r) = ◦
µ(r),
φ(1, r) = ◦
φ(r),˙
φ(1, r) = ψ(r)
The choice t= 1 is made only for convenience. Analogous results hold in the
case that data are prescribed on any hypersurface t=t0>0.
1.2 Auxiliary system and preliminary results
Using characteristic derivatives, we show in this section that the first and second
derivatives of φcan be bounded in terms of λand µ.
Lemma 1.6 Let D+=e−µ∂t+e−λ∂r;D−=e−µ∂t−e−λ∂r;
X=˙
φe−µ−φ0e−λ;Y=˙
φe−µ+φ0e−λ;
a= (−˙
λ−1
t)e−µ−µ0e−λ;b=−e−µ
t;c= (−˙
λ−1
t)e−µ+µ0e−λ
then X,Yare solutions of the system
D+X=aX +bY (1.12)
D−Y=bX +cY (1.13)
Proof: We have
D+X= (e−µ∂t+e−λ∂r)( ˙
φe−µ−φ0e−λ)
=e−µ(−˙µ˙
φe−µ+¨
φe−µ)−e−µ(−˙
λφ0e−λ+˙
φ0e−λ)
+e−λ(−µ0˙
φe−µ+˙
φ0e−µ)−e−λ(−λ0φ0e−λ+φ00e−λ)
=¨
φe−2µ−φ00e−2λ−˙µ˙
φe−2µ+λ0φ0e−2λ+ ( ˙
λφ0−µ0˙
φ)e−µ−λ
10
¿From (1.7), we deduce that
D+X= (µ0φ0−λ0φ0)e−2λ+ ( ˙µ˙
φ−˙
λ˙
φ)e−2µ
−2
t˙
φe−2µ−˙µ˙
φe−2µ+λ0φ0e−2λ+ ( ˙
λφ0−µ0˙
φ)e−µ−λ
=−˙
λ˙
φe−2µ+ ( ˙
λφ0−µ0˙
φ)e−µ−λ−2
t˙
φe−2µ
= [(−˙
λ−1
t)e−µ−µ0e−λ]( ˙
φe−µ−φ0e−λ)−1
t(˙
φe−µ+φ0e−λ)
=aX +bY
If we replace, rby −r(i.e ∂rby −∂r), the wave equation is invariant, Xand Y,
aand c,D+and D−interchange respectively; and we can write the equation
with D−to obtain (1.13)..
The full system above is overdetermined and we will show that a solution
(f, λ, µ, φ) of the subsystem consisting of equations (1.2), (1.3), (1.4) and (1.7)
solves the remaining equations (1.5) and (1.6). Notice that such a solution
determines the right hand side of (1.5) which is then a given function say ˜µ.
Then, since (1.4) already provides µ, an idea introduced in [15], and that we
will follow here, is to replace µ0in (1.2) and (1.7) by an auxiliary function ˜µ,
which is not assumed a priori to be a derivative, and prove later that, under
certain conditions, ˜µis nothing else than µ0. We then introduce the following
auxiliary system obtained by coupling (1.3)-(1.4) to the equations obtained by
replacing µ0by ˜µin (1.2),(1.5) and (1.12)-(1.13), i.e
∂tf+eµ−λw
p1 + w2+F/t2∂rf−(˙
λw +eµ−λ˜µp1 + w2+F/t2)∂wf= 0 (1.14)
˜µ=−4πteλ+µj(1.15)
and
D+X= ˜aX +bY (1.16)
D−Y=bX + ˜cY (1.17)
Where µ0is substituted by eµin aand cto obtain eaand ecrespectively.
Let us estimate the first and second order derivatives of the scalar field φ,
using the characteristic curves of (1.7) and system (1.16)-(1.17).
Proposition 1.7 Let
K0= 2 sup{| ψ(r)|e−◦
µ(r)+|◦
φ0(r)|e−
◦
λ(r);r∈R}
m(t) = sup{| ˙
λ(t, r)|+2
t+|˜µ(t, r)|e(µ−λ)(t,r);r∈R}
K(t) = sup{(|X|2+|Y|2)1
2(t, r) ; r∈R}.
11
If (X, Y )is a solution of (1.16)-(1.17) with
X(1) = e−◦
µ(r)ψ(r)−e−
◦
λ(r)◦
φ0(r)
and
Y(1) = e−◦
µ(r)ψ(r) + e−
◦
λ(r)◦
φ0(r)
then:
1) If t∈]T, 1],T≥0, we have
K(t)≤K0+ 2 Z1
t
m(s)K(s)ds (1.18)
2) If t≥1the analogous estimate holds with the limits tand 1exchanged in the
integral in (1.18).
Proof: The characteristic curves (t, γi), i= 1,2 of the second order partial
differential equation (1.7) satisfy g(u, u) = 0 with u= (1,˙γi,0,0). Then,
−e2µ+e2λ˙γ2
i= 0 and ˙γi=±eµ−λ. Therefore, for any function f,
df
dt (t, γi(t)) = ∂tf+ ˙γi∂rf=∂tf±eµ−λ∂rf
eµ(e−µ∂tf±e−λ∂rf) = eµD+for eµD−f
and we have D+=D−=e−µd
dt on the corresponding characteristic. Then
(1.16)-(1.17) become
(d
dt X(t, γ1(t)) = eµ(˜aX +bY )(t, γ1(t))
d
dt Y(t, γ2(t)) = eµ(bX + ˜cY )(t, γ2(t))
Integrate this system on [t, 1], thus
(X(t, γ1(t)) = X(1, γ1(1)) −R1
teµ(s,γ2(s))(˜aX +bY )(s, γ1(s))ds
Y(t, γ2(t)) = Y(1, γ2(1)) −R1
teµ(s,γ2(s))(bX + ˜cY )(s, γ2(s))ds
Now take the absolute value in each equation and add the two inequalities to
obtain:
|X(t, γ1(t))|+|Y(t, γ2(t))| ≤ |X(1, γ1(1))|+|Y(1, γ2(1))|
+Z1
t
eµ(s,γ1(s))(|˜a||X|+|b||Y|)(s, γ1(s))ds +Z1
t
eµ(s,γ2(s))(|b||X|+|˜c||Y|)(s, γ2(s))ds
≤ |X(1, γ1(1))|+|Y(1, γ2(1))|+Z1
t
eµ(s,γ1(s))[(|˜a|+|b|)(|X|+|Y|)](s, γ1(s))ds
+Z1
t
eµ(s,γ2(s))[(|b|+|˜c|)(|X|+|Y|)](s, γ2(s))ds
12
Take the supremum in space of each term of the above inequality. Now, we have
|X(1, γ1(1))|+|Y(1, γ2(1))| ≤ K0,
(X+Y= 2 ˙
φe−µ
Y−X= 2φ0e−λ
thus (2|˙
φ|e−µ≤ |X|+|Y|
2|φ0|e−λ≤ |X|+|Y|
which implies
4(e−2µ˙
φ2+e−2λφ02)≤2(|X|+|Y|)2, i.e K(s)≤√2
2sup{(|X|+|Y|)(s, r); r∈R}.
Since, (|X|+|Y|)2≤2(|X|2+|Y|2), we have
sup{(|X|+|Y|)(s, r); r∈R} ≤ 2K(s).
And (1.18) follows.
Corollary 1.8 If gφ=Fwhere Fis a continuous function of variables t
and r, then we have the inequality
K(t)≤K0+ 2 Z1
t
[m(s)K(s) + sup{eµ(s,r)|F(s, r)|;r∈R}]ds
Lemma 1.9 Let D+and D−be defined as in Lemma 1.6 and define
X1=e−λ∂rX,Y1=e−λ∂rY;b1= (−2˙
λ−1
t)e−µ−(˜µ+µ0)e−λ;
b2=−e−µ
t;b3=−˙
λ0e−µ−λ+ (λ0˜µ−˜µµ0−˜µ0)e−2λ;
b4= (−2˙
λ−1
t)e−µ+ (˜µ+µ0)e−λ;b5=−˙
λ0e−µ−λ−(λ0˜µ−˜µµ0−˜µ0)e−2λ;
If Xand Ysatisfy (1.16) and (1.17) then X1and Y1satisfy
D+X1=b1X1+b2Y1+b3X(1.19)
D−Y1=b2X1+b4Y1+b5Y(1.20)
Proof: we have by definition,
D+X1= (∂rX)D+e−λ+e−λD+(∂rX) (1.21)
(∂rX)D+e−λ= (∂rX)(e−µ∂t+e−λ∂r)e−λ= (e−λ∂rX)(−˙
λe−µ−λ0e−λ)
= (−˙
λe−µ−λ0e−λ)X1
(1.22)
Next
∂rD+=∂r(e−µ∂t+e−λ∂r) = D+∂r−µ0e−µ∂t−λ0e−λ∂r,
i.e
∂r(D+X) = D+(∂rX)−(µ0e−µ∂t+λ0e−λ∂r)X,
and then
D+(∂rX) = ∂r(D+X)+(µ0e−µ∂t+λ0e−λ∂r)X(1.23)
13
Now we have firstly,
(µ0e−µ∂t+λ0e−λ∂r)X=1
2(µ0+λ0)D+X+1
2(µ0−λ0)D−X
=1
2(µ0+λ0)D+X+1
2(µ0−λ0)(D+X−2X1)
=µ0D+X−(µ0−λ0)X1
i.e
(µ0e−µ∂t+λ0e−λ∂r)X=µ0(˜aX +bY )−(µ0−λ0)X1(1.24)
and secondly,
∂r(D+X) = (∂r˜a)X+ ˜a∂rX+ (∂rb)Y+b∂rY
= (∂r˜a)X+ ˜aeλX1+ (∂rb)Y+beλY1
i.e
∂r(D+)X= ˜aeλX1+beλY1+[−˙
λ0e−µ+µ0(˙
λ+1
t)e−µ−˜µ0e−λ+˜µλ0e−λ]X+µ0
te−µY
(1.25)
Substituting (1.25) and (1.24) in (1.23) gives
D+(∂rX) = ˜aeλX1+beλY1+ [−˙
λ0e−µ+µ0(˙
λ+1
t)e−µ−˜µ0e−λ+ ˜µλ0e−λ]X
+µ0
te−µY+µ0(˜aX +bY )−(µ0−λ0)X1
= ˜aeλX1+beλY1+ [−˙
λ0e−µ+µ0(˙
λ+1
t)e−µ−˜µ0e−λ+ ˜µλ0e−λ]X
+µ0
te−µY+ [(−µ0˙
λ−µ0
t)e−µ−˜µµ0e−λ]X−µ0
te−µY−(µ0−λ0)X1
i.e
D+(∂rX) = (˜aeλ−µ0+λ0)X1+beλY1+ (−˙
λ0e−µ−˜µµ0e−λ−˜µ0e−λ+ ˜µλ0e−λ)X
(1.26)
Substituting (1.26) and (1.22) in (1.21) gives
D+X1= (−˙
λe−µ−λ0e−λ)X1+ [˜a+ (−µ0+λ0)e−λ]X1+bY1+ (−˙
λ0e−µ−˜µµ0e−λ
−˜µ0e−λ+ ˜µλ0e−λ)e−λX
= (−˙
λe−µ+ ˜a−µ0e−λ)X1+bY1+ [−˙
λ0e−µ−λ+ (−˜µµ0−˜µ0+ ˜µλ0)e−2λ]X
and equation (1.19) follows. If we replace e−λby −e−λ, the wave equation
is invariant, D+and D−,X1and −Y1,b1and b4,−b3and b5interchange
respectively; and we can write equation (1.20).
14
Proposition 1.10 Let K(t)be defined as in Proposition 1.7 and set:
A0= 2 sup{[(|ψ0|+|◦
µ0|| ψ|)e−◦
µ−
◦
λ+ (|◦
φ00 |+|◦
λ0|| ◦
φ0|)e−2
◦
λ](r) ; r∈R}
A(t) = sup{[X2
1+Y2
1]1/2(t, r) ; r∈R}
v(t) = sup{2
t+ 2 |˙
λ|+(|˜µ|+|µ0|)eµ−λ(t, r) ; r∈R}
h(t) = sup{[|˙
λ0|e−λ+ (|µ0|| ˜µ|+|λ0|| ˜µ|+|˜
µ0|)eµ−2λ](t, r) ; r∈R}
If in addition to the assumptions of Proposition 1.7 the quantities X1and Y1
satisfy (1.19) and (1.20) and agree with e−λ∂rXand e−λ∂rYrespectively for
t= 1 then
1) If t∈]T, 1],T≥0, we have the estimate
A(t)≤A0+ 2 Z1
t
(v(s)A(s) + h(s)K(s))ds (1.27)
2) If t≥1the analogous estimate holds with the limits tand 1exchanged in
the integral in (1.27).
Proof: Analogous to the proof of Proposition 1.7, using this time Lemma
1.9.
Note that the factor e−λin the definition of X1and Y1is very important.
Without it the above derivation would not work since the derivative λ0would
occur in b1and b4.
Lemma 1.11 Let D+and D−be defined as in lemma 1.6 and define
X2=eµX,Y2=eµY. If Xand Yhold system (1.12)-(1.13) and the field
equations (1.3)-(1.4) are satisfied, then X2and Y2satisfy
D+X2=eµ[k
t−4πt(ρ−p)]X2−e−µ
tY2(1.28)
D−Y2=−e−µ
tX2+eµ[k
t−4πt(ρ−p)]Y2(1.29)
Proof: We have
D+X2=D+(eµX) = eµD+X+ (D+eµ)X
=eµ[(−˙
λ−1
t)e−µ−µ0e−λ]X−Y
t+ ( ˙µ+µ0eµ−λ)X
= ( ˙µ−˙
λ−1
t)X−Y
t
=e−µ( ˙µ−˙
λ−1
t)X2−e−µ
tY2
15
Subtract the field equations (1.3) and (1.4) to obtain
2te−2µ(˙
λ−˙µ)+2k−2e−2µ= 8πt2(ρ−p)
i.e
˙µ−˙
λ=ke2µ+ 1
t−4πte2µ(ρ−p).
Substituting this into the above equation gives (1.28). If we replace ∂rby −∂r,
the wave equation is invariant, D+and D−,X2and Y2interchange respectively
and we can write equation (1.29).
Remark 1.12 Let
B0= 2 sup{(|X2|+|Y2|)(1, r) ; r∈R}
B(t) = sup{(|X2|2+|Y2|2)1/2(t, r) ; r∈R}
l(t) = sup{1
t+e2µ[|k|
t+ 4πt(ρ−p)](t, r) ; r∈R}
If (X2, Y2)is solution of (1.28)-(1.29), then we obtain analogously to (1.18),
the estimate
B(t)≤B0+ 2 Z1
t
l(s)B(s)ds (1.30)
with t∈]T, 1],T > 0or t≥1.
1.3 The reduced system
We first solve each equation of the auxiliary system introduced in the previous
section, when the other unknowns are fixed (in the form to be used later for the
iteration). In order to clarify our statements, we introduce the notations φ1,φ2
in place of ˙
φ,φ0.
Proposition 1.13 1) Let ¯
f,¯
λ,¯µ,˜µ,¯
φ1,¯
φ2be regular for (t, r)∈I×R,
I⊂]0,∞[. Substitute f,λ,µ,˙
φ,φ0respectively by ¯
f,¯
λ,¯µ,¯
φ1,¯
φ2in ρand p
to define ¯ρand ¯p. Suppose that 1∈I,◦
f∈C1(R2×[0,∞)),◦
λ,◦
µ∈C1(R)and
are periodic of period 1in r. Assume that:
e−2◦
µ(r)+k
t−k+8π
tZ1
t
s2¯p(s, r)ds > 0,(t, r)∈I×R(1.31)
then the system
∂tf+e¯µ−¯
λw
p1 + w2+F/t2∂rf−(˙
¯
λw +e¯µ−¯
λ˜µp1 + w2+F/t2)∂wf= 0 (1.32)
e−2µ(2t˙
λ+ 1) + k= 8πt2¯ρ(1.33)
16
e−2µ(2t˙µ−1) −k= 8πt2¯p(1.34)
has a unique regular solution (f, λ, µ)on I×Rwith f(1) = ◦
f,λ(1) = ◦
λ,
µ(1) = ◦
µ. This solution is given by
f(t, r, w, F) = ◦
f((R, W)(1, t, r, w, F), F ) (1.35)
where (R, W )is the solution of the characteristic system
d
ds(r, w) = ( e¯µ−¯
λw
p1 + w2+F/t2,−˙
¯
λw −e¯µ−¯
λ˜µp1 + w2+F/t2) (1.36)
satisfying (R, W)(t, t, r, w, F) = (r, w);
e−2µ(t,r)=e−2◦
µ(r)+k
t−k+8π
tZ1
t
s2¯p(s, r)ds (1.37)
˙
λ(t, r) = 4πte2µ¯ρ(t, r)−1 + ke2µ(t, r)
2t(1.38)
λ(t, r) = ◦
λ(r)−Z1
t
˙
λ(s, r)ds (1.39)
If I=]T, 1] (respectively I= [1, T[) with T∈[0,1[ (respectively T∈]1,∞[), then
there exists some T∗∈[T, 1] (respectively T∗∈]1, T]) such that condition (1.31)
holds on ]T∗,1]×R(respectively [1, T∗[×R). T∗is independent of ¯pif I=]T, 1],
whereas it depends on ¯pif I= [1, T [.
2) Let λ,µ,¯
λ,¯µbe regular; let C,Dbe regular as ˜µ(see definition 1.4).
Set
X=φ1e−µ−φ2e−λ, Y =φ1e−µ+φ2e−λ(1.40)
and define the operators ¯
D+,¯
D−as D+,D−in Lemma 1.6, with λ,µsubsti-
tuted respectively by ¯
λ,¯µ. Assume that ψ∈C1(R),◦
φ∈C2(R)are periodic of
period 1. Then the system ¯
D+X=C(1.41)
¯
D−Y=D(1.42)
has a unique regular solution (φ1, φ2) such that (φ1, φ2)(1) = (ψ, ◦
φ0).
Proof: 1) the proof of this point is the same as that of Proposition 2.4 in [15].
The only thing added is the existence of T∗we now prove and that will replace
in the case of local existence, the hypothesis ◦
µ≤0 if k=−1 in [15].
If I=]T, 1]; since ¯p≥0, the left hand side of (1.31) is bounded from below by
h(t, r) = e−2◦
µ(r)+k
t−k. If k∈ {0,1}, we have, since 1
t≥1, h(t, r)≥e−2◦
µ(r)>0
and we can take T∗=T. If k=−1, since ◦
µis bounded, there exists β > 0,
17
such that h(1, r) = e−2◦
µ(r)> β. By the continuity of t7→ h(t, r) at t= 1, we
conclude that:
∃T∗∈]T, 1] such that e−2µ(t,r)≥h(t, r)>β
2, t ∈]T∗,1] and ¯p≥0.(1.43)
If I= [1, T[, define h(t, r) to be all the left hand side of (1.31) and proceed as
above in the case k=−1, to obtain T∗that depends this time on ¯p.
2) The system (1.41)-(1.42) in (X, Y ) is a first order linear hyperbolic sys-
tem, and the existence of a unique solution with the prescribed data (X, Y )(1) =
(e−◦
µψ−e−
◦
λ◦
φ0, e−◦
µψ+e−
◦
λ◦
φ0) is given by a theorem of Friedrichs [10]. (See also
the paper of Douglis [9] where existence of C1solutions of hyperbolic systems
in one space dimension was proved for C1initial data in the more general quasi-
linear case.) We then deduce from the relations (1.40) that define a bijection
(X, Y )7→ (φ1, φ2), the existence of a unique regular solution (φ1, φ2) of (1.41)-
(1.42) such that (φ1, φ2)(1) = (ψ, ◦
φ0). This completes the proof of Proposition
1.13.
In fact, since the equations for Xand Yare decoupled, it is not necessary
to use existence results for hyperbolic systems in the above proof; it suffices to
solve a parameter-dependent ordinary differential equation. The above proce-
dure has the advantage that it can easily be generalized to problems where the
corresponding equations are coupled as they are, for instance, in the case of a
nonlinear scalar field.
Now we show that the solution of the subsystem consisting of equations
(1.2), (1.3), (1.4) and (1.7) also satisfies equations (1.5) and (1.6), and that the
auxiliary system is equivalent to the full system.
Proposition 1.14 1) Let (f, λ, µ, φ)be a regular solution of (1.2), (1.3), (1.4)
and (1.7) on some time interval I∈]0,∞[with 1∈I, and let the initial data
satisfy (1.5) for t= 1 with ◦
φ, ψ ∈C1(R), in particular ◦
µ∈C2(R). Then (1.5)
and (1.6) hold for all t∈I, in particular µ∈C2(I×R).
2) Let (f, λ, µ, ˜µ, φ1, φ2)be a regular solution of equations (1.14),(1.3), (1.4),
(1.15), (1.16) and (1.17) with the initial data (f, λ, µ, φ1, φ2)(1) = (◦
f, ◦
λ, ◦
µ, ψ, ◦
φ0)
that are as in proposition 1.13 and satisfy (1.5) for t= 1. Then there exists a
unique regular function φsatisfying φ(1) = ◦
φ,˙
φ(1) = ψsuch that (f, λ, µ, φ)
solves the full system (1.2)-(1.11). The function φis given by:
φ(t, r) = ◦
φ(r) + Rt
1φ1(s, r)ds.
18
Proof: 1) Firstly, we prove that (1.5) holds. ¿From equations (1.9), (1.2), (1.7)
and integration by parts, it follows that, since supp f(t, r, ., .) is compact :
Zt
1
p0(s, r)s2ds =πZt
1Z∞
−∞ Z∞
0
w2
p1 + w2+F/s2∂rf(s, r, w, F)dFdwds
+Zt
1
(−µ0˙
φ2e−2µ−λ0φ02e−2λ+˙
φ0˙
φe−2µ+φ0φ00e−2λ)s2ds
=πZt
1Z∞
−∞ Z∞
0
[−eλ−µw∂tf+ ( ˙
λw2eλ−µ+µ0wp1 + w2+F/t2)∂wf]dFdwds
+Zt
1
[−µ0˙
φ2e−2µ−λ0φ02e−2λ+˙
φ0˙
φe−2µ+φ0¨
φe−2µ+ ( ˙
λ−˙µ)φ0˙
φe−2µ
+2
sφ0˙
φe−2µ+ (λ0−µ0)e−2λφ02]s2ds
=πZ∞
−∞ Z∞
0
[−eλ−µwf]s=t
s=1dFdw +πZt
1Z∞
−∞ Z∞
0
(˙
λ−˙µ)eλ−µwfdFdwds
+πZt
1Z∞
0
[( ˙
λw2eλ−µ+µ0wp1 + w2+F/t2)f]∞
−∞dFds
−πZt
1Z∞
−∞ Z∞
0
(2 ˙
λweλ−µ+µ0p1 + w2+F/t2+µ0w2
p1 + w2+F/s2)fdFdwds
+Zt
1
[−µ0˙
φ2e−2µ−µ0e−2λφ02+˙
φ0˙
φe−2µ+φ0¨
φe−2µ+ ( ˙
λ−˙µ)φ0˙
φe−2µ]ds +Zt
1
2sφ0˙
φe−2µds
i.e
Zt
1
p0(s, r)s2ds =πZ∞
−∞ Z∞
0
[−eλ−µwf]s=t
s=1dFdw −πZt
1Z∞
−∞ Z∞
0
(˙
λ+ ˙µ)eλ−µwfdFdwds
−πZt
1Z∞
−∞ Z∞
0
µ0(p1 + w2+F/t2+w2
p1 + w2+F/s2)fdFdwds
+Zt
1
[−µ0˙
φ2e−2µ−µ0e−2λφ02+˙
φ0˙
φe−2µ+φ0¨
φe−2µ+ ( ˙
λ−˙µ)φ0˙
φe−2µ]ds + [s2φ0˙
φe−2µ]s=t
s=1
−Zt
1
s2(−2 ˙µφ0˙
φe−2µ+φ0¨
φe−2µ+˙
φ0˙
φe−2µ)ds
=πZ∞
−∞ Z∞
0
[−eλ−µwf]s=t
s=1dFdw −πZt
1Z∞
−∞ Z∞
0
(˙
λ+ ˙µ)eλ−µwfdFdwds
−πZt
1Z∞
−∞ Z∞
0
µ0(p1 + w2+F/t2+w2
p1 + w2+F/s2)fdFdwds
+ [s2φ0˙
φe−2µ]s=t
s=1 +Zt
1
(˙
λ+ ˙µ)φ0˙
φe−2µ−Zt
1
µ0(˙
φ2e−2µ+φ02e−2λ)s2ds
19
Therefore,
Zt
1
p0(s, r)s2ds = [−eλ−µj(s, r)s2]s=t
s=1−Zt
1
(˙
λ+ ˙µ)eλ−µj(s, r)s2ds−Zt
1
µ0(ρ+p)(s, r)s2ds
(1.44)
Adding equations (1.3) and (1.4), we have
˙
λ+ ˙µ= 4πte2µ(ρ+p).(1.45)
¿From equation (1.4), we obtain
e−2µ(t,r)=e−2◦
µ(r)+k
t−k+8π
tZ1
t
s2p(s, r)ds
and differentiating this with respect to r, yields :
tµ0e−2µ=◦
µ0e−2◦
µ+ 4πZt
1
s2p0(s, r)ds (1.46)
Substituting for the last integral by (1.44), using (1.45) and assuming the fact
that the constraint equation (1.5) holds for t= 1, relation (1.46) implies
−te2µ(µ0+ 4πeλ+µjt) = 4πZt
1
(ρ+p)s2(µ0+ 4πeλ+µjs)ds
and since the left hand side is zero at t= 1, we obtain
µ0+ 4πteλ+µj= 0
on I, i.e (1.5) holds for all t∈I. In particular this relation shows that µis C2
with respect to rwith
µ00 = (λ0+µ0)µ0−4πteλ+µj0.
Now we prove that equation (1.6) holds. From (1.10), (1.2), (1.7) and integration
by parts we obtain the identity
j0(t, r) = π
t2eλ−µZ∞
−∞ Z∞
0
[−p1 + w2+F/t2∂tf
+ ( ˙
λwp1 + w2+F/t2+eµ−λµ0(1 + w2+F/t2))∂wf]dFdw
+ (λ0+µ0)e−(λ+µ)˙
φφ0−e−(λ+µ)(˙
φ0φ0+˙
φφ00)
=−π
t2eλ−µZ∞
−∞ Z∞
0p1 + w2+F/t2∂tfdFdw
+π
t2eλ−µZ∞
0
[( ˙
λwp1 + w2+F/t2+eµ−λµ0(1 + w2+F/t2))f]∞
−∞
−π
t2eλ−µZ∞
−∞ Z∞
0
[˙
λp1 + w2+F/t2+˙
λw2
p1 + w2+F/t2+eµ−λµ02w]fdFdw
+ 2µ0e−(λ+µ)˙
φφ0−e−(λ+µ)˙
φ0φ0−eλ−3µ[˙
φ¨
φ+ ( ˙
λ−˙µ+2
t)˙
φ2]
20
i.e
j0(t, r) = −π
t2eλ−µZ∞
−∞ Z∞
0p1 + w2+F/t2∂tfdFdw −2µ0π
t2Z∞
−∞ Z∞
0
wfdFdw
−˙
λeλ−µπ
t2Z∞
−∞ Z∞
0
(p1 + w2+F/t2+w2
p1 + w2+F/t2)fdFdw
+ 2µ0e−(λ+µ)˙
φφ0−e−(λ+µ)˙
φ0φ0−eλ−3µ[˙
φ¨
φ+ ( ˙
λ−˙µ+2
t)˙
φ2]
=−π
t2eλ−µZ∞
−∞ Z∞
0p1 + w2+F/t2∂tfdFdw −2µ0π
t2Z∞
−∞ Z∞
0
wfdFdw
−˙
λeλ−µ(ρ+p−˙
φ2e−2µ
−φ02e−2λ)+2µ0e−(λ+µ)˙
φφ0−e−(λ+µ)˙
φ0φ0−eλ−3µ[˙
φ¨
φ+ ( ˙
λ−˙µ+2
t)˙
φ2]
=−π
t2eλ−µZ∞
−∞ Z∞
0p1 + w2+F/t2∂tfdFdw −˙
λeλ−µ(ρ+p−˙
φ2e−2µ
−φ02e−2λ)−2µ0j−e−(λ+µ)˙
φ0φ0−e−3µ+λ(˙
φ¨
φ−(˙
λ−˙µ+2
t)˙
φ2).
Since by (1.8)
˙ρ(t, r) = −2π
t3Z∞
−∞ Z∞
0p1 + w2+F/t2fdFdw
+π
t2Z∞
−∞ Z∞
0p1 + w2+F/t2∂tfdFdw
+π
t2Z∞
−∞ Z∞
0
(−F
t3)f
p1 + w2+F/t2dFdw
+e−2µ(−˙µ˙
φ2+˙
φ¨
φ) + e−2λ(−˙
λφ02+˙
φ0φ0)
=−2ρ
t+1
t(e−2µ˙
φ2+e−2λφ02)−q
t+1
t(e−2µ˙
φ2−e−2λφ02)
+π
t2Z∞
−∞ Z∞
0p1 + w2+F/t2∂tfdFdw +e−2µ(−˙µ˙
φ2+˙
φ¨
φ) + e−2λ(−˙
λφ02+˙
φ0φ0)
=−2ρ
t−q
t+2e−2µ
t˙
φ2+e−2µ(−˙µ˙
φ2+˙
φ¨
φ) + e−2λ(−˙
λφ02+˙
φ0φ0)
+π
t2Z∞
−∞ Z∞
0p1 + w2+F/t2∂tfdFdw ;
¿From (1.3) we obtain
˙
λ(t, r) = 4πte2µρ(t, r)−1 + ke2µ(t, r)
2t
21
and differentiating with respect to tyields:
¨
λ= 4πe2µρ+ 8πt ˙µe2µρ+1 + ke2µ
2t2+ 4πte2µ˙ρ−k˙µe2µ
t
= 4πe2µρ+ 2 ˙µ(˙
λ+1 + ke2µ
2t)−˙µ
tke2µ+1 + ke2µ
2t2
+ 4πte2µ{−2ρ
t−q
t+2
te−2µ˙
φ2+e−2µ(−˙µ˙
φ2+˙
φ¨
φ) + e−2λ(−˙
λφ02+˙
φ0φ0)}
+ 4π2
te2µZ∞
−∞ Z∞
0p1 + w2+F/t2∂tfdFdw
=˙µ−˙
λ
t−4πqe2µ+ 2 ˙
λ˙µ+ 8π˙
φ2+ 4πt(−˙µ˙
φ2+˙
φ¨
φ)+4πte2µ−2λ(−˙
λφ02+˙
φ0φ0)
+ 4π2
te2µZ∞
−∞ Z∞
0p1 + w2+F/t2∂tfdFdw.
Combining all these relations gives :
e−2λ(µ00 +µ0(µ0−λ0)) −e−2µ(¨
λ+ ( ˙
λ+1
t)( ˙
λ−˙µ)) = e−2λ[µ0(µ0+λ0)−4πteµ+λj0+µ0(µ0−λ0)]
−e−2µ{˙µ−˙
λ
t−4πqe2µ+ 2 ˙
λ˙µ+ 8π˙
φ2+ 4πt(−˙µ˙
φ2+˙
φ¨
φ)+4πte2µ−2λ(−˙
λφ02+˙
φ0φ0)
+ 4π2
te2µZ∞
−∞ Z∞
0p1 + w2+F/t2∂tfdFdw + ( ˙
λ+1
t)( ˙
λ−˙µ)}
= 2µ02e−2λ−e−2λ4πteλ+µ{−π
t2eλ−µZ∞
−∞ Z∞
0p1 + w2+F/t2∂tfdFdw
−eλ−µ˙
λ(ρ+p) + eλ−3µ˙
λ˙
φ2+e−λ−µ˙
λφ02−2µ0j−e−(λ+µ)˙
φ0φ0−eλ−3µ¨
φ˙
φ−eλ−3µ(˙
λ−˙µ+2
t)˙
φ2}
−e−2µ[−˙
λ
t−4πqe2µ+ 2 ˙
λ˙µ+˙µ
t+ 8π˙
φ2+ 4πt(−˙µ˙
φ2+˙
φ¨
φ)+4πte2µ−2λ(−˙
λφ02+˙
φ0φ0)
+ 4π2
te2µZ∞
−∞ Z∞
0p1 + w2+F/t2∂tfdFdw]−e−2µ(˙
λ+1
t)( ˙
λ−˙µ)
= 2µ02e−2λ+˙
λ(ρ+p)4πt + 8πtµ0eµ−λj+˙
λ
te−2µ+ 4πq −2e−2µ˙
λ˙µ−˙µ
te−2µ−e−2µ(˙
λ+1
t)( ˙
λ−˙µ))
= 2µ02e−2λ+˙
λ(˙
λ+ ˙µ)e−2µ+ 8πtµ0eµ−λ(−1
4πte−µ−λµ0) + ˙
λ
te−2µ+ 4πq −2e−2µ˙
λ˙µ−˙µ
te−2µ−e−2µ˙
λ2
+e−2µ˙
λ˙µ−˙
λ
te−2µ+˙µ
te−2µ
= 4πq
2) subtract the two equations (1.16)-(1.17) to obtain
˙
φ2−φ0
1= (˜µ−µ0)φ1(1.47)
Let us first prove that µ0= ˜µ. Consider equation (1.44) and write p=p1+p2
where p1and p2are the contributions to pmade by fand φrespectively. We
22
obtain from [15] that studies the case φ= 0, and in which pcorresponds to p1
here, using definitions (1.8), (1.9) and (1.10) of ρ,p,j:
Zt
1
s2p0
1(s, r)ds =−Zt
1
(˙
λ+ ˙µ)eλ−µs2(j+e−λ−µφ1φ2)ds −[eλ−µs2(j+e−λ−µφ1φ2)]t
1
−Zt
1
˜µ[(ρ+p)−(e−2µφ2
1+e−2λφ2
2)]s2ds
We have
D+(φ1e−µ−φ2e−λ) = ˙
φ1e−2µ−φ0
2e−2λ−˙µφ1e−2µ+λ0φ2e−2λ+( ˙
λφ2−µ0φ1+φ0
1−˙
φ2)e−µ−λ
¿From (1.16),
D+(φ1e−µ−φ2e−λ) = (−˙
λ−2
t)φ1e−2µ+˙
λφ2e−µ−λ−˜µe−µ−λφ1+ ˜µe−2λφ2
We deduce from these two relations that
φ0
2e−2λ=˙
φ1e−2µ−˙µφ1e−2µ+λ0φ2e−2λ−µ0φ1e−µ−λ
+ (φ0
1−˙
φ2)e−µ−λ−(−˙
λ−2
t)φ1e−2µ+ ˜µe−µ−λφ1−˜µe−2λφ2
Then,
Zt
1
s2p0
2(s, r)ds =Zt
1
s2(−µ0φ2
1e−2µ−λ0φ2
2e−2λ+φ0
1φ1e−2µ+φ0
2φ2e−2λ)ds
=Zt
1
s2[−µ0φ2
1e−2µ−λ0φ2
2e−2λ+φ0
1φ1e−2µ
+φ2(˙
φ1e−2µ−˙µφ1e−2µ+λ0φ2e−2λ−µ0φ1e−µ−λ
+ (φ0
1−˙
φ2)e−µ−λ−(−˙
λ−2
t)φ1e−2µ+ ˜µe−µ−λφ1−˜µe−2λφ2)]ds
=Zt
1
s2[−µ0φ2
1e−2µ+φ0
1φ1e−2µ+φ2˙
φ1e−2µ+ ( ˙
λ−˙µ)e−2µφ1φ2
+ (φ0
1−˙
φ2)φ2e−µ−λ+ (˜µ−µ0)φ1φ2e−µ−λ−˜µe−2λφ2
2]ds +Zt
1
2sφ1φ2e−2µds
23
Integrate the last term of this relation by parts and using (1.47), we obtain
Zt
1
s2p0
2(s, r)ds =Zt
1
s2[−µ0φ2
1e−2µ+φ0
1φ1e−2µ+φ2˙
φ1e−2µ+ ( ˙
λ−˙µ)e−2µφ1φ2
+ (φ0
1−˙
φ2)φ2e−µ−λ+ (˜µ−µ0)φ1φ2e−µ−λ−˜µe−2λφ2
2]ds + [s2φ1φ2e−2µ]t
1
−Zt
1
s2(−2 ˙µφ1φ2e−2µ+˙
φ1φ2e−2µ+φ1˙
φ2e−2µ)ds
= [s2φ1φ2e−2µ]t
1+Zt
1
[( ˙
λ+ ˙µ)e−2µφ1φ2+ (φ0
1φ1−φ1˙
φ2)e−2µ
+ (φ0
1−˙
φ2)φ2e−µ−λ−µ0φ2
1e−2µ−˜µφ2
2e−2λ+ (˜µ−µ0)φ1φ2e−µ−λ]s2ds
= [s2φ1φ2e−2µ]t
1+Zt
1
[( ˙
λ+ ˙µ)e−2µφ1φ2+ (φ0
1−˙
φ2)(φ1e−2µ+φ2e−µ−λ)
−µ0φ2
1e−2µ−˜µφ2
2e−2λ+ (˜µ−µ0)φ1φ2e−µ−λ]s2ds
= [s2φ1φ2e−2µ]t
1+Zt
1
[( ˙
λ+ ˙µ)e−2µφ1φ2−˜µ(φ2
1e−2µ+φ2
2e−2λ)]s2ds
Then, using (1.45),
Zt
1
s2p0
2(s, r)ds = [−eλ−µjs2]t
1−Zt
1
4πeλ+µjs(ρ+p)s2ds −Zt
1
˜µ(ρ+p)s2ds
(1.46) becomes :
tµ0e−2µ=◦
µ0e−2◦
µ+ 4π(e
◦
λ−◦
µ◦
j−eλ−µjt2)+4πZt
1
(4πseλ+µj+ ˜µ)(ρ+p)s2ds
and using the definition (1.15) of ˜µ:
tµ0e−2µ=e−2◦
µ(◦
µ0+ 4πe
◦
λ+◦
µ◦
j) + t˜µe−2µfor all t∈I⊂]0,∞[,
Hence, if (1.5) holds for t= 1, then, tµ0e−2µ=t˜µe−2µand µ0= ˜µ.
Now we prove the existence of φ. Define φby : φ(t, r) = ◦
φ(r)+Rt
1φ1(s, r)ds.
Then φ(1) = ◦
φ,˙
φ(1) = φ1(1) = ψand ˙
φ=φ1. Now (1.47) implies, since
µ0= ˜µ, that ˙
φ2=φ0
1, hence the relation φ2(1) = ◦
φ0implies φ0=φ2.
The relation µ0= ˜µalso implies that the systems (1.12)-(1.13) and (1.16)-(1.17)
are identical. Then a direct calculation, using the fact that (φ1, φ2) satisfies the
system (1.12)-(1.13) shows that φsatisfies (1.7).
We conclude this section with a proposition dealing with the solvability of the
constraint equation (1.5) for t= 1. Let ˜
ψ=e−µψ.
Proposition 1.15 Given a function ◦
λ(r), a non-negative function ¯
f(r, w, F)
and functions ◦
φ(r)and ˜
ψ(r), all periodic in rand regular, there exists a function
24
◦
µ(r), periodic in rand regular, such that the constraint equation
◦
µ0=−4πe
◦
λ+◦
µ◦
j
holds for a non-negative function ◦
f. It can be assumed that ◦
f=¯
f+aΦ, where
Φ(r, w, F)is a fixed function, independent of the particular choice of input data,
and ais a suitable constant.
Proof: This can be proved just as in [27], with Φ chosen as in that reference.
This result shows that it is possible to produce a plentiful supply of initial data.
It cannot be applied to produce data with f= 0. A way of doing that is to
adjust ˜
ψ=¯
ψ+bΦ (bis a suitable constant) instead of adjusting f. Φ(r)≥0
and suppΦ ⊂I,Ian interval in which ∂r◦
φ(r)6= 0.
Remark 1.16 1) The two previous propositions show that the coupled system
(1.2)-(1.3)-(1.4)-(1.5)-(1.6)-(1.7) reduces to the subsystem (1.14), (1.3), (1.4),
(1.15), (1.16), (1.17) on which we concentrate in the next chapter.
2) In the following, only one norm on function spaces is used, namely the L∞-
norm, which is denoted by ||.||. For example if f∈Ck(I×[0,∞[), we define
||f(t)|| = sup{|f(t, r)|, r ∈[0,∞[}.
25
Chapter 2
Local existence and
continuation of solutions
In this chapter using an iteration we prove the local existence and uniqueness of
solutions of the Einstein-Vlasov-scalar field system together with continuation
criteria.
2.1 Iteration
Let us first use the solution (f, λ, µ, ˜µ, φ1, φ2) of the auxiliary system consisting
of the equations (1.14), (1.3), (1.4), (1.15), (1.16) and (1.17), to construct a
sequence of iterative solutions as follows. Define ◦
˜µ:= ◦
µ0,λ0(t, r) := ◦
λ(r),
µ0(t, r) := ◦
µ(r), ˜µ0(t, r) := ◦
˜µ(r), g0(t, r) = ψ(r), h0(t, r) = ◦
φ0for t∈]0,1],
r∈R. If λn−1,µn−1, ˜µn−1are already defined and regular on ]T∗,1] ×Rthen
let
Gn−1(t, r, w, F):= weµn−1−λn−1
p1 + w2+F/t2,−˙
λn−1w−eµn−1−λn−1˜µn−1p1 + w2+F/t2!
(2.1)
and denote by (Rn, Wn)(s, t, r, w, F) the solution of the characteristic system
d
ds(R, W) = Gn−1(s, R, W, F)
with initial data
(Rn, Wn)(t, t, r, w, F) = (r, w); (t, r, w, F)∈]0,1] ×R2×[0,∞[ ;
note that Fis constant along characteristics. Define
fn(t, r, w, F) := ◦
f((Rn, Wn)(1, t, r, w, F), F),(2.2)
26
that is, fnis the solution of
∂tfn+weµn−1−λn−1
p1 + w2+F/t2∂rfn−(˙
λn−1w+eµn−1−λn−1˜µn−1p1 + w2+F/t2)∂wfn= 0
(2.3)
with fn(1) = ◦
f. Define ρn,pn,jn,qnby the formulas (1.8), (1.9), (1.10) and
(1.11) with f,λ,µ,˙
φ,φ0respectively replaced by fn,λn−1,µn−1,gn−1,hn−1,
(n≥1). Using Proposition 1.13, 1), define µnand λnto be the solutions of
e−2µn(t,r)=e−2◦
µ(r)+k
t−k+8π
tZ1
t
s2pn(s, r)ds (2.4)
˙
λn(t, r) = 4πte2µn(t,r)ρn(t, r)−1 + ke2µn
2t(2.5)
λn(t, r) = ◦
λ(r)−Z1
t
˙
λn(s, r)ds (2.6)
and set
˜µn(t, r) = −4πte(µn+λn)(t,r)jn(t, r) (2.7)
Notice that, by Proposition 1.13, the right hand side of (2.4) is positive on
]T∗,1], ∀n. Now define gnand hnusing Proposition 1.13, 2) to satisfy the
conditions that the quantities
Xn=e−µngn−e−λnhn, Yn=e−µngn+e−λnhn
are solutions of the system
D+
n−1Xn=an−1Xn−1+bn−1Yn−1(2.8)
D−
n−1Yn=bn−1Xn−1+cn−1Yn−1(2.9)
where D+
n−1,D−
n−1,an−1,bn−1and cn−1are defined in the same way as D+,
D−, ˜a,b, ˜c(see Lemma 1.6), with µ,λ,˙
φ,φ0, ˜a,b, ˜csubstituted respectively
by µn−1,λn−1,gn−1,hn−1,an−1,bn−1,cn−1. Now K0and A0being defined in
Propositions 1.7 and 1.10, we introduce the following quantities that are similar
to those defined in those propositions:
Kn(t) = sup{(g2
ne−2µn+h2
ne−2λn)1
2(t, r) ; r∈R}
An(t) = sup{e−λn[(g0
n−µ0
ngn)2e−2µn+ (h0
n−λ0
nhn)2e−2λn]1/2(t, r) ; r∈R}
mn−1(t) = sup{2
t+ (|˙
λn−1|+|˜µn−1|eµn−1−λn−1)(t, r) ; r∈R}
vn−1(t) = sup{2
t+ 2 |˙
λn−1|+(|˜µn−1|+|µ0
n−1|)eµn−1−λn−1(t, r) ; r∈R}
βn−1(t) = sup{[|˙
λ0
n−1|e−λn−1+ (|µ0
n−1|| ˜µn−1|+|λ0
n−1|| ˜µn−1|
+|˜µ0
n−1|)eµn−1−2λn−1](t, r) ; r∈R}
(2.10)
27
Now we proceed for (2.8)-(2.9) the same way as we did for (1.16)-(1.17) to
establish the inequality (1.18) and we obtain the following analogous inequality:
Kn(t)≤K0+ 2 Z1
t
mn−1(s)Kn−1(s)ds (2.11)
We can use (2.8)-(2.9) to establish a system for (e−λn−1∂rXn, e−λn−1∂rYn) anal-
ogous to (1.19)-(1.20) from which we deduce the following inequality which is
analogous to (1.27)
An(t)≤A0+ 2 Z1
t
(vn−1(s)An−1(s) + βn−1(s)Kn−1(s))ds (2.12)
Throughout the document, we use the fact that by (2.2), kfn(t)k=k◦
fkfor
n∈Nand t∈]T∗,1]. The numerical constant Cmay change from line to line
and does not depend on nor tor the initial data. In order to prove the local
existence theorem, we prove respectively in the next two propositions :
- a uniform bound on the momenta in the support of distribution functions fn,
and a uniform bound of the first derivatives with respect to rof the functions
fn,λn,µn,gn,hn;
- the convergence of the iterates.
Proposition 2.1 We take ◦
fas in proposition 1.13 and such that
supp◦
f⊂[0, W0]×[0, F0], W0>0, F0>0.(2.13)
then there exist nonnegative constants T1, T2such that the quantities
Qn(t) = sup{| w|; (r, w, F)∈suppfn(t)}for all t ∈[T1,1].
Bn(t) = sup{k ∂rfn(s)k+A2
n−1(s); t≤s≤1}for all t ∈[T2,1].
and Kn(t)for all t∈[T1,1] are uniformly bounded in n.
Proof: Firstly we bound Qn(t) and Kn(t). On suppfn(t), we have
p1 + w2+F/t2≤p1 + Q2
n+F0/t2≤1
t(1 + F0)(1 + Qn(t)) (2.14)
and thus
kρn(t)k ≤ π
t2ZQn(t)
−Qn(t)ZF0
0
1
t(1 + F0)(1 + Qn(t))||fn(t)||dFdw + (Kn−1(t))2
≤C
t3(1 + F0)2(1 + Qn(t))2k◦
fk+(Kn−1(t))2;
kpn(t)k,kjn(t)k ≤ π
t2ZQn(t)
−Qn(t)ZF0
0
Qn(t)||fn(t)||dFdw + (Kn−1(t))2
≤C
t2(1 + F0)(1 + Qn(t))2k◦
fk+(Kn−1(t))2
28
¿From (1.43), we have, setting C0=β
2,
e−2µn(t, r)≥C0
t(2.15)
Using (2.5)-(2.7) and (2.15) we have
|˙
λn(s, r)| ≤ 4πseµn(s,r)|ρn(s, r)|+1 + s/C0
2s
≤C
C0
[(1 + F0)2(1 + Qn(s))2
sk◦
fk+(Kn−1(s))2] + 1 + C0
2sC0
;
and
|˜µneµn−λn(s, r)| ≤ 4πs2
C0
[C
s2(1 + F0)(1 + Qn(s))2k◦
fk+Kn−1(s)2]
≤C
C0
[(1 + F0)(1 + Qn(s))2k◦
fk+Kn−1(s)2]
Thus
|˙
Wn+1(s)| ≤ | ˙
λn(s)|+|˜µn|eµn−λn(s)p1 + w2+F/s2
≤C
C0
[(1 + F0)2(1 + Qn(s))2
sk◦
fk+(Kn−1(s))2+1
s]|Wn+1(s)|
+C
C0
[(1 + F0)(1 + Qn(s))2k◦
fk+Kn−1(s)2]1 + F0
s(1 + |Wn+1(s)|)
≤C
C0
[(1 + F0)2(1 + Qn(s))2
s(1+ k◦
fk)(1 + Kn−1(s))2](1 + |Wn+1(s)|)
≤C1
1
s(1 + Qn(s))2(1 + Kn−1(s))2(1 + |Wn+1(s)|)
This implies after integration over [t, 1],
Wn+1(t)≤W0+C1Z1
t
1
s(1 + Qn(s))2(1 + Kn−1(s))2(1 + |Wn+1(s)|)ds;
then
Qn+1(t)≤W0+C1Z1
t
1
s(1 + Qn(s))2(1 + Kn−1(s))2(1 + Qn+1(s))ds (2.16)
with C1=C
C0(1 + F0)2(1+ k◦
fk). Next we have, using (2.5)-(2.7) and (2.15)
|˙
λn(s, r)|+|(˜µneµn−λn)(s, r)|≤ C1
(1 + Qn(s))2
s(1 + Kn−1(s))2(2.17)
we then deduce from (2.11) and (2.17) that
Kn+1(t)≤K0+C1Z1
t
(1 + Qn(s))2
s(1 + Kn−1(s))2Kn(s)ds (2.18)
29
Add (2.16) and (2.18) to obtain
Qn+1(t)+Kn+1(t)≤W0+K0+C1Z1
t
1
s(1+Qn(s))2(1+Kn−1(s))2(1+Qn+1(s)+Kn(s))ds
(2.19)
Now define Hn(t) := sup{Qm(t) + Km(t) ; m≤n}. (Hn)n∈Nis an increasing
sequence. Then,
Qn(t) + Kn(t)≤Hn(t)≤Hn+1(t),
Qn+1(t) + Kn+1(t)≤W0+K0+C1Z1
t
1
s(1 + Hn+1(s))5ds and
Qm(t) + Km(t)≤W0+K0+C1Z1
t
1
s(1 + Hn+1(s))5ds for m≤n;
which imply :
Hn+1(t)≤W0+K0+C1Z1
t
1
s(1 + Hn+1(s))5ds
Let z1be the left maximal solution of the equation
z1(t) = W0+K0+C1Z1
t
1
s(1 + z1(s))5ds
which exists on some interval ]T1,1] with T1∈[T∗,1[. By comparing the solution
of the integral inequality with that of the corresponding integral equation it
follows that
Hn+1(t)≤z1(t), t ∈]T1,1[, n ∈N.
Since Qn(t) + Kn(t)≤Hn+1(t), we obtain
Kn(t), Qn(t)≤z1(t), t ∈]T1,1[, n ∈N.
And all the quantities which were estimated against Qnand Knin the above
argument are bounded by certain powers of z1on ]T1,1]. Namely |˙
λn(t)|,|ρn(t)|,
|pn(t)|,|jn(t)|,|˜µneµn−λn(t)|,g2
n−1e−2µn−1(t), h2
n−1e−2λn−1(t) are bounded. (2.4)
shows that e−2µnis bounded and by (2.15), e2µnis bounded. (2.6) shows that
|λn(t)|is bounded. Consequently eλnand e−λnare bounded. Then gnand hn
are bounded. We conclude that, there exists a continuous function C2(t) which
depends only on z1as an increasing function, such that
(kµn(t)k,kλn(t)k,k˙
λn(t)k,kρn(t)k,kpn(t)k,
kjn(t)k,k˜µneµn−λnk,kgn(t)k,khn(t)k ≤ C2(t)(2.20)
30
Now we bound Bn(t). We have, using (2.20), the estimates
ρ0
n(t) = π2
t2Z∞
−∞ Z∞
0p1 + w2+F/t2∂rfndFdw
+ (−µ0
n−1g2
n−1+gn−1g0
n−1)e−2µn−1+ (−λ0
n−1h2
n−1+hn−1h0
n−1)e−2λn−1
=π2
t2Z∞
−∞ Z∞
0p1 + w2+F/t2∂rfndFdw
+ (−µ0
n−1gn−1+g0
n−1)e−µn−1gn−1e−µn−1+ (−λ0
n−1hn−1+h0
n−1)e−λn−1hn−1e−λn−1
≤π2
t2Z∞
−∞ Z∞
0p1 + w2+F/t2∂rfndFdw +g2
n−1e−2µn−1
+ (−µ0
n−1gn−1+g0
n−1)2e−2µn−1+ (−λ0
n−1hn−1+h0
n−1)2e−2λn−1+h2
n−1e−2λn−1
≤π2
t2Z∞
−∞ Z∞
0p1 + w2+F/t2∂rfndFdw +g2
n−1e−2µn−1+h2
n−1e−2λn−1
+e−2λn−1[(−µ0
n−1gn−1+g0
n−1)2e−2µn−1+ (−λ0
n−1hn−1+h0
n−1)2e−2λn−1]e2λn−1
and
kρ0
n(t)k≤ C2(t)(C3+Bn(t))
We deduce in the same way as previously :
kρ0
n(t)k,kp0
n(t)k,kj0
n(t)k,kµ0
n(t)k,k˙
λ0
n(t)k,kλ0
n(t)k≤ C2(t)(C3+Bn(t))
(2.21)
k˜µ0
neµn−λnk≤ C2(t)(C3+Bn(t)) (2.22)
Following step 2 of the proof of theorem 3.1 in [15], we have
|∂rGn(s, r, w, F)| ≤ C2(s)(C3+Bn(s));
|∂wGn(s, r, w, F)| ≤ C2(s)
and differentiate the characteristic system of the Vlasov equation with respect
to r:
|d
ds∂r(R, W)n+1(s, t, r, w, F )|=|∂r(R, W)n+1(s, t, r, w, F).∂rGn(s, Rn+1, Wn+1, F)|
≤ |∂r(R, W)n+1(s, t, r, w, F )|C2(s)(C3+Bn(s))
therefore for (r, w, F)∈suppfn+1(t)∪suppfn(t), we obtain by Gronwall’s in-
equality
|∂r(R, W)n+1(1, t, r, w, F )| ≤ exp Z1
t
C2(s)(C3+Bn(s))ds.
31
¿From the definition of fin (2.2), we obtain
||∂rfn+1(t, r, w, F)|| =||∂r(R, W )n+1(1, t, r, w, F).∂(r, w)◦
f((R, W)n+1(1, t, r, w, F )) ||
≤ ||∂(r, w)◦
f||sup{|∂r(R, W)n+1(1, t, r, w, F )|; (r, w, F )∈suppfn+1(t)}
≤ ||∂(r, w)◦
f||exp Z1
t
C2(s)(C3+Bn(s))ds.
(2.23)
with C3=k◦
λ0k+k◦
µ0e−2◦
µk+1. We use (2.20), (2.21), (2.22) and estimate
(2.12) to obtain
An+1(t)≤A0+Z1
t
C2(s)(C3+Bn(s))(1 + An)(s)ds
Let Dn(t) := sup{Am(t)|m≤n}and En(t) := sup{Bm(t)|m≤n}.{Dn}and
{En}are increasing sequences. Therefore
1 + An+1(t)≤A0+1+Z1
t
C2(s)(C3+En(s))(1 + Dn+1(s))ds (2.24)
then we deduce by replacing nby any m≤nin (2.24)
1 + Dn+1(t)≤A0+1+Zt
1
C2(s)(C3+En(s))(1 + Dn+1(s))ds;
which gives:
Dn+1(t)≤2(A0+ 1) exp Z1
t
C2(s)(C3+En(s))ds. (2.25)
Now add (2.23)-(2.25) to obtain
Bn+1(t)≤(2(A0+ 1)+ k∂r,w ◦
fk) exp Z1
t
C2(s)(C3+En(s))ds
and deduce by replacing nby every m≤nthat:
En+1(t)≤C4exp Z1
t
C2(s)(C3+En+1(s))ds
where C4= 2(A0+ 1)+ k∂(r,w)◦
fk. Let z2be the left maximal solution of
z2(t) = C4exp Z1
t
C2(s)(C3+z2(s))ds
i.e
˙z2(t) = −C2(t)(C3+z2(t))z2(t), z2(1) = C4;
32
which exists on an interval ]T2,1] ⊂]T1,1]. Then we have
En+1(t)≤z2(t), t ∈]T2,1], n ∈N
and so
An(t), Bn(t)≤z2(t), t ∈]T2,1], n ∈N
and all the quantities estimated against Bnabove can be bounded in terms of
z2on ]T2,1], uniformly in n.
Remark 2.2 The sequences λn,µn,fn,˜µneµn−λn,ρn,pn,jn,gn,hn,λ0
n,µ0
n,
f0
n,g0
n, h0
n,˙
λn,˙µn,˙gn,˙
hn,˙
λn0,ρ0
n,p0
n,j0
n,˜µn0, are uniformly bounded in the
L∞−norm by a function of ton [T∗
1,1] with T∗
1= max(T1, T2).
In order to prove the convergence of the iterates in the following proposition,
we introduce auxiliary variables ˜gnand ˜
hndefined by ˜gn=gne−µn,
˜
hn=hne−λn, for n∈N.
Proposition 2.3 Let [T3,1] ⊂[T2,1], be an arbitrary compact subset on which
the previous estimates hold. Then on such an interval, the iterates converge
uniformly.
Proof: Define for t∈[T3,1]:
αn(t) := sup{k (fn+1 −fn)(s)k+k(˜gn+1 −˜gn)(s)k+k(˜
hn+1 −˜
hn)(s)k
+k(λn+1 −λn)(s)k+k(µn+1 −µn)(s)k;t≤s≤1}
and let Cdenote a constant which may depend on the functions z1and z2
introduced previously. If we consider the new quantities
˜
Xn= (˜gn+1 −˜gn)−(˜
hn+1 −˜
hn); ˜
Yn= (˜gn+1 −˜gn)+(˜
hn+1 −˜
hn),
then we obtain by subtracting the system (2.8)-(2.9) written for n+ 1 and n
(see appendix), the new system
D+
n˜
Xn=an˜
Xn−1+bn˜
Yn−1+Fn(2.26)
D−
n˜
Yn=bn˜
Xn−1+cn˜
Yn−1+Gn(2.27)
where
Fn= (an−an−1+bn−bn−1)˜gn−1+ (an−1−an+bn−bn−1)˜
hn−1
+ (e−µn−1−e−µn)(˙
˜gn−˙
˜
hn)+(e−λn−1−e−λn)(˜g0
n−˜
h0
n)
and substitute in Fn,˜
h0
nand ˜g0
nrespectively by −˜
h0
nand −˜g0
nto obtain Gn.
Now let
θn(t) = sup{| ˜gn+1 −˜gn|+|˜
hn+1 −˜
hn|;r∈R}
33
Thus similarly to (2.11), we have :
θn(t)≤2Z1
t
(mn(s)θn−1(s) + sup{eµn(|Fn(s, r)|+|Gn(s, r)|); r∈R})ds
(2.28)
Using the mean value theorem to express the differences e−µn−e−µn−1,
e−λn−e−λn−1and remark 2.2, then (2.28) gives
|˜gn+1 −˜gn|+|˜
hn+1 −˜
hn|≤ CZ1
t
(αn−1+|˜µn−˜µn−1|+|˙
λn−˙
λn−1|)(s)ds
(2.29)
The expressions of ρn,pn,jnyield, using proposition 2.1, that
|ρn+1 −ρn|(t),|pn+1 −pn|(t),|jn+1 −jn|(t)≤Cαn(t)
¿From (2.5) and (2.7), we have respectively
|˙
λn−˙
λn−1|(t) = 4πt |(e2µn−e2µn−1)ρn+ (ρn−ρn−1)e2µn−1|(t)
≤Cαn−1(t)(2.30)
|˜µn−˜µn−1|(t) = 4πt|(eλn+µn−eλn−1+µn−1)jn+ (jn−jn−1)eλn−1+µn−1|(t)
≤Cαn−1(t)
(2.31)
Using the two previous inequalities, (2.29) gives
(|˜gn+1 −˜gn|+|˜
hn+1 −˜
hn|)(t)≤CZ1
t
αn−1(s)ds (2.32)
By the mean value theorem, (2.4) gives :
|µn+1 −µn|(t)≤CZ1
t
αn(s)ds (2.33)
(2.6) gives :
|λn+1 −λn|(t) = Z1
t|˙
λn+1 −˙
λn|ds ≤CZ1
t
αn(s)ds (2.34)
Now from (2.30)-(2.31), (2.33)-(2.34), the mean value theorem and the fact that
R1
tαn−1(s)ds ≤Cαn−1(t), we deduce
|Gn−Gn−1|(s, r, w, F)≤Cαn−1(s)
which implies for (r, w, F)∈suppfn−1(t)∪suppfn(t),
|d
ds((R, W)n+1−(R, W)n)|(s, t, r, w, F) =|Gn−Gn−1|(s, r, w, F)≤Cαn−1(s)
34
Integrating over [t, 1] and using the fact that
|(R, W)n+1 −(R, W )n|(t, t, r, w, F) = 0 gives
|(R, W)n+1 −(R, W )n|(1, t, r, w, F)≤CZ1
t
αn−1(s)ds
This implies using (2.2) and the mean value theorem
|(fn+1 −fn)(t)| ≤| ∂r,w ◦
f|| (R, W)n+1 −(R, W )n|(1, t, r, w, F)
≤C|∂r,w ◦
f|Z1
t
αn−1(s)ds
(2.35)
Adding (2.32), (2.33), (2.34), (2.35), then
αn(t)≤CZ1
t
(αn(s) + αn−1(s))ds ;n≥1.
By Gronwall’s inequality αn(t)≤CR1
tαn−1(s)ds ;
and by induction
αn(t)≤Cn+1 (1 −t)n
n!≤Cn+1
n!for n ∈N, t ∈[T3,1]
Since the series PCn+1
n!converges, we deduce the convergence of Pαnwhich
implies that αn→0 for n→ ∞. Every difference term which appears in αn,
converges to zero. We deduce the uniform convergence of
fn, λn, µn,˜gn,˜
hn,˙
λn,˙µn,˜µn, ρn, pn, jn.(2.36)
And in L∞−norm, λn→λ;µn→µ; ˜µn→˜µ;fn→f; ˜gn→˜g;˜
hn→˜
h.
It remains to show that the limits ˜g, ˜
h, f, λ, µ are C1,fsolves the Vlasov
equation (1.2), λ, µ solve the field equations (1.3)-(1.4), and to show the exis-
tence of a function φthat solves the wave equation (1.7). This is the subject of
the next section.
2.2 Local existence
Theorem 2.4 (local existence) Let ◦
f∈C1(R2×[0,∞[) with
◦
f(r+ 1, w, F) = ◦
f(r, w, F)for (r, w, F)∈R2×[0,∞[,◦
f≥0, and
W0:= sup{|w||(r, w, F)∈supp◦
f}<∞
F0:= sup{F|(r, w, F)∈supp◦
f}<∞
35
Let ◦
λ, ψ ∈C1(R),◦
µ, ◦
φ∈C2(R)with ◦
λ(r) = ◦
λ(r+ 1),◦
µ(r) = ◦
µ(r+ 1),
◦
φ(r) = ◦
φ(r+ 1) and
◦
µ0(r) = −4πe
◦
λ+◦
µ◦
j(r), r ∈R
Then there exists a unique, left maximal, regular solution (f, λ, µ, φ)of system
(1.2)-(1.11) with (f, λ, µ, φ)(1) = (◦
f, ◦
λ, ◦
µ, ◦
φ)and ˙
φ(1) = ψon a time interval
]T, 1] with T∈[0,1[.
Proof : Consider the sequences of iterates constructed at the begining of this
chapter and the limit obtained in the above proposition. We need the uniform
convergence of the derivatives of these iterates.
We know by (2.36) that ( ˙
λn) and ( ˙µn) converge uniformly. We must now show
that, λ0
n,µ0
n,˙
fn,∂rfn,∂wfn,˙
˜gn, ˜g0
n,˙
˜
hn,˜
h0
nalso converge uniformly. Using
(2.3), the convergence of ˙
fnwill be a consequence of that of λn,µn,˙
λn, ˜µn
∂rfn,∂wfn. Using system (2.8)-(2.9), the convergence of ˙
˜gn,˙
˜
hnwill be a con-
sequence of that of ˜g0
n,˜
h0
n,µn,λn, ( ˙
λn), ˜µn. We then proceed to show the
uniform convergence of λ0
n,µ0
n,∂rfn,∂wfn, ˜g0
n,˜
h0
n.
In what follows, we fix T4∈[T2,1], t∈[T4,1], |w|< U,F < F0,t≤s≤1.
Step 1: Convergence of (∂rfn) and (∂wfn).
Following step 4 in the proof of theorem 3.1 in [15], and using (2.36), we can
establish with minor changes, using Proposition 2.1, that if we set:
ξn(s) = e(λn−µn)(s,r)∂Rn(s, t, r, w, F) (2.37)
ηn(s) = ∂Wn(s)+(p1 + w2+F/s2eλn−µn˙
λn)∂Rn(s) (2.38)
in which ∂stands for ∂ror ∂wand s7→ (Rn(s), Wn(s)) the indicated solution of
the characteristic system associated to equation (2.3) in fn, and then: ∀ > 0,
∃N∈Nsuch that we have, for n>N:
(|ξn+1 −ξn|+|ηn+1 −ηn|)(s)≤C+CZ1
s
(|ξn+1 −ξn|+|ηn+1 −ηn|)(τ)dτ
(2.39)
in which C > 0 stands, as in what follows, for a constant that may change
from line to line. (2.39) implies by Gronwall’s lemma, that (ξn) and (ηn) con-
verge uniformly. Now, since the transformation (∂Rn, ∂Wn)7→ (ξn, ηn) defined
by (2.37)-(2.38) is invertible with convergent coefficients, this implies the con-
vergence of ∂r,w(Rn, Wn) and, given (2.2), the convergence of (∂rfn) and (∂wfn).
Step 2: convergence of (λ0
n),(µ0
n),(˜µ0
n),(˜g0
n),(˜
h0
n).
We set
γn(t) = sup{|ξn+1 −ξn|(s) + |ηn+1 −ηn|(s)+ k(µ0
n+1 −µ0
n)(s)k
+k(λ0
n+1 −λ0
n)(s)k+k(˜g0
n+1 −˜g0
n)(s)k+k(˜
h0
n+1 −˜
h0
n)(s)k;t≤s≤1}
(2.40)
36
Now since (µn), (˜µn), ( ˙
λn), (˜gn), (˜
hn), (ρn), (jn) converge uniformly, we take
the above integer Nsufficiently large so that we have for n > N:
k(µn+1 −µn)(s)k,k(jn+1 −jn)(s)k,k(˜µn−˜µn−1)(s)k,k(˙
λn+1 −˙
λn)(s)k,
k(˜gn−˜gn−1)(s)k,k(˜
hn−˜
hn−1)(s)k,k(ρn+1 −ρn)(s)k≤
(2.41)
A) Estimation of (λ0
n), (µ0
n), (˜µ0
n). We deduce from (2.37)-(2.38), taking ∂=∂r
that:
∂Rn(s) = e(µn−λn)(s,r)ξn(s) (2.42)
∂Wn(s) = ηn(s)−(p1 + w2+F/s2˙
λn)ξn(s) (2.43)
Let us first consider ρ0
n,j0
n,p0
nthat involve ∂rfn, (˜gn˜
hn)0,1
2(˜g2
n+˜
h2
n). We have,
using (2.2), (2.42), (2.43)
k(∂rfn+1 −∂rfn)(s)k ≤k ∂r,w ◦
fk(|∂rRn+1 −∂rRn|+|∂rWn+1 −∂rWn|)(s)
≤Ck∂r,w ◦
fk(|eµn+1−λn+1 ξn+1 −eµn−λnξn|
+|ηn+1 −ηn|+|˙
λn+1ξn+1 −˙
λnξn|)(s).
(2.44)
Estimate (2.44) gives, using (2.41) and since (λn),(µn),(ξn),(˙
λn) are bounded,
k(∂rfn+1 −∂rfn)(s)k≤ C(|ξn+1 −ξn|+|ηn+1 −ηn|)(s) + C (2.45)
Next we have, using (2.41) and remark 2.2 :
|(˜gn˜
hn)0−(˜gn−1˜
hn−1)0|=|˜g0
n˜
hn−˜g0
n−1˜
hn−1+ ˜gn˜
h0
n−˜gn−1˜
h0
n−1|
≤C +C(|˜g0
n−˜g0
n−1|+|˜
h0
n−˜
h0
n−1|)(2.46)
Now using (2.41) and the fact that (˜gn), (˜
hn), (˜g0
n), ˜
h0
nare bounded, we obtain
|1
2(˜g2
n+˜
h2
n)0−1
2(˜g2
n−1+˜
h2
n−1)0|=|˜g0
n˜gn−˜g0
n−1˜gn−1+˜
hn˜
h0
n−˜
hn−1˜
h0
n−1|
≤C(|˜g0
n−˜g0
n−1|+|˜
h0
n−˜
h0
n−1|) + C
(2.47)
We then deduce, from the expressions of ρn,pn,jnand using (2.40), (2.45),
(2.46), (2.47), (2.41)
k(ρ0
n+1 −ρ0
n)(s)k,k(p0
n+1 −p0
n)(s)k,k(j0
n+1 −j0
n)(s)k≤ C +C(γn+γn−1)(s)
(2.48)
Concerning (µ0
n), we obtain by taking the derivative of (2.4) with respect to r:
µ0
ne−2µn=◦
µ0e
◦
µ
t−4π
tZ1
t
s2p0
n(s, r)ds
subtracting this relation written for n+ 1 and n, we obtain
µ0
n+1 −µ0
n=e2µn+1 [µ0
n(e−2µn−e−2µn+1 )−4π
tZ1
t
s2(p0
n+1 −p0
n)(s, r)ds]
37
This gives, using (2.41), (2.48) and the fact that µn,µ0
nare bounded :
k(µ0
n+1 −µ0
n)(s)k≤ C +CZ1
s
(γn−1(τ) + γn(τ))dτ (2.49)
Concerning (λ0
n), if we take the derivative of (2.5) with respect to r, we have
˙
λ0
n= (8πtµ0
nρn+ 4πtρ0
n)e2µn−kµ0
n
te2µn(2.50)
We first deduce that ˙
λn0is bounded since µ0
n,ρn,ρ0
n,µnare bounded. Next,
subtracting (2.50) written for n+ 1 and n, we obtain :
˙
λ0
n+1−˙
λ0
n=e2µn+1 [(µ0
n+1 −µ0
n)(8πtρn+1 −k
t)+8πtµ0
n(ρn+1 −ρn)
+ 4πt(ρ0
n+1 −ρ0
n)] + (e2µn+1 −e2µn)(4πtρ0
n−k
tµ0
n+ 8πtµ0
nρn)
using (2.40), (2.41), (2.48), and since (µn), (ρn), (µ0
n) are bounded
k(˙
λ0
n+1 −˙
λ0
n)(s)k≤ C +C(γn−1(s) + γn(s)) (2.51)
Now, (2.6) gives :
(λ0
n+1 −λ0
n)(t, r) = Zt
1
(˙
λ0
n+1 −˙
λ0
n)(s, r)ds
which gives, taking the norms, using (2.51) and integrating over [s, 1], with
λn+1(1, r)−λn(1, r) = 0 :
k(λ0
n+1 −λ0
n)(s)k≤ C +CZ1
s
(γn−1(τ) + γn(τ))dτ (2.52)
We will also need to bound ˜µ0
n+1 −˜µ0
n. If we take the derivative of (2.7) with
respect to r, we obtain, after subtracting the expressions written for n+ 1 and
n:
˜µ0
n+1 −˜µ0
n= (eλn+1+µn+1 −eλn+µn)(j0
n+jn)−4πt[(j0
n+1 −j0
n)
+ (µ0
n+1 −µ0
n+λ0
n+1 −λ0
n)jn+1 + (µ0
n+λ0
n)(jn+1 −jn)]eλn+1+µn+1
We then deduce from (2.40), (2.41), (2.48):
k(˜µ0
n+1 −˜µ0
n)(s)k≤ C +C(γn−1(s) + γn(s)) (2.53)
B) Estimation of (˜g0
n), (˜
h0
n). Recall that
Xn= ˜gn−˜
hn;Yn= ˜gn+˜
hn;an= (−˙
λn−1
t)e−µn−˜µne−λn;
bn=−e−µn
t;cn= (−˙
λn−1
t)e−µn+ ˜µne−λn
(2.54)
38
Set
Cn=anXn+bnYn;˜
Cn= (λ0
n−µ0
n)e−λnX0
n+1 +µ0
nCn+C0
n
Dn=bnXn+cnYn;˜
Dn= (µ0
n−λ0
n)e−λnY0
n+1 +µ0
nDn+D0
n
(2.55)
Then system (2.8)-(2.9) becomes
(D+
nXn+1 =Cn
D−
nYn+1 =Dn
If we take the derivative of the above system with respect to r, a direct calcu-
lation shows that (see appendix) :
D+
nX0
n+1 =˜
Cn(2.56)
D−
nY0
n+1 =˜
Dn(2.57)
We are going to integrate (2.56)-(2.57) on characteristic curves of the wave op-
erator. Consider the following characteristic curves γ1
n,γ2
nof the wave operator,
starting from the point (s, r), i.e for every n,
˙γ1
n=eµn−λn,˙γ2
n=−eµn−λn, γ1
n(s) = γ2
n(s) = r(2.58)
We have D+
n=e−µnd
dt on γ1
nand D−
n=e−µnd
dt on γ2
n. We then have, integrat-
ing (2.56) over γ1
nand (2.57) over γ2
n:
X0
n+1(s) = X0
n+1(1) −Z1
s
eµn˜
Cn(τ, γ1
n(τ))dτ
Y0
n+1(s) = Y0
n+1(1) −Z1
s
eµn˜
Dn(τ, γ2
n(τ))dτ
Now if we subtract respectively each of this two relations written for n+ 1 and
n, we obtain :
(X0
n+1 −X0
n)(s) = Z1
sheµn−1˜
Cn−1(τ, γ1
n−1(τ)) −eµn˜
Cn(τ, γ1
n(τ))idτ (2.59)
(Y0
n+1 −Y0
n)(s) = Z1
sheµn−1˜
Dn−1(τ, γ2
n−1(τ)) −eµn˜
Dn(τ, γ2
n(τ))idτ (2.60)
Since eµnand ˜
Cnare bounded, we have
|eµn˜
Cn(τ, γ1
n(τ)) −eµn−1˜
Cn−1(τ, γ1
n−1(τ))|={eµn(τ, γ1
n(τ)) −eµn−1(τ, γ1
n(τ))}˜
Cn(τ, γ1
n(τ))
+{˜
Cn(τ, γ1
n(τ)) −˜
Cn−1(τ, γ1
n(τ))}eµn−1(τ, γ1
n(τ)) + {˜
Cn−1(τ, γ1
n(τ)) −˜
Cn−1(τ, γ1
n−1(τ))}
eµn−1(τ, γ1
n(τ)) + {eµn−1(τ, γ1
n(τ)) −eµn−1(τ, γ1
n−1(τ))}˜
Cn−1(τ, γ1
n−1(τ))
≤C{k (eµn−eµn−1)(τ)k+k(˜
Cn−˜
Cn−1)(τ)k
+|˜
Cn−1(τ, γ1
n(τ)) −˜
Cn−1(τ, γ1
n−1(τ))|+|eµn−1(τ, γ1
n(τ)) −eµn−1(τ, γ1
n−1(τ))|}
(2.61)
39
Now integrating the relation ˙γ1
n−˙γ1
n−1=eµn−λn−eµn−1−λn−1over [s, τ] yields
|γ1
n−γ1
n−1|(τ)≤Csup{k (λn−λn−1)(t)k+k(µn−µn−1)(t)k, T4≤t≤1}
(2.62)
we then deduce from (2.36) (the right hand side of (2.62) tends to zero as n
tends to ∞), the uniform continuity of (eµn−1), ( ˜
Cn−1) over the compact set
K= [T4,1] ×(γ1
n([T4,1]) ∪γ1
n−1([T4,1])) i.e
∀ > 0,∃η(n, )>0 such that |γ1
n−γ1
n−1|(τ)≤η⇒
|˜
Cn−1(τ, γ1
n(τ)) −˜
Cn−1(τ, γ1
n−1(τ))|+|eµn−1(τ, γ1
n(τ)) −eµn−1(τ, γ1
n−1(τ))|<
And from (2.61), (2.59)-(2.60), we deduce that
|X0
n+1 −X0
n|(s)≤C +CZ1
sk(˜
Cn−˜
Cn−1)(τ)kdτ (2.63)
|Y0
n+1 −Y0
n|(s)≤C +CZ1
sk(˜
Dn−˜
Dn−1)(τ)kdτ (2.64)
Therefore, for nsufficiently large, (2.63)- (2.64) implies respectively :
−C −CZ1
sk(˜
Cn−˜
Cn−1)(τ)k≤ X0
n+1 −X0
n≤C +CZ1
sk(˜
Cn−˜
Cn−1)(τ)kdτ
−C −CZ1
sk(˜
Dn−˜
Dn−1)(τ)k≤ Y0
n+1 −Y0
n≤C +CZ1
sk(˜
Dn−˜
Dn−1)(τ)kdτ
We deduce from (2.54) (definition of Xnand Yn), by adding and subtracting
the previous inequalities, that
k(˜g0
n+1 −˜g0
n)(s)k,k(˜
h0
n+1 −˜
h0
n)(s)k≤ C +CZ1
s
[k(˜
Cn−˜
Cn−1)(τ)k
+k(˜
Dn−˜
Dn−1)(τ)k]dτ
(2.65)
Now from (2.55), (2.41) and the fact that the sequences ( ˙
λn), (λn), (µn), (˜µ0
n)
are bounded together with their first derivatives, we have (see appendix)
k(˜
Cn−˜
Cn−1)(τ)k≤ C +C(γn−1(τ) + γn(τ)) (2.66)
and
k(˜
Dn−˜
Dn−1)(τ)k≤ C +C(γn−1(τ) + γn(τ)) (2.67)
Therefore, we deduce from (2.65), (2.66)-(2.67) that
k(˜g0
n+1 −˜g0
n)(s)k,k(˜
h0
n+1 −˜
h0
n)(s)k≤ C +CZ1
s
(γn−1(τ) + γn(τ))dτ (2.68)
40
C) Convergence of (λ0
n), (µ0
n), (˜µ0
n), (˜g0
n), (˜
h0
n). Add inequalities (2.39),
(2.49),(2.52) and (2.68) and take the supremum over s∈[t, 1] to obtain using
(2.40)
γn(t)≤C +CZ1
t
(γn−1(s) + γn(s))ds (2.69)
Define Γn(t) = sup{γm, m ≤n}; then (Γn) is an increasing sequence and (2.69)
gives
Γn(t)≤C +CZ1
t
Γn(s)ds
And by Gronwall’s lemma,
Γn(t)≤C, t ∈[T4,1],n sufficiently large.
We then deduce that (Γn) converges uniformly to 0, and from (2.40)-(2.53),
(λ0
n), (µ0
n), (˜g0
n), (˜
h0
n), (˜µ0
n) converge uniformly on [T4,1]. We deduce from sys-
tem (2.8)-(2.9), the uniform convergence of (˙
˜gn) and (˙
˜
hn). The regularity of f,
λ,µ, ˜g,˜
h(and ˜µ) follows from step 1 and step 2. Therefore g=eµ˜gand h=eλ˜
h
are regular. Note that, using the convergence of the derivatives, we can prove
that the limit (f, λ, µ, ˜µ, g, h) is a regular solution of (1.14), (1.3), (1.4), (1.15),
(1.16), (1.17) and by Proposition 1.14, we conclude the existence of a regular
function φsuch that (f, λ, µ, φ) is a solution of the full system (1.2)-(1.11).
To end this theorem, we prove the uniqueness of the solution. Let ui=
(fi, λi, µi, φi), i= 1,2 be two regular solutions of the Cauchy problem for the
same initial data (◦
f, ◦
λ, ◦
µ, ◦
φ, ψ) at t= 1. Using the fact that uiis a solution
of the system, one proceeds similarly as to prove the convergence of iterates to
obtain
α(t)≤CZ1
t
α(s)ds
where
α(t) = sup{k f1(s)−f2(s)k+kλ1(s)−λ2(s)k+kµ1(s)−µ2(s)k
+k˜g1(s)−˜g2(s)k+k˜
h1(s)−˜
h2(s)k;s∈[t, 1]},
with ˜g1=˙
φ1eµ1; ˜g2=˙
φ2eµ2;˜
h1=φ0
1eλ1;˜
h2=φ0
2eλ2. We deduce that
α(t) = 0, for t∈]0,1]. This implies that f1=f2,λ1=λ2,µ1=µ2, ˜g1= ˜g2
and ˜
h1=˜
h2. By Proposition 1.14, we conclude that φ1=φ2.
2.3 Continuation criteria
Let us now prove continuation criteria for tdecreasing.
Theorem 2.5 Let (◦
f, ◦
λ, ◦
µ, ◦
φ, ψ)be initial data as in theorem 2.4. Let (f, λ, µ, φ)
be a solution of (1.2)-(1.11) on a left maximal interval of existence ]T, 1] for
41
which :
1. sup{|w||(t, r, w, F)∈suppf}<∞,
2. sup{(e−2µ˙
φ2+e−2λφ02)(t, r); t∈]T, 1]}<∞,
3. µis bounded.
Then T= 0.
If k≥0or ◦
µ≤0then condition 3is automatically satisfied.
Proof : Let (f, λ, µ, ˜µ, g, h) be a left maximal solution of the auxiliary sys-
tem (1.14), (1.3), (1.4), (1.15), (1.16), (1.17) with existence interval ]T, 1]. By
Proposition 1.14, there exists φsuch that (f, λ, µ, φ) solves (1.2)-(1.11). By
assumption
Q∗:= sup{|w||(r, w, F)∈suppf(t), t ∈]T, 1]}<∞.
We want to show that T= 0, so let us assume that T > 0 and take t1∈]T, 1[. We
will show that the system has a solution with initial data (f(t1), λ(t1), µ(t1), φ(t1),
˙
φ(t1)) prescribed at t=t1which exists on an interval [t1−δ, t1] with δ > 0
independent of t1. By moving t1close enough to Tthis would extend our initial
solution beyond T, a contradiction to the initial solution being left maximal.
We have proved in Proposition 2.1 that such a solution exists at least on the
left maximal existence interval of the solutions (z1, z2) of
z1(t) = W(t1) + K(t1) + C1Zt1
t
1
s(1 + z1(s))5ds
z2(t) = C4exp Zt1
t
C2(s)(C3+z2(s))ds,
where
W(t1) := sup{|w||(r, w, F)∈suppf(t1)},
K(t1) := sup{(|˙
φ2|e−2µ+|φ02|e−2λ)1
2(t1, r) ; r∈R},
A(t1) := sup{e−λ[( ˙
φ0−µ0˙
φ)2e−2µ+ (φ00 −λ0φ0)2e−2λ]1/2(t1, r) ; r∈R},
C1=C
C0
(1 + F0)2(1+ kf(t1)k) ; C0= inf{e−µ(t1,r);r∈R}
C3:=ke−2µ(t1)µ0(t1)k+kλ0(t1)k+1 ; C4:= 2 + 2A(t1)+ k∂(r,w)f(t1)k
and C2is an increasing function of z1. Now W(t1)≤Q∗,kf(t1)k=k◦
fk,F0
is unchanged since Fis constant along characteristics, and since t1<1, taking
42
t=t1in (2.4) shows that: C0(µ(t1)) ≥C0(◦
µ). Thus there exists a constant
M1>0 such that
1
TC1(f(t1), F0, µ(t1)) ≤M1for t1∈]T, 1].
The expressions of ρ, p, j, ˙
λ, ˜µshow since |w| ≤ Q∗, that
|ρ(s, r)|,|p(s, r)|,|j(s, r)|,|˙
λ(s, r)|,|˜µeµ−λ(s, r)| ≤ C+ (K(s))2
K(s) is bounded on ]T, 1]. We proceed as in step 6 of the proof of theorem 3.1
in [15] to prove that ∂(r,w)fis uniformly bounded on ]T, 1]. Let µ0= ˜µ; consider
the relations
µ0=−4πteλ+µj;µ00 =−[(λ0+µ0)j+j0]4πteλ+µ(2.70)
˙
λ0=e2µ(8πtµ0ρ+kµ0
t+ 4πtρ0) ; λ0=◦
λ0+Zt
1
˙
λ0(s, r)ds (2.71)
We bound ρ0,j0by quantities which depend on ∂rfand A(s). Since ∂rf,ρand
jare bounded, we deduce from the above relations that µ00,˙
λ0and consequently
v(s) and h(s) (see Proposition 1.10) are bounded each by A(s). Using inequality
(1.27) and the fact that K(s) is bounded, we obtain
A(t)≤A0+CZ1
t
(A(s) + 1)ds
And we deduce that A(t)≤A∗= (1 + A0)eC;t∈]T, 1]. Therefore
D:= sup{k ∂(r,w)f(t)k+A(t)|t∈]T, 1]}<∞.
From
µ0(t, r) = e2µ
t◦
µ0(r)e−2◦
µ+ 4πRt
1p0(s, r)s2ds,
(2.70), (2.71) and since K(t) and A(t) are bounded, p0is bounded and we obtain
a uniform bound C3(µ(t1), λ(t1)) ≤M3. Let y2be the left maximal solution of
y2(t) = Dexp Zt1
t
C∗
2(s)(M3+y2(s))ds,
where C∗
2depends on y1in the same way as C1depends on z1.y2exists on
an interval [t1−α, t1] with α > 0 independent of t1. If we choose t1such that
T > t1−αthen z1is bounded; z2≤y2by construction. In particular, z2exists
on I⊂[t1−α, t1].
From (1.37), we deduce for k≥0 that e−2µ≥e−2◦
µ+k
t−k≥e−2◦
µsince 1
t≥1.
If k=−1 and ◦
µ≤0, then e−2µ≥e−2◦
µ−1
t+ 1 ≥1. Either, µis bounded above.
Then condition 3 holds. This complete the proof of the theorem.
43
Theorem 2.6 Let (f, λ, µ, φ)be a solution of (1.2)-(1.11) on a left maximal
interval of existence ]T, 1],T > 0, with initial data as in Theorem 2.5. If
1. Q(t) = sup{|w||(r, w, f)∈suppf(t), t ∈]T, 1]}<∞
2. µis bounded.
then T= 0.
If k≥0or ◦
µ≤0then condition 2is automatically satisfied.
Proof: We need to prove that K(t) is bounded for all t∈]T, 1]. Unless otherwise
specified in what follows constants denoted by Cwill be positive, may depend
on the initial data and may change their value from line to line.
We deduce from system (1.28)-(1.29) :
D+X2
2= 2eµk
t−4πt(ρ−p)X2
2−2e−µ
tX2Y2
D−Y2
2=−2e−µ
tX2Y2+ 2eµk
t−4πt(ρ−p)Y2
2
On the corresponding characteristic curves of the wave equation,
D+=D−=e−µd
dt and then
d
dtX2
2(t, γ1(t)) = 2e2µk
t−4πt(ρ−p)X2
2(t, γ1(t)) −2
tX2Y2(t, γ1(t))
d
dtY2
2(t, γ2(t)) = −2
tX2Y2(t, γ2(t)) + 2e2µk
t−4πt(ρ−p)Y2
2(t, γ2(t))
Integrate the first of the two previous equations on [t, 1] :
X2
2(t, γ1(t)) = X2
2(1, γ1(1)) + 2 Z1
t{e2µ[−k
s+ 4πs(ρ−p)]X2
2+1
sX2Y2}(s, γ1(s))ds
≤X2
2(1, γ1(1)) + 2 Z1
t{e2µ[−k
s+ 4πs(ρ−p)]X2
2+1
2s(X2
2+Y2
2)}(s, γ1(s))ds
≤X2
2(1, γ1(1)) + 2 Z1
t{[1
2s+e2µ(−k
s+ 4πs(ρ−p))]X2
2+1
2sY2
2}(s, γ1(s))ds
In a similar way,
Y2
2(t, γ2(t)) ≤Y2
2(1, γ2(1))+2 Z1
t{1
2sX2
2+1
2s+e2µ(−k
s+ 4πs(ρ−p))Y2
2}(s, γ2(s))ds
Add the two previous inequalities and take the supremum over space :
B(t)2≤B(1)2+ 2 Z1
t
l(s)B(s)2ds (2.72)
where
B(t) = sup{(|X2|2+|Y2|2)1/2(t, r) ; r∈R}
l(t) = sup{1
t+e2µ[|k|
t+ 4πt(ρ−p)](t, r) ; r∈R}
44
Now subtract the two equations (1.8)-(1.9) to obtain :
ρ−p=π
t2Z∞
−∞ Z∞
0
(p1 + w2+F/t2−w2
p1 + w2+F/t2)fdFdw
=π
t2Z∞
−∞ Z∞
0
1 + F/t2
p1 + w2+F/t2fdFdw
≤π
t2Z∞
−∞ Z∞
0
1 + F/t2
p1 + F/t2fdFdw
≤π
t2Z∞
−∞ Z∞
0p1 + F/t2fdFdw
≤C
t3; since Q(t)<∞
Using (2.15) for the bound of eµ, we obtain :
l(t)≤1
t+|k|
C0
+C
tC0
Then (2.72) implies :
B(t)2≤B(1)2+ 2 Z1
t
(C(1 + 1
s) + 1
s)B(s)2ds
And by Gronwall’s lemma,
B(t)2≤B(1)2t−2eC(1−t)t−C≤Ct−C−2
Now, we have from (1.9),
p(s, r) = π
s2Z+∞
−∞ Z+∞
0
w2
p1 + w2+F/s2f(s, r, w, F)dFdw +1
2(X2+Y2)(s, r)
≤π
s2Z+∞
−∞ Z+∞
0
w2
|w|f(s, r, w, F)dFdw +1
2e−2µ(X2
2+Y2
2)(s, r)
≤C
s2+1
2e−2µB(s)2
≤C
s2+Cs−C−2e−2µ
45
Then using (1.37) (where ¯pis replaced by p), we obtain the estimate :
e−2µ(t,r)≤e−2◦
µ(r)+k
t−k+8π
tZ1
t
s2(C
s2+Cs−C−2e−2µ)ds
≤e−2◦
µ(r)+k
t−k+C
tZ1
t
(1 + s−Ce−2µ)ds
≤e−2◦
µ(r)+|k|
t+C
tZ1
t
(1 + s−Ce−2µ)ds
≤e−2◦
µ(r)+|k|
t+C
t(1 + Z1
t
s−Ce−2µds)
≤C
t(1 + Z1
t
s−Ce−2µds).
By Gronwall’s lemma, we deduce that e−2µ≤Ct−1exp[ C
1−C(1−t1−C)]. There-
fore,
(X2+Y2)(t, r) = e−2µ(X2
2+Y2
2)(t, r)≤Ct−3−Cexp[ C
1−C(1 −t1−C)]
i.e K(t) is bounded. And we conclude by Theorem 2.5 that T= 0.
We prove in the next theorem, the analogue of theorems 2.4 and 2.5 for
t≥1.
Theorem 2.7 Let (◦
f, ◦
λ, ◦
µ, ◦
φ, ψ)be initial data as in Theorem 2.4. Then there
exists a unique, right maximal, regular solution (f, λ, µ, φ)of (1.2)-(1.11) with
(f, λ, µ, φ, ˙
φ)(1) = (◦
f, ◦
λ, ◦
µ, ◦
φ, ψ)on a time interval [1, T[with T∈]1,∞]. If
sup{| w| |(t, r, w, F)∈suppf}<∞;
sup{e2µ(t,r)|r∈R, t ∈[1, T[}<∞
and
K(t)<∞
then T=∞.
Proof : We give only those parts of the proof which differ from the proof of
Theorem 2.4 for t≤1. The iterates are defined in the same way as before,
except that now (2.4) is used to define µnonly on the interval [1, Tn[, where
Tn:= sup (τ∈]1, Tn−1[|e−2◦
µ(r)+k
t−k−8π
tZt
1
s2pn(s, r)ds > 0, r ∈R, t ∈[1, τ]),
[1, Tn−1[ being the existence interval of the previous iterates and T0=∞. De-
fine:
Qn(t) := sup {|w|,(r, w, F)∈suppfn(t)}, t ∈[1, Tn[
46
En(t) := sup nse2µn(s,r)|r∈R,1≤s≤to
we obtain the estimates
p1 + w2+F/t2≤p1+(Qn(t))2+F0≤(1 + F0)(1 + Qn(t));
kρn(t)k,kpn(t)k,kjn(t)k≤ C∗
t(1 + Qn(t))2+ (Kn−1(t))2; (2.73)
and
|eµn−λn˜µn(t, r)|+|˙
λn(t, r)|≤ C∗(1 + Qn(t))2+ (1 + Kn−1(t))2(1 + En(t)).
where C∗=C(1 + F0)2(1+ k◦
fk). Thus, we have similarly to (2.16):
Qn+1(t)≤W0+C∗Zt
1
(1 + Qn(s))2(1 + En(s))(1 + Kn−1(s))2(1 + Qn+1(s))ds.
(2.74)
and similarly to (2.18):
Kn+1(t)≤K0+C∗Zt
1
(1 + Qn(s))2(1 + Kn−1(s))2Kn(s)(1 + En(s))ds. (2.75)
We deduce from the field equation (1.4) that
(2 ˙µne2µn)t=e2µn+ke4µn+ 8π(te2µn)2pn
Integrating over [1, s] and using integration by parts for the left hand side yields
the following estimate, since (2.73) holds,
En(t)≤k e2◦
µk+C∗Zt
1
(1 + Qn(s))2(1 + En(s))2(1 + Kn−1(s))2ds. (2.76)
Reasoning in the same way as in the proof of Proposition 2.1, we can say the
differential inequalities (2.74), (2.75), (2.76) allow us to estimate Qn,Knand
Enagainst the solution z1,z2and z3of the system
z1(t) = W0+C∗Zt
1
(1 + z1(s))3(1 + z2(s))2(1 + z3(s))ds,
z2(t) = K0+C∗Zt
1
(1 + z1(s))2(1 + z2(s))3](1 + z3(s))ds,
z3(t) =ke2◦
µk+C∗Zt
1
(1 + z1(s))2(1 + z2(s))2(1 + z3(s))2ds,
and in particular Tn≥Twhere [1, T[ is the right maximal existence interval
of (z1, z2, z3). One can now establish a bound on first order derivatives of
the iterates in the same way as in the proof of Proposition 2.1 and obtains a
local solution on a right maximal existence interval which is extendible if the
quantities Q(t) , E(t) =ke2µ(t)kand K(t) can be bounded.
47
Theorem 2.8 Let (f, λ, µ, φ)be a right maximal regular solution obtained in
Theorem 2.7. Assume that
sup{| w| |(t, r, w, F)∈suppf}<∞;
and
sup{e2µ(t,r)|r∈R, t ∈[1, T[}< C < ∞;
then T=∞.
Proof : We deduce from system (1.12)-(1.13):
D+X2= 2aX2+ 2bXY
D−Y2= 2bXY + 2cY 2
On the respectively characteristic curves of the wave equation, D+=D−=
e−µd
dt and then we obtain :
d
dtX2(t, γ1(t)) = 2eµ(aX2+bXY )(t, γ1(t)) (2.77)
d
dtY2(t, γ2(t)) = 2eµ(bXY +cY 2)(t, γ2(t)) (2.78)
¿From (2.77), we have:
d
dtX2(t, γ1(t)) = 2(−˙
λ−µ0eµ−λ−1
t)X2−2XY
t
= 8πte2µ(j−ρ)X2+1 + ke2µ
tX2−2
tX2−2XY
t
≤(−1
t+ke2µ
t)X2+X2+Y2
tsince j−ρ < 0 ;
If k= 0 or −1 then d
dtX2(t, γ1(t)) ≤1
tY2(t, γ1(t)).
If k= 1 then d
dtX2(t, γ1(t)) ≤1
t(CX2+Y2)(t, γ1(t)).
Since j+ρ > 0, we deduce as above, from (2.78), the estimates
d
dtY2(t, γ2(t)) ≤1
tX2(t, γ2(t)) for k= 0 or k=−1;
d
dtY2(t, γ2(t)) ≤1
t(X2+CY 2)(t, γ2(t)) for k= 1.
48
After integrating these two inequalities over [1, t] and taking the maximum over
space, we obtain :
K(t)2≤K(1)2+Zt
1
1
sK(s)2ds for k= 0 or k=−1;
K(t)2≤K(1)2+Zt
1
1 + C
sK(s)2ds for k= 1.
We deduce by Gronwall’s lemma that:
K(t)2≤K(1)2t , for k= 0 or k=−1 and t∈[1, T [ (2.79)
K(t)2≤K(1)2t1+C,for k= 1 and t∈[1, T[ (2.80)
And we conclude by Theorem 2.7 that T=∞.
49
Chapter 3
Global existence and
asymptotic behaviour of
solutions in the past
3.1 Global existence in the past
We prove that the solutions obtained in Theorem 2.4 exist on the whole interval
]0,1].
Theorem 3.1 Consider a solution of the Einstein-Vlasov system with k≥0
and initial data given for t= 1. Then this solution exists on the whole interval
]0,1]. If k < 0and ◦
µ≤0, the same result holds.
Proof : we follow the works of M. Weaver [32] and S.B. Tchapnda [29]. The
strategy of the proof is the following : suppose we have a solution on an interval
]T, 1] with T > 0. We want to show that the solution can be extended to the
past. By consideration of the maximal interval of existence this will prove the
assertion.
Firstly let us prove that under the hypotheses of the theorem, µis bounded
above.
From the field equation (1.4) we have for k≥0,
d
dt(te−2µ) = −k−8πt2p≤0.(3.1)
So te−2µcannot increase towards the future, i.e. it cannot decrease towards the
past. Thus on ]T, 1], te−2µmust remain bounded away from zero and hence µ
is bounded above.
For the case k=−1, since p(s, r)≥0, we get from (1.37), e−2µ≥e−2◦
µ−1
t+1 ≥1
which gives the upper bound of µfor ◦
µ≤0.
50
Now, let us prove that wis bounded.
Consider the following rescaled version of w, called u1, which has been inspired
by the works of [32] (p. 1090) and [30] (p. 5):
u1=eµ
2tw.
If we prove that µis bounded below then the boundedness of u1will imply the
boundedness of w. So let us show that µis bounded below under the assumption
that u1is bounded.
We have d
dt(te−2µ) = −k−8πt2p. (3.2)
Transforming the integral term defining pto u1as an integration variable instead
of wyields
p=Z∞
−∞ Z∞
0
8πte−3µu2
1
p1+4t2e−2µu2
1+F/t2fdFdu1+1
4(X2+Y2);
where Xand Yare defined in lemma 1.5. The integrand term in pcan then be
estimated by 4πe−2µ|u1|. We have
e2µ(ρ−p) = π
t2Z∞
−∞ Z∞
0
1 + F/t2
p1 + w2+F/t2e2µfdFdw
=π
t2Z∞
−∞ Z∞
0
(1 + F/t2)2teµ
p1+4t2e−2µu2
1+F/t2fdFdu1
≤2π
tZ∞
−∞ Z∞
0
(1 + F/t2)eµfdFdu1
≤2π
t3eµZ¯u1
−¯u1ZF0
0
(1 + F)fdFdu1
≤Ct−3¯u1eµ
where ¯u1is the maximum modulus of u1on the support of fat a given time. We
can then estimate from (2.72) l(s) by h(s) = Csup{1+s−1+s−2eµ¯u1(s, r); r∈
R}and B(t)2by B(1)2exp(R1
th(s)ds). Thus
X2+Y2≤e−2µB(t)2≤e−2µB(1)2exp(Z1
t
h(s)ds).
Therefore, using the bound for µand u1,pcan be estimated by Ce−2µand so
(3.2) implies that
|d
dt(te−2µ)| ≤ C(1 + te−2µ),
integrating this with respect to tover [t, 1] yields
te−2µ(t, r)≤e−2µ(1,r)+Z1
t
C1 + se−2µ(s,r)ds,
51
which implies by the Gronwall inequality that te−2µis bounded on ]T, 1]; that
is µis bounded below on the given time interval.
The next step is to prove that u1is bounded. To this end, it suffices to get
a suitable integral inequality for ¯u1. Since u1=u1(t, r(t)), we can compute ˙u1:
˙u1=−eµ
2t2w+eµ
2tw( ˙µ+ ˙rµ0) + eµ
2t˙w
i.e.
˙u1=˙µ+ ˙rµ0−1
tu1+eµ
2t˙w(3.3)
We have
µ0=−4πteµ+λj, ˙r=eµ−λw
p1 + w2+F/t2
and
˙w= 4πte2µ(jp1 + w2+F/t2−ρw) + 1 + ke2µ
2tw
so that (3.3) implies the following :
˙u1=e2µ−4πt(ρ−p) + k
tu1+ 2πe3µj1 + F/t2
p1+4t2e−2µu2
1+F/t2.
i.e
˙u1|u1|=e2µ−4πt(ρ−p) + k
tu1|u1|+ 2πe3µj(1 + F/t2)|u1|
p1+4t2e−2µu2
1+F/t2(3.4)
In order to estimate the modulus of the first term on the right hand side of
equation (3.4), we need the estimate of e2µ(ρ−p)¯u2
1. For convenience let log+
be defined by log+(x) = log xwhen log xis positive and log+(x) = 0, otherwise.
Then estimating the integral defining ρ−pshows that
ρ−p≤C(1 + log+( ¯w)),
i.e.
ρ−p≤C(1 + log+(¯u1)−µ).
The expression −µis not under control ; however the expression we wish to
estimate contains a factor e2µ. The function µ7→ −µe2µhas an absolute maxi-
mum at −1/2 which is (1/2)e−1. Thus the first term on the right hand side of
equation (3.4) can be estimated by C¯u2
1(1 + log+(¯u1)).
Next the second term on the right hand side of equation (3.4) will be esti-
mated.
By definition
j=π
t2Z∞
−∞ Z∞
0
wf(t, r, w, F)dFdw −˙
φφ0e−µ−λ=j1+j2
52
The first term of jcan be estimated by C¯w2, i.e.
|j1| ≤ C¯u2
1e−2µ
and the second term |j2| ≤ 1
2e−2µB(t)2; so that it suffices to estimate the
quantity
(¯u2
1+B(t)2)(1 + F/t2)
p1+4t2e−2µu2
1+F/t2|u1|(3.5)
in order to estimate the second term on the right hand side of equation (3.4).
But since µand t−1are bounded on the interval being considered, the quantity
(3.5) can be estimated by C(¯u2
1+B(t)2). Thus adding the estimates for the
first and second terms on the right hand side of (3.4) allows us to deduce from
(3.4) that
|˙u1||u1| ≤ C¯u2
1(1 + log+(¯u1))+C(¯u2
1+B(t)2)
i.e
|d
dt|u1|2| ≤ C(¯u1)2(1 + log+(¯u2
1)) + CB(t)2
Integrating over [t, 1] gives :
¯u2
1(t)≤¯u2
1(1) + CZ1
t¯u2
1(s)(1 + log+(¯u2
1(s))+B(s)2ds (3.6)
We deduce from the estimate of ρ−pand from inequality (2.72), that l(s) can
be estimated by C(1 + log+(¯u1)). We then obtain
B(t)2≤B(1)2+CZ1
t
(1 + log+(¯u2
1)(s))B(s)2ds (3.7)
Adding (3.6) and (3.7) gives estimate :
¯u2
1(t)+B(t)2≤¯u2
1(1)+B(1)2+CZ1
t
(1+¯u2
1+B(s)2)1 + log+(1 + ¯u2
1(s) + B(s)2)ds
(3.8)
Set v(t) = ¯u2
1(t) + B(t)2, then (3.8) can be written
v(t)≤v(1) + CZ1
t
(1 + v(s)) 1 + log+(1 + v(s))ds (3.9)
By the comparison principle for solutions of integral equations, it is enough to
show that the solution of the integral equation
a(t) = a(1) + CZ1
t
(1 + a(s)) 1 + log+(1 + a(s))ds
is bounded. The solution a(t) is a non-increasing function. Thus either a(t)≤e
everywhere, in which case the desire conclusion is immediate. Or there is some
53
T1in ]T, 1] such that e≤a(t) on ]T, T1]. We take T1maximal with that property.
Then it follows on ]T, T1] that inequality
a(t)≤C 1 + ZT1
t
a(s)(1 + log a(s))ds!
holds for a constant C. The boundedness of a(t) follows from that of the solution
of the differential equation ˙x=Cx(1 + log x) which is exp(exp(Ct)−1). In
either case a(t) is bounded. Thus ¯u2
1and B(t)2are bounded i.e wand K(t) are
bounded. The proof of the theorem is complete using theorem 2.6.
3.2 On past asymptotic behaviour
In this section we examine the behaviour of solutions as t→0.
Firstly we follow the work of Ringstrom [24](P. S310-S311) to bound the
quantity |φ0|eµ−λby C|tlog t|−1, where C is a positive constant.
Lemma 3.2 Let A1=1
8(−˙
φ+φ
tlog t+φ0eµ−λ)2and
A2=1
8(−˙
φ+φ
tlog t−φ0eµ−λ)2with t∈]0,1[. If φsatisfies the wave equation,
then
(∂t+e−µ−λ∂r)A1=−1
4t(1 + 1
log t)[(−˙
φ+φ
tlog t)2+φ02e2µ−2λ]
+1
2t(1 + 1
log t)φ02e2µ−2λ+1
4(˙
λ−˙µ+1
t)( ˙
φ−φ0eµ−λ)(−˙
φ+φ
tlog t+φ0eµ−λ)
(3.10)
(∂t+e−µ−λ∂r)A2=−1
4t(1 + 1
log t)[(−˙
φ+φ
tlog t)2+φ02e2µ−2λ]
+1
2t(1 + 1
log t)φ02e2µ−2λ+1
4(˙
λ−˙µ+1
t)( ˙
φ+φ0eµ−λ)(−˙
φ+φ
tlog t−φ0eµ−λ)
(3.11)
Proof : We have,
8(∂t+e−µ−λ∂r)A1= 2[−¨
φ+˙
φ
tlog t−φ(1 + log t)
(tlog t)2+ ( ˙µ−˙
λ)φ0eµ−λ+˙
φ0eµ−λ
+eµ−λ(−˙
φ0+φ0
tlog t+ (µ0−λ0)φ0eµ−λ+φ00eµ−λ)](−˙
φ+φ
tlog t+φ0eµ−λ)
= 2[−¨
φ+φ00e2µ−2λ+˙
φ
tlog t−φ(1 + log t)
(tlog t)2+ ( ˙µ−˙
λ)φ0eµ−λ
+φ0eµ−λ
tlog t+ (µ0−λ0)φ0e2µ−2λ](−˙
φ+φ
tlog t+φ0eµ−λ)
54
i.e
8(∂t+e−µ−λ∂r)A1= 2[( ˙
λ−˙µ+1
t)˙
φ+ (µ0−λ0)φ0e2µ−2λ+˙
φ
tlog t−φ(1 + log t)
(tlog t)2
+ ( ˙µ−˙
λ)φ0eµ−λ+φ0eµ−λ
tlog t+ (µ0−λ0)φ0e2µ−2λ](−˙
φ+φ
tlog t+φ0eµ−λ)
= 2[( ˙
λ−˙µ+1
t)˙
φ+˙
φ
tlog t−φ
(tlog t)2−φ
t2log t
+ ( ˙µ−˙
λ)φ0eµ−λ+φ0eµ−λ
tlog t](−˙
φ+φ
tlog t+φ0eµ−λ)
= 2[( ˙
λ−˙µ+1
t)( ˙
φ−φ0eµ−λ) + 1
tφ0eµ−λ+1
tlog tφ0eµ−λ
+1
tlog t(˙
φ−φ
tlog t) + 1
t(˙
φ−φ
tlog t)](−˙
φ+φ
tlog t+φ0eµ−λ)
= 2(−˙
φ+φ
tlog t+φ0eµ−λ)(−1
tlog t−1
t)(−˙
φ+φ
tlog t−φ0eµ−λ)
+ 2( ˙
λ−˙µ+1
t)( ˙
φ−φ0eµ−λ)(−˙
φ+φ
tlog t+φ0eµ−λ)
=−2
t(1 + 1
log t)(−˙
φ+φ
tlog t)2−φ02e2µ−2λ)
+ 2( ˙
λ−˙µ+1
t)( ˙
φ−φ0eµ−λ)(−˙
φ+φ
tlog t+φ0eµ−λ)
=−2
t(1 + 1
log t)(−˙
φ+φ
tlog t)2+φ02e2µ−2λ+4
t(1 + 1
log t)φ02e2µ−2λ
+ 2( ˙
λ−˙µ+1
t)( ˙
φ−φ0eµ−λ)(−˙
φ+φ
tlog t+φ0eµ−λ);
and (3.10) follows. If we replace rby −r, the wave equation is invariant, ∂t+
e−µ−λ∂rand ∂t−e−µ−λ∂r,A1and A2interchange; and we can write (3.11).
Lemma 3.3 Let (f, λ, µ, φ)be a left maximal solution of the Einstein-Vlasov-
scalar field system on the interval ]T, 1],0≤T < e−1. Assume that
Q(t) = sup{| w| |(r, w, F)∈suppf(t)} ≤ Ctα
for some positive constants C,αand for some t∈]T, e−1]. Then
(−˙
φ+φ
tlog t)2+φ02e2µ−2λ≤C(tlog t)−2(3.12)
Proof : Consider the two characteristic curves (t, γ1(t)) and (t, γ2(t)) of the
wave operator. Since t∈]0, e−1], the term (1 + 1
log t)φ02e2µ−2λis nonnegative
55
and (−˙
φ+φ
tlog t)2+φ02e2µ−2λ= 4(A1+A2), then from (3.10) :
(∂t+e−µ−λ∂r)A1(t, γ1(t)) ≥ −1
t(1 + 1
log t)(A1+A2)(t, γ1(t))
−1
4(˙
λ−˙µ+1
t)(−˙
φ+φ0eµ−λ)(−˙
φ+φ
tlog t+φ0eµ−λ)(t, γ1(t))
(3.13)
Similarly, we deduce from (3.11) that :
(∂t−e−µ−λ∂r)A2(t, γ2(t)) ≥ −1
t(1 + 1
log t)(A1+A2)(t, γ2(t))
−1
4(˙
λ−˙µ+1
t)(−˙
φ−φ0eµ−λ)(−˙
φ+φ
tlog t−φ0eµ−λ)(t, γ2(t))
(3.14)
Since Q(t)≤Ctα, we can bound ρ−pby Ct−3+α(see the proof of Theorem
2.6). e2µ≤Ct; then
(˙
λ−˙µ)(t) + 1
t=−ke2µ
t+ 4πte2µ(ρ−p)≤C(1 + t−1+α); and from (2.72), l(s)
can be bounded by s−1+C+Cs−1+α. We deduce from (2.72) (consider the
integral term in the interval [t, e−1]) that
B(t)2≤B(e−1)2exp[2 Re−1
t(s−1+C+Cs−1+α)ds] i.e B(t)2≤Ct−2. There-
fore |˙
φ(t)|and |φ0|eµ−λ(t) are bounded each by Ct−1. We can then have a lower
bound of the second term of the right hand side of each inequality (3.13) and
(3.14) which is −C(t−2+t−3+α). Then
(∂t+e−µ−λ∂r)A1(t, γ1(t)) ≥ −1
t(1 + 1
log t)(A1+A2)(t, γ1(t)) −C(t−2+t−3+α)
and
(∂t+e−µ−λ∂r)A2(t, γ2(t)) ≥ −1
t(1 + 1
log t)(A1+A2)(t, γ2(t)) −C(t−2+t−3+α)
On the corresponding characteristic, we have ∂t+e−µ−λ∂r=∂t−e−µ−λ∂r=
d
dt . Take the supremum in the space of each of the above two inequalities and
add them. Then
d
dt(A1+A2)(t, r)≥ −2
t(1 + 1
log t)(A1+A2)(t, r)−C(t−2+t−3+α)
Set u(t) = (A1+A2)(t) and v(t) = (tlog t)2(A1+A2)(t). If v(t) is bounded,
then we conclude that u(t) is bounded by C(tlog t)−2. Let us prove that v(t) is
bounded. We have :
dv
dt = 2t(log t)u+ 2t(log t)2u+ (tlog t)2du
dt
= (tlog t)2(du
dt +2
t(1 + 1
log t)u)
≥(tlog t)2(−Ct−2−Ct−3+α) = −C(log t)2(1 + t−1+α)
Then, v(t)≤v(e−1) + CRe−1
t(1 + s−1+α)(log s)2ds ≤v(e−1) + C. We obtain
the desired conclusion of the lemma.
56
Remark 3.4 In the case f= 0, we obtain from previous theorem and theorem
2.5, the global existence of solutions and the above estimates hold on the whole
interval ]0, e−1].
Remark 3.5 We have from the field equation (1.4),
e−2µ=e−2◦
µ+k
t−k+8π
tZ1
t
s2p(s, r)ds ≥e−2◦
µ+k
t−k
and then, for k= 0,e−2µ≥e−2◦
µ
t≥C0
t;
for k= 1,e−2µ≥e−2◦
µ+1
t−1≥e−2◦
µ
t≥C0
t;
for k=−1,e−2µ≥e−2◦
µ−1
t+ 1 ≥C0
t+ 1 ;
where
C0=(inf e−2◦
µfor k= 0 or 1
inf e−2◦
µ−1for k=−1
Thus
e2µ≤t
C0for k= 0 or k= 1 ;
and e2µ≤t
C0+tfor k=−1.
Remark 3.6 Let us prove that inf e−2◦
µ(r)=1
||e2◦
µ||.
For all r∈R,e2◦
µ(r)≤ ||e2◦
µ||, hence e−2◦
µ(r)≥1
||e2◦
µ|| ; and
inf e−2◦
µ(r)≥1
||e2◦
µ||.
For all r∈R,e−2◦
µ(r)≥inf e−2◦
µ(r), i.e e2◦
µ(r)≤1
inf e−2◦
µ(r)and
||e2◦
µ|| ≤ 1
inf e−2◦
µ(r)i.e inf e−2◦
µ(r)≤1
||e2◦
µ||. This completes the proof.
First we analyze the curvature invariant RαβγδRαβγδ called the Kretschman
scalar in order to prove that there is a spacetime singularity. Thus the spacetime
cannot be extended further.
Theorem 3.7 Let (f, λ, µ, φ)be a regular solution of the surface-symmetric
Einstein-Vlasov-scalar field system on the interval ]0,1] with data given for
t= 1. Then
(RαβγδRαβγδ)(t, r)≥4
t6inf e−2◦
µ+k2
,
with r∈R.
Proof We can compute the Kretschman scalar (see [15]) and obtain
RαβγδRαβγδ = 4[e−2λ(µ00 +µ0(µ0−λ0)) −e−2µ(¨
λ+˙
λ(˙
λ−˙µ))]2
+8
t2[e−4µ˙
λ2+e−4µ˙µ2−2e−2(λ+µ)(µ0)2]
+4
t4(e−2µ+k)2
=: K1+K2+K3
57
The first term K1is nonnegative and can be dropped.
Inserting the expressions
e−2µ˙
λ= 4πtρ −k+e−2µ
2t;e−2µ˙µ= 4πtp +k+e−2µ
2t;e−λ−µµ0=−4πtj
into the formula for K2yields
K2=8
t2(4πtρ −k+e−2µ
2t)2+ (4πtp +k+e−2µ
2t)2−2(−4πtj)2
=8
t216π2t2(ρ2+p2−2j2)−4πt(ρ−p)k+e−2µ
t+(k+e−2µ)2
2t2.
Now
|j(t, r)| ≤ π
t2Z∞
−∞ Z∞
0|w|fdFdw +|˙
φ|e−µ|φ0|e−λ
≤π
t2Z∞
−∞ Z∞
0
(1 + w2+F/t2)1/4f1/2|w|
(1 + w2+F/t2)1/4f1/2dFdw
+1
2(˙
φ2e−2µ+φ02e−2λ)
≤π
t2[Z∞
−∞ Z∞
0p1 + w2+F/t2fdFdw]1
2[Z∞
−∞ Z∞
0
w2
p1 + w2+F/t2fdFdw]1
2
+1
2(˙
φ2e−2µ+φ02e−2λ) by the Cauchy-Schwarz inequality.
≤π
2t2[Z∞
−∞ Z∞
0p1 + w2+F/t2fdFdw +Z∞
−∞ Z∞
0
w2
p1 + w2+F/t2fdFdw]
+1
2(˙
φ2e−2µ+φ02e−2λ)
≤1
2(ρ+p)(t, r).
In fact the above inequality holds in general for all choice of matter satisfying
the dominant energy condition. Therefore
ρ2+p2−2j2≥ρ2+p2−1
2(ρ+p)2=1
2ρ2+1
2p2−ρp =1
2(ρ−p)2
and
K2≥8
t28πt2(ρ−p)2−4πt(ρ−p)k+e−2µ
t+(k+e−2µ)2
2t2
≥4
t24πt(ρ−p)−k+e−2µ
t2
≥0.
58
Recalling the expression for e−2µwe get
e−2µ+k=e−2◦
µ(r)+k
t+8π
tZ1
t
s2p(s, r)ds
≥e−2◦
µ+k
t≥inf e−2◦
µ+k
t
thus
K3=4
t4(e−2µ+k)2≥4
t6inf e−2◦
µ+k2
and so we deduce from (3.15) that
(RαβγδRαβγδ)(t, r)≥4
t6inf e−2◦
µ(r)+k2
, t ∈]0,1], r ∈R,
and the proof is complete.
Remark 3.8 We deduce from the above inequality that
lim
t→0(RαβγδRαβγδ)(t, r) = ∞,
uniformly in r∈R.
Next we prove that the singularity at t= 0 is a crushing singularity i.e.
the mean curvature of the surfaces of constant tblows up. In the case where
there is only a scalar field and no Vlasov contribution this singularity is velocity
dominated i.e the generalized Kasner exponents have limits as t→0.
Theorem 3.9 Let (f, λ, µ, φ)be a regular solution of the surface-symmetric
Einstein-Vlasov-scalar field system on the interval ]0,1] with initial data given
on t= 1. Let
K(t, r) := −e−µ˙
λ(t, r) + 2
t
denotes the mean curvature of the hypersurfaces of constant t. Then
K(t, r)≤ −Ct−3/2,
where Cis a positive constant.
Proof For a metric of the form ds2=−α(t, r)2dt2+gijdxidxj,
the second fundamental form of the hypersurfaces of constant tis given by
Kij =−(2α)−1∂tgij and its trace K(t, r) = gij Kij is the mean curvature of
that hypersurfaces. For gdefined by (1.1), we have
Kij =−e−µ
2∂tgij. Thus
K11 =−e−µ
2∂tg11 =−˙
λe2λ−µ;K22 =−e−µ
2∂tg22 =−te−µ;
K33 =−te−µsin2
kθ.
And K(t, r) = −(˙
λ+2
t)e−µ. We have
˙
λ=e2µ4πtρ −k+e−2µ
2t≥ −e2µk+e−2µ
2t.(3.15)
59
and
K(t, r)≤k−3e−2µ
2teµ.
For k= 0 or k=−1,
K(t, r)≤ − 3
2te−µ.
and the estimate
e−2µ≥e−2◦
µ+k
t
implies
K(t, r)≤ − 3
2t(inf e−2◦
µ+k
t)1/2≤ −Ct−3/2where C=3
2(inf e−2◦
µ+k)1/2.
For k= 1 we have
e−2µ≥e−2◦
µ
t>1 = k(since t < 1)
thus
K(t, r)≤eµ1−3e−2µ
2t≤(e2µ−3
2)e−µ
t
≤ −e−µ
t≤ −inf e−◦
µ
t3/2
≤ −Ct−3/2where C= inf e−◦
µ.
Remark 3.10 We deduce from above that
lim
t→0K(t, r) = −∞,
uniformly in r∈R.
Theorem 3.11 Let (λ, µ, φ)be a regular solution of the spherical, plane and hy-
perbolic symmetric Einstein-scalar field system on the interval ]0,1] with initial
data given at t= 1. Then
lim
t→0
K1
1(t, r)
K(t, r)=a(r) ; lim
t→0
K2
2(t, r)
K(t, r)= lim
t→0
K3
3(t, r)
K(t, r)=1
2(1 −a(r)),
uniformly in r∈R,
where K1
1(t, r)
K(t, r),K2
2(t, r)
K(t, r),K3
3(t, r)
K(t, r)
are the generalized Kasner exponents and a(r)a function of r.
60
Proof We have
K1
1(t, r)
K(t, r)=t˙
λ(t, r)
t˙
λ(t, r)+2;K2
2(t, r)
K(t, r)=K3
3(t, r)
K(t, r)=1
t˙
λ(t, r)+2.
with
t˙
λ= 4πt2e2µρ−k
2e2µ−1
2.
As we have seen previously
e2µ(t,r)≤Ct
which implies that
e2µ(t,r)→0 as t→0
Let t0∈]0, e−1] and t∈]0, t0]. From (3.11),
∂t(φ
log t) = 1
log t(˙
φ−φ
tlog t) = O(t−1(log t)−2)
so that φ(t, r)
log t=φ(t0, r)
log t0−Zt0
t
s−1(log s)−2ds.
The integral term of the above relation converges as t→0. Set
A(r) = lim
t→0
φ(t, r)
log t=φ(t0, r)
log t0−Zt0
0
s−1(log s)−2ds
Since from (3.11), ( ˙
φ−φ
tlog t) = O((t|log t|)−1), we have
t˙
φ=φ
log t+O((|log t|)−1)
so that t˙
φ→A(r) as t→0. Inequality (3.11) shows also that
φ02e2µ−2λ=O((t|log t|)−2). Using these limits, we have
t˙
λ(t, r) = 2π(t2˙
φ2+t2φ02e2µ−2λ)−k
2e2µ−1
2→2πA(r)2−1
2as t→0, uniformly in r.
We take a(r) = 4πA(r)2−1
4πA(r)2+3 to complete the proof .
61
Chapter 4
Global existence and
asymptotic behaviour of
solutions in the future
4.1 Global existence in the future
We prove the global existence in the future in the cases of plane and hyperbolic
symmetries.
Theorem 4.1 Assume that (f, λ, µ, φ)is a right maximal regular solution of
the Einstein-Vlasov system with scalar field obtained in Theorem 2.7. Then for
k= 0 or k=−1,
sup{e2µ(t,r)|r∈R, t ∈[1, T[}<∞.
Proof : We now establish a series of estimates which will result in an upper
bound on µ. Similar estimates were used in [4] and [3]. Unless otherwise spec-
ified in what follows constants denoted by Cwill be positive, may depend on
the initial data and may change their value from line to line.
Firstly, integration of (1.4) with respect to tand the fact that pis non-negative
imply that
e2µ(t,r)="e−2◦
µ(r)+k
t−k−8π
tZt
1
s2p(s, r)ds#−1
≥t
C−kt, t ∈[1, T[ (4.1)
Next let us show that
Z1
0
eµ+λρ(t, r)dr ≤Ct, t ∈[1, T[ (4.2)
62
We have d
dt Z1
0
eµ+λρ(t, r)dr =Z1
0
[( ˙
λ+ ˙µ)eµ+λρ+eµ+λ˙ρ]dr
with
˙ρ=−2π
t3Z∞
−∞ Z∞
0p1 + w2+F/t2fdFdw +π
t2Z∞
−∞ Z∞
0p1 + w2+F/t2∂tfdFdw
+π
t2Z∞
−∞ Z∞
0
(−F
t3)f
p1 + w2+F/t2dFdw +e−2µ(−˙µ˙
φ2+˙
φ¨
φ) + e−2λ(−˙
λφ02+˙
φ0φ0)
=−2
tρ−1
tq+1
t(e−2µ˙
φ2+e−2λφ02) + 1
t(e−2µ˙
φ2−e−2λφ02)
+π
t2Z∞
−∞ Z∞
0p1 + w2+F/t2∂tfdFdw +e−2µ(−˙µ˙
φ2+˙
φ¨
φ) + e−2λ(−˙
λφ02+˙
φ0φ0)
=−2
tρ−1
tq+2
te−2µ˙
φ2+e−2µ(−˙µ˙
φ2+˙
φ¨
φ)
+e−2λ(−˙
λφ02+˙
φ0φ0) + π
t2Z∞
−∞ Z∞
0p1 + w2+F/t2∂tfdFdw.
The Vlasov equation and integration by parts imply,
π
t2Z∞
−∞ Z∞
0p1 + w2+F/t2∂tfdFdw
=π
t2Z∞
−∞ Z∞
0p1 + w2+F/t2"(˙
λw +eµ−λµ0p1 + w2+F/t2)∂wf−eµ−λw
p1 + w2+F/t2∂rf#dFdw
=π
t2Z∞
−∞ Z∞
0h˙
λwp1 + w2+F/t2+eµ−λµ0(1 + w2+F/t2)i∂wfdFdw
−π
t2Z∞
−∞ Z∞
0
eµ−λw∂rfdFdw
=−eµ−λhj0+e−µ(−µ0˙
φ+˙
φ0)φ0e−λ+e−λ(−λ0φ0+φ00)˙
φe−µi
−˙
λπ
t2Z∞
−∞ Z∞
0 p1 + w2+F/t2+w2
p1 + w2+F/t2!fdFdw
−µ0eµ−λπ
t2Z∞
−∞ Z∞
0
2wfdFdw
63
And so
˙ρ=−2
tρ−1
tq−eµ−λj0−2µ0jeµ−λ−˙
λ(ρ+p) + 2
te−2µ˙
φ2
+e−2µ(−˙µ˙
φ2+˙
φ¨
φ) + e−2λ(−˙
λφ02+˙
φ0φ0)+(λ0+µ0)e−2λ˙
φφ0
−e−2λ(˙
φ0φ0+˙
φφ00)−2µ0˙
φφ0e−2λ+˙
λ(e−2µ˙
φ2+e−2λφ02)
=−2
tρ−1
tq−eµ−λ(j0+ 2µ0j)−˙
λ(ρ+p)+(˙
λ−˙µ+2
t)˙
φ2e−2µ
+ (λ0−µ0)˙
φφ0e−2λ+˙
φ(e−2µ¨
φ−e−2λφ00)
=−2
tρ−1
tq−eµ−λ(j0+ 2µ0j)−(4πtρe2µ−1 + ke2µ
2t)(ρ+p);
where we use the wave equation to substitute the term e−2µ¨
φ−e−2λφ00 and also
the expression of ˙
λ. Therefore,
d
dt Z1
0
eµ+λρ(t, r)dr =−1
tZ1
0
eµ+λ2ρ+q+eµ−λ(j0+ 2µ0j)−ρ+p
2(1 + ke2µ)dr
=−1
tZ1
0
eµ+λ2ρ+q−ρ+p
2(1 + ke2µ)−Z1
0
(e2µj)0dr
(4.3)
and since µand jare periodic with respect to r, we deduce that:
d
dt Z1
0
eµ+λρ(t, r)dr =−1
tZ1
0
eµ+λ2ρ+q−ρ+p
2(1 + ke2µ)dr
For k= 0, since q≥ −2ρ, we have q+3ρ−p
2≥q+ρ≥ −ρ; we deduce that:
d
dt Z1
0
eµ+λρ(t, r)dr ≤1
tZ1
0
eµ+λρ(t, r)dr
Integrating this inequality with respect to tyields (4.2) for k= 0. For k=−1,
we have, using (4.1):
d
dt Z1
0
eµ+λρ(t, r)dr =−1
tZ1
0
eµ+λ2ρ+q−ρ+p
2(1 −e2µ)dr
≤ −1
tZ1
0
eµ+λ(2ρ+q−ρ+p
2)dr −1
C+tZ1
0
eµ+λρ+p
2dr
≤ −1
tZ1
0
eµ+λ(2ρ+q)dr + (1
t−1
C+t)Z1
0
eµ+λρ+p
2dr
≤1
tZ1
0
eµ+λρdr + (1
t−1
C+t)Z1
0
eµ+λρdr
≤(2
t−1
C+t)Z1
0
eµ+λρdr
64
where we use the fact that 2ρ+q≥ −ρand ρ+p
2≤ρ. Integrating the above
inequality with respect to tyields (4.2) for k=−1. Using equation µ0=
−4πteµ+λj, the fact that |j| ≤ ρand (4.2) we find
|µ(t, r)−Z1
0
µ(t, σ)dσ |=|Z1
0Zr
σ
µ0(t, τ)dτdσ |≤ Z1
0Z1
0|µ0(t, τ)|dτdσ
≤4πt Z1
0
eµ+λ|j(t, τ)|dτ ≤4πt Z1
0
eµ+λρ(t, τ)dτ
that is
|µ(t, r)−Z1
0
µ(t, σ)dσ |≤ Ct2, t ∈[1, T[, r ∈[0,1] (4.4)
Next we show that
eµ(t,r)−λ(t,r)≤Ct, t ∈[1, T [, r ∈[0,1].(4.5)
To see this observe that : relation ˙µ−˙
λ= 4πte2µ(p−ρ) + 1+ke2µ
t,p−ρ≤0
and (4.1) imply that
∂
∂teµ−λ= ( ˙µ−˙
λ)eµ−λ=eµ−λ4πte2µ(p−ρ) + 1 + ke2µ
t
≤1 + ke2µ
teµ−λ≤(1
t+k
C−kt)eµ−λ;
and integrating this inequality with respect to tyields
eµ−λ≤Ct
C−kt ≤Ct,
i.e. (4.5).
We now estimate the average of µ(t) over the interval [0,1] which in combi-
nation with (4.4) will yield the desired upper bound on µ. We use (1.4), (4.2),
(4.5) and the fact that p≤ρ,ke2µ≤0 :
Z1
0
µ(t, r)dr =Z1
0
◦
µ(r)dr +Zt
1Z1
0
˙µ(s, r)drds
≤C+Zt
1
1
2sZ1
0
[e2µ(8πs2p+k) + 1]drds
=C+1
2ln t+ 4πZt
1Z1
0
se2µpdrds +Zt
1Z1
0
ke2µ
2sdrds
≤C+1
2ln t+ 4πZt
1Z1
0
seµ−λeµ+λρdrds +Zt
1Z1
0
ke2µ
2sdrds
≤C+1
2ln t+CZt
1
s3ds
=C+1
2ln t+Ct4
65
with (4.4) this implies
µ(t, r)≤C(1 + ln t+t4+t2)≤Ct4, t ∈[1, T[, r ∈[0,1].(4.6)
Remark 4.2 we have proven that for initial data as in Theorem 2.4(local ex-
istence), the right maximal regular solution of the Einstein-Vlasov-scalar field
satisfies estimates (4.2)-(4.5)-(4.6).
In the next theorem, we prove that this solution exists on the full interval [1,∞[.
Theorem 4.3 Assume that (f, λ, µ, φ)is a solution of the full system on a right
maximal interval of existence [1, T[, then T=∞.
Proof: Assume that T < ∞. We show that under the bound of µ, we obtain the
bound of sup{|w||(t, r, w, F)∈suppf}which is in contradiction to Theorem
2.8. The proof of the bound on wis similar to the proof of [see [15], Theorem
6.2]. Let
W0:= sup{|w||(r, w, F)∈supp◦
f}<∞,
F0:= sup{F|(r, w, F)∈supp◦
f}<∞.
Except in the vacuum case we have W0>0 and F0>0. For t≥1 define
P+(t) := max{0,max{w|(r, w, F)∈suppf(t)}},
P−(t) := min{0,min{w|(r, w, F)∈suppf(t)}}.
Constants denoted by C will be positive, may depend on the initial data and may
change their value from line to line. Let (r(s), w(s), F ) be a characteristic in the
support of f. Assume that P+(t)>0 for some t∈[1, T[, and let w(t) = w > 0.
We have
˙w=−˙
λw −eµ−λµ0p1 + w2+F/s2
= (−4πse2µρ+1 + ke2µ
2s)w+ 4πse2µjp1 + w2+F/s2
= 4πse2µ(jp1 + w2+F/s2−ρw) + 1 + ke2µ
2sw
=4π2
se2µZ∞
−∞ Z∞
0˜wp1 + w2+F/s2−wq1 + ˜w2+˜
F/s2fd ˜
Fd ˜w
+1 + ke2µ
2sw−4πse2µ1
2w(˙
φ2e−2µ+φ02e−2λ) + p1 + w2+F/s2˙
φφ0e−µ−λ
(4.7)
66
Using the fact that K(s)2≤K(1)2sfor s∈[1, T[ (see (2.78)), we have :
1
2w(˙
φ2e−2µ+φ02e−2λ) + p1 + w2+F/s2˙
φφ0e−µ−λ
≥(w+p1 + w2+F/s2)˙
φφ0e−µ−λ
≥ −p1 + w2+F/s2K(s)2
≥ −C(1 + P+(s))s(4.8)
Set γ= ˜wp1 + w2+F/s2−wq1 + ˜w2+˜
F/s2. As long as w(s)>0, we have
the following estimates: if ˜w≤0 then γ≤0. If ˜w > 0 then
4π2
se2µZ∞
−∞ Z∞
0
γfd ˜
Fd ˜w+1 + ke2µ
2sw≤1 + ke2µ
2sw
+4π2
se2µZP+(s)
0ZF0
0
˜w2(1 + w2+F/s2)−w2(1 + ˜w2+˜
F/s2)
˜wp1 + w2+F/s2+wq1 + ˜w2+˜
F/s2
fd ˜
Fd ˜w
≤4π2
se2µZP+(s)
0ZF0
0
˜w2(1 + F/s2)
2 ˜ww fd ˜
Fd ˜w+1 + ke2µ
2sw
≤4π2
se2µZP+(s)
0ZF0
0
˜w(1 + F)
wfd ˜
Fd ˜w+1 + ke2µ
2sw
≤4π2F0(1 + F0)k◦
fke2µ
2s(P+(s))21
w+1 + ke2µ
2sw
≤C
s(P+(s))2
w+w(4.9)
Therefore, using (4.8) and (4.9), (4.7) yields:
˙w(s)≤C
s(P+(s))2
w(s)+w(s)+C(1 + P+(s))s2
i.e.
˙w(s)w(s)≤C
s(P+(s))2+CP+(s)(1 + P+(s))s2
d
dsw(s)2≤C(s−1+s2)(P+(s))2+CP+(s)s2
as long as w(s)>0. Let t1∈[1, t[ be defined minimal such that w(s)>0 for
s∈[t1, t[, then
w(t)2≤w(t1)2+CZt
t1
[(s−1+s2)(P+(s))2+s2P+(s)]ds
If t1= 1 then w(t1)≤w0and
w(t)2≤w2
0+CZt
1
[(s−1+s2)(P+(s))2+s2P+(s)]ds.
67
If t1>1 then w(t1) = 0 (t1is the minimal) and
w(t)2≤CZt
t1
[(s−1+s2)(P+(s))2+s2P+(s)]ds
≤w2
0+CZt
1
[(s−1+s2)(P+(s))2+s2P+(s)]ds.
Thus
(P+(t))2≤w2
0+CZt
1
[(s−1+s2)(P+(s))2+s2P+(s)]ds; for all t∈[1, T[
Now we use the fact that P+≤1
2(1 + P2
+) to obtain
(P+(t))2≤w2
0+CZt
1
[(s−1+s2)(P+(s))2+s2]ds
≤(w2
0+Ct3) + CZt
1
(s−1+s2)(P+(s))2ds; for all t∈[1, T[
If t < ∞, applying Gronwall’s inequality to this estimate implies that P+is
bounded on [1, T[.
Estimating ˙w(s) from below in the case w(s)<0 along the same lines shows
that P−is bounded as well and the proof is complete.
Remark 4.4 In the case of spherical symmetry (k= 1), there is no global
existence in the future, regardless of the size of initial data. For any solution
(f, λ, µ, φ), the estimate
e−2µ(t,r)=e−2◦
µ(r)+ 1
t−1−8π
tZt
1
s2p(s, r)ds ≤e−2◦
µ(r)+ 1
t−1
has to hold on the interval [1, T[. Since the right hand side of this inequality
tends to −1for t→ ∞, it follows that T < ∞. And we deduce from the previous
Theorem (|w|<∞) that ||e2µ|| → ∞ for t→T.
4.2 The future asymptotic behaviour
In this section we prove that the spacetime obtained in Theorem 4.3 (with f= 0)
in the plane symmetric case is timelike and null geodesically complete in the
expanding direction. Later on, we prove that this result holds for homogeneous
solutions of the Einstein-Vlasov-scalar field system in plane and hyperbolic sym-
metry.
Let us determine first the explicit solutions φ, µ, λ in the case f= 0 and k= 0.
68
4.2.1 Integration of equations
In the case k= 0 the wave equation can be reduced to a simple linear equation
as observed in [19]. This reduction goes as follows. In that case the field
equations imply that λ−µ+ log tis constant in time. It may, however, be
dependent on r. Suppose that ris replaced by a new coordinate son the
initial hypersurface. Choosing sappropriately makes the transformed quantity
λ−µ+ log tconstant on the initial hypersurface and hence everywhere. Let
us call this constant η. Then λ−µ+ log t=ηand the wave equation (1.7)
simplifies to
∂ttφ+t−1∂tφ=t2e−2η∂ssφ. (4.10)
Now with the change of coordinate rby s,√grrdr =eλdr =e˜
λds =√gssds with
˜
λ−µ+ log t=ηi.e ds =eλ−˜
λdr =te−ηeλ−µdr and 1 = e−ηR1
0te(λ−µ)(t,r)dr
for all t≥1. In particular for t= 1, 1 = Ae−ηis the period of variables rand
sfor A=R1
0e(λ−µ)(1,r)dr.
Now if we set T=βt2(βa positive constant), then (4.10) reads
∂T T φ+T−1∂Tφ=1
4βe−2η∂ssφ. Setting Ae−η= 2πand 4βe2η= 1, we can use
the results of Jurke (cf. [11]) obtained in the case of polarized Gowdy T3-models
(here Wis replaced by φ,tby T, the period of the space coordinate is 2π). The
equations are similar with the same boundary conditions. Following this, for all
(t, r)∈[1,∞[×Rand T=t2,φmust be in this form :
φ(t, r) = (a1+ 2blog t(homogeneous case)
a1+ 2blog t+t−1α(t, r) + β(t, r) (non-homogeneous case)
(4.11)
where a1and bare constants fixed by initial values of φand ˙
φ,αand βreal-
valued C2-functions with |α|,|α0| ≤ C,|˙α| ≤ Ct,|β|,|β0| ≤ Ct−3,|˙
β| ≤
Ct−2,Ca positive constant and 1
4(t−2∂tt −t−3∂t)α(t, r) = ∂rrα(t, r). We
deduce that |˙
φφ0| ≤ Ct−1.
¿From the field equation (1.4), we have :
2t˙µ= 1 + 8πt2e2µp
i.e
˙µ=1
2t+ 2πt(˙
φ2+e2µ−2λφ02) = 1
2t+ 2πt(˙
φ2+ 4t2φ02)
¿From (1.3)
2t˙
λ=−1+8πt2e2µρ
i.e
˙
λ=−1
2t+ 2πt(˙
φ2+e2µ−2λφ02) = −1
2t+ 2πt(˙
φ2+ 4t2φ02)
We deduce from the expression of φ, that ˙µand ˙
λare bounded each by a
positive constant C. From Theorem 15 of [11] (the hypothesis of this theorem
69
are satisfied : atis replaced here by ˙µ), µcan be cast for all (t, r)∈[1,∞[×R
into the form
µ(t, r) = (1
2(16πb2+ 1) log t+γif µ0= 0
νt2+δ(t, r) (non-homogeneous case) (4.12)
where νis a positive constant, γa constant fixed by initial value of µand the
function δsatisfies the inequalities, |δ(t, r)| ≤ C(1+t), |˙
δ| ≤ Ct with a positive
constant C. Note that if φ0= 0 then from equation (1.5), µ0= 0 and λ0= 0;
the solutions are independent of rand we are in the homogeneous case. Since
˙
λ−˙µ=−t−1, we deduce that λ(t, r) = µ(t, r)−log t+◦
λ(r)−◦
µ(r).
4.2.2 Geodesic completeness
Let ]τ−, τ+[3τ7→ (xα(τ), pβ(τ)) be a geodesic whose existence interval is max-
imally extended and such that x0(τ0) = t(τ0) = 1 for some τ0∈]τ−, τ+[. We
want to show that for future-directed timelike and null geodesics, τ+= +∞.
Consider first the case of a timelike geodesic, i.e.,
gαβpαpβ=−m2;p0>0
with m > 0. Since dt/dτ =p0>0, the geodesic can be parameterized by the
coordinate time t. Recall that along the geodesics the variables
t,r,p0,w:= eλp1,F:= t4(p2)2+ sin2
kθ(p3)2satisfy the following system of
differential equations :
dr
dτ =e−λw, dw
dτ =−˙
λp0w−e2µ−λµ0(p0)2,dF
dτ = 0 (4.13)
dt
dτ =p0,dp0
dτ =−˙µ(p0)2−2e−λµ0p0w−e−2µ˙
λw2−e−2µt−3F. (4.14)
With respect to coordinate time the geodesic exists on the interval [1,∞[ since
on bounded t-intervals the Christoffel symbols are bounded and the right hand
sides of the geodesic equations written in coordinate time are linearly bounded
in p1,p2,p3. Along the geodesic we define wand Fas above. Then the relation
between coordinate time and proper time along the geodesic is given by
dt
dτ =p0=e−µpm2+w2+F/t2,
and to control this we need to control was a function of coordinate time.
70
The plane symmetric case without Vlasov
Assume that w(t)>0 for some t≥1. By (4.13) and the fact that |˙
φ||φ0|(t)≤
Ct−1,e(µ−λ)(t)=e−ηt, we have as long as w(s)>0
d
dsw(s) = −˙
λw −e2µ−λµ0p0= 4πse2µ(jpm2+w2+F/s2−ρw) + 1
2sw
≤1
2sw−4πse2µρw +|4πse2µj(w+pm2+F/s2)|
≤1
2sw+ 4πse2µ|j|pm2+F/s2since |j| ≤ ρ
≤1
2sw+ 4πseµ−λ|˙
φ||φ0|pm2+F/s2
≤1
2sw+Cs
(4.15)
Let t0∈[1, t[ be defined minimal such that w(s)>0 for s∈[t0, t[. Then
Gronwall’s inequality shows that
w(t)≤w(t0) + CZt
t0
sexp(Zt0
s
dτ
2τ)dsexp(Zt
t0
dτ
2τ).
Now either t0= 1 and w(t0) = w(1) or t0>1 and w(t0) = 0 (t0is the minimal).
Thus
w(t)≤|w(1)|+CZt
1
sexp(Z1
s
dτ
2τ)dsexp(Zt
1
dτ
2τ)≤Ct2.
Estimating ˙w(s) from below in the case w(s)<0 along the same lines yields
the upper bound of −w(t).
Since |δ| ≤ C(1 + t), νt2+δ > νt2−C(1 + t) = νt2(1 −C(1+t)
νt2). For tlarge, we
choose C(1+t)
νt2<1
2i.e νt2+δ > 1
2νt2. Then along the geodesic we have :
dτ
dt =eµ
pm2+w2+F/t2=eνt2+δ
pm2+Ct4+F/t2
≥e1
2νt2
t2√m2+C+F≥νt2
2t2√m2+C+F= constant.
Since the left hand side is constant, the integral over [1,∞[ diverges.
In the homogeneous case (ν= 0, j= 0, ρ≥0), (4.15) becomes
d
dsw(s)≤1
2sw
and we can prove similarly as above that w(t)≤Ct1/2for t≥1. Therefore
dτ
dt =e1
2(16πb2+1) log t+γ
pm2+Ct +F/t2≥t1
2(16πb2+1)eγ
t1/2√m2+C+F≥Ct8πb2
71
The integral on the right hand side of the above inequality over [1,∞[ diverges.
In either case, we conclude that τ+= +∞as desired.
In the case of a future-directed null geodesic, i.e. m= 0 and p0(τ0)>0, p0is
everywhere positive and the quantity Fis again conserved. The argument can
now be carried out exactly as in the timelike case, implying that τ+= +∞. We
have proven :
Theorem 4.5 Consider initial data with plane symmetry for the Einstein-scalar
field system written in areal coordinates. Then the corresponding spacetime is
timelike and null geodesically complete in the expanding direction.
Remark 4.6 In the homogeneous plane symmetric case with only a scalar field,
ρ(t) = p(t) = 1
2e−2µ˙
φ2,(˙
λ−˙µ)(t) = −t−1and solving the wave equation, we
obtain |˙
φ(t)|=|ψ|t−1. From the field equations, ˙
λ(t) = (2πψ2−1
2)t−1and
λ(t) = ◦
λ+ (2πψ2−1
2) log t;µ(t) = ◦
µ+ (2πψ2+1
2) log t;
ρ(t) = p(t) = 1
2ψ2e−2◦
µt−3−4πψ2;j(t) = 0 ;q(t) = 2p(t).
We can compute the limiting values of the generalized Kasner exponents :
t˙
λ= 2πψ2−1
2;
lim
t→∞
K1
1(t, r)
K(t, r)= lim
t→∞
t˙
λ(t, r)
t˙
λ+ 2 =4πψ2−1
4πψ2+ 3 ;
lim
t→∞
K2
2(t, r)
K(t, r)= lim
t→∞
K3
3(t, r)
K(t, r)= lim
t→∞
1
t˙
λ+ 2 =2
4πψ2+ 3,
The spatially homogeneous case
Consider now the Einstein-Vlasov-scalar field system for k≤0. We study the
future behaviour for solutions which are independent of the space coordinate r.
In this case µ0= 0, φ0= 0 and equation (1.5) shows that j= 0.
We prove that w(t) is bounded for finite time tand the spacetime obtained
is geodesically complete. Since ρ≥0, j= 0 and k≤0, we have from (4.13) as
long as w(s)>0,
d
dsw(s) = −˙
λw −e2µ−λµ0p0= 4πse2µ(jpm2+w2+F/s2−ρw) + 1 + ke2µ
2sw
=−4πse2µρw +1 + ke2µ
2sw
≤1
2sw
and we can prove as above that w(t)≤Ct1/2for t≥1. Using (4.1), e2µ≥t
C≥
1
Cfor k= 0; and e2µ≥t
C+t=1
1+C/t ≥1
1+Cfor k=−1. In each case, eµ≥C.
72
Then along the geodesic,
dτ
dt =eµ
pm2+w2+F/t2≥C
pm2+Ct +F/t2
≥C
t1/2√m2+C+F≥Ct−1/2.
The integral on the right hand side over [1,∞[ diverges. Therefore τ+= +∞.
In the case of a future-directed null geodesic, the argument is the same as what
we done in the previous subsection.
In the homogeneous case, a number of further estimates can also be obtained.
We follow the proof of Theorem 4.1 and [17] to obtain a better bound of µwhich
depends explicitly on the data. Recall (4.3)
d
dt(eµ+λρ)(t) = −1
teµ+λ2ρ+q−ρ+p
2(1 + ke2µ).
Since q≥0, we obtain :
for k= 0, d
dt(eµ+λρ)(t)≤ −1
teµ+λρ(t);
thus
eµ+λρ(t)≤e
◦
µ+
◦
λ◦
ρt−1; (4.16)
for k=−1
d
dt(eµ+λρ)(t)≤ −1
teµ+λ2ρ−ρ+p
2−1
C0+t
ρ+p
2
≤eµ+λρ−1
t−1
C0+t
≤ − 2
C1+teµ+λρ(t)
where C0=k+e−2◦
µ(see (4.1)) and C1= max(0, C0). Thus
eµ+λρ(t)≤(C1+ 1)2e
◦
µ+
◦
λ◦
ρt−2.(4.17)
Next we have similarly to (4.5),
eµ−λ≤e
◦
µ−
◦
λtfor k = 0 (4.18)
and
eµ−λ≤e
◦
µ−
◦
λe−2◦
µt
e−2◦
µ−1 + tfor k = −1
If ◦
µ≤0 then t
e−2◦
µ−1+t≤1. If ◦
µ≥0 then e−2◦
µt
e−2◦
µ−1+t≤1. Thus in either case,
eµ−λ≤e|◦
µ|−
◦
λfor k = −1 (4.19)
73
Now
µ(t) = ◦
µ+Zt
1
˙µ(s)ds =◦
µ+Zt
1
1
2s[e2µ(8πs2p+k) + 1]ds.
For k= 0,
µ(t)≤◦
µ+1
2log t+ 4πZt
1
se2µρds =◦
µ+1
2log t+ 4πZt
1
seµ−λeµ+λρds
≤◦
µ+1
2log t+ 4πe
◦
µ+
◦
λ◦
ρe
◦
µ−
◦
λZt
1
sds
≤◦
µ+1
2log t+ 2πe2◦
µ◦
ρt2
i.e
µ(t)≤◦
µ+ 2πe2◦
µ◦
ρt2.(4.20)
For k=−1,
µ(t)≤◦
µ+ 4πZt
1
se2µρds +Zt
1
1
2s(1 −e2µ)ds
≤◦
µ+ 4πZt
1
seµ−λeµ+λρds +Zt
1
1
2s(1 −s
C0+s)ds
≤◦
µ+ 4π(C1+ 1)2e|◦
µ|−
◦
λ◦
ρe
◦
µ+
◦
λZt
1
s−1ds +Zt
1
1
2(1
s−1
C0+s)ds
≤◦
µ+1
2log(C0+1)+4π(C1+ 1)2e|◦
µ|+◦
µ◦
ρZt
1
s−1ds
i.e
µ(t)≤◦
µ+1
2log(C0+1)+4πe|◦
µ|+◦
µ◦
ρ(C1+ 1)2log t. (4.21)
We have proven :
Theorem 4.7 Consider spatially homogeneous solutions of plane and hyper-
bolic symmetric Einstein-Vlasov-scalar field system written in areal coordinates
and initial data given for t= 1. Then these solutions exist on the whole in-
terval [1,∞[. The corresponding spacetimes are timelike and null geodesically
complete in the expanding direction and estimates (4.16)-(4.17)-(4.18)-(4.19)-
(4.20)-(4.21) hold.
74
Conclusion
We have investigated in spherical, plane and hyperbolic symmetry, cosmological
solutions of the Einstein-Vlasov-scalar field system. But their are some remain-
ing problems listed as follows :
- past global existence for k=−1 without any restriction on the data;
- asymptotics in the past direction with Vlasov matter. Maybe the idea of [24]
could be used here?
- future geodesic completeness in general;
- future asymptotics. Maybe one can use the results of [26] which study the
future asymptotic behavior of massless scalar fields in a class of cosmological
vacuum spacetimes;
- in the case of a non-linear scalar field, using our approach can we obtain sim-
ilar results as in the case of non-vanishing cosmological constant?
Thus it appears that the work of this thesis can serve as a useful starting point
for future investigations.
75
Appendices
Appendix A
Here we establish relations (2.26) and (2.27). Relation (2.8) gives :
e−µn−1(˙
˜gn−˙
˜
hn) + e−λn−1(˜g0
n−˜
h0
n) = an−1(˜gn−1−˜
hn−1) + bn−1(˜gn−1+˜
hn−1)
i.e
e−µn−1˙
˜gn−e−λn−1˜
h0
n=e−µn−1˙
˜
hn−e−λn−1˜g0
n+(an−1+bn−1)˜gn−1+(bn−1−an−1)˜
hn−1
Therefore,
D+
n˜
Xn=D+
n(˜gn+1 −˜
hn+1)−D+
n(˜gn−˜
hn)
=an(˜gn−˜
hn) + bn(˜gn+˜
hn)−e−µn(˙
˜gn−˙
˜
hn)−e−λn(g0
n−h0n)
= (an+bn)˜gn+ (bn−an)˜
hn−˙
˜gn(e−µn−e−µn−1) + ˜
h0
n(e−λn−e−λn−1)
+˙
˜
hne−µn−˜g0
ne−λn−˙
˜gne−µn−1+˜
h0
ne−λn−1
= (an+bn)˜gn+ (bn−an)˜
hn−˙
˜gn(e−µn−e−µn−1) + ˜
h0
n(e−λn−e−λn−1)
+˙
˜
hne−µn−˜g0
ne−λn−e−µn−1˙
˜
hn+e−λn−1˜g0
n−(an−1+bn−1)˜gn−1−(bn−1−an−1)˜
hn−1
= (an+bn)(˜gn−˜gn−1)+(bn−an)(˜
hn−˜
hn−1)+(an+bn−an−1−bn−1)˜gn−1
+ (bn−an+an−1−bn−1)˜
hn−1+ (e−µn−e−µn−1)(˙
˜
hn−˙
˜gn)+(e−λn−e−λn−1)(˜
h0
n−˜g0
n)
=an[(˜gn−˜gn−1)−(˜
hn−˜
hn−1)] + bn[(˜gn−˜gn−1)+(˜
hn−˜
hn−1)]
+ (an+bn−an−1−bn−1)˜gn−1+ (bn−an+an−1−bn−1)˜
hn−1
+ (e−µn−e−µn−1)(˙
˜
hn−˙
˜gn)+(e−λn−e−λn−1)(˜
h0
n−˜g0
n)
=an˜
Xn−1+bn˜
Yn−1+Fn
If we replace ˜
h0
nand ˜g0
nrespectively by −˜
h0
nand −˜g0
n, (2.8) and (2.9), D+
nand
D−
n,˜
Xnand ˜
Yninterchange respectively and we can write (2.27).
76
Appendix B
Let us prove relations (2.56) and (2.57). We have
∂r(D+
nXn+1) = (∂rD+
n)Xn+1 +D+
nX0
n+1
i.e
D+
nX0
n+1 =∂r(D+
nXn+1)−(∂rD+
n)Xn+1
=C0
n+µ0
ne−µn∂tXn+1 +λ0
ne−λnX0
n+1
We deduce from relation (e−µn∂t+e−λn∂r)Xn+1 =Cn, that
e−µn∂tXn+1 =Cn−e−λnX0
n+1
Therefore
D+
nX0
n+1 =C0
n+µ0
nCn+λ0
ne−λnX0
n+1 −µ0
ne−λnX0
n+1
=C0
n+ (λ0
n−µ0
n)e−λnX0
n+1 +µ0
nCn=˜
Cn
If we replace rby −r(i.e ∂rby −∂r), D+
nand D−
n,Xn+1 and Yn+1 interchange
respectively and we can write (2.57).
Appendix C
Let us prove inequalities (2.66)-(2.67). we have from (2.55)
˜
Cn+˜
Cn−1= (λ0
n−µ0
n)e−λnX0
n+1 −(λ0
n−1−µ0
n−1)e−λn−1X0
n
+µ0
nCn−µ0
n−1Cn−1+˜
C0
n−˜
C0
n−1
Now we obtain the following relations :
i) (λ0
n−µ0
n)e−λnX0
n+1 −(λ0
n−1−µ0
n−1)e−λn−1X0
n= (λ0
n−µ0
n)e−λn(X0
n+1 −X0
n)
+ [(λ0
n−µ0
n)e−λn−(λ0
n−1−µ0
n−1)e−λn−1]X0
n
= (λ0
n−µ0
n)e−λn(˜g0
n+1 −˜g0
n+˜
h0
n−˜
h0
n+1) + [(λ0
n−λ0
n−1)e−λn
−(µ0
n−µ0
n−1)e−λn+ (λ0
n−1−µ0
n−1)(e−λn−e−λn−1]X0
n
ii)µ0
nCn−µ0
n−1Cn−1= (µ0
n−µ0
n−1)Cn+µ0
n−1(Cn−Cn−1)
iii)˜
C0
n+˜
C0
n−1=a0
nXn+anX0
n+b0
nYn+bnY0
n−a0
n−1Xn−1−an−1X0
n−1−b0
n−1Yn−1−bn−1Y0
n−1
= (a0
n−a0
n−1)Xn+a0
n−1(Xn−Xn−1)+(an−an−1)X0
n+an−1(X0
n−X0
n−1)
+ (b0
n−b0
n−1)Yn+b0
n−1(Yn−Yn−1)+(bn−bn−1)Y0
n+bn−1(Y0
n−Y0
n−1)
77
iv)a0
n−a0
n−1=−µ0
n(−˙
λn−1
t−˙
λ0
n)e−µn+ (−˜µ0
n+ ˜µ0
nλ0
n)e−λn
+µ0
n−1(−˙
λn−1−1
t−˙
λ0
n−1)e−µn−1+ (−˜µ0
n−1+ ˜µ0
n−1λ0
n−1)e−λn−1
= (µ0
n−1−µ0
n)(−˙
λn−1
t)e−µn−µ0
n−1[(−˙
λn−1
t)e−µn+ (−˙
λn−1−1
t)e−µn−1]
+ ( ˙
λ0
n−1−˙
λ0
n)e−µn−˙
λ0
n−1(e−µn−e−µn−1) + (˜µ0
n−1−˜µ0
n)e−λn
−˜µ0
n−1(e−λn−e−λn−1)+(λ0
n−λ0n−1)˜µne−λn+λ0n−1(˜µne−λn−˜µn−1e−λn−1)
v)b0
n−b0
n−1=µ0
n
te−µn−µ0
n−1
te−µn−1
=1
t(µ0
n−µ0
n−1)e−µn+µ0
n−1
t(e−µn−e−µn−1)
Using remark 2.2, (2.36) and (2.40), we obtain respectively from i), ii), iv) and
v) the following estimations :
|(λ0
n−µ0
n)e−λnX0
n+1 −(λ0
n−1−µ0
n−1)e−λn−1X0
n| ≤ C+C(|˜g0
n+1 −˜g0
n|+|˜
h0
n+1 −˜
h0
n|
+|µ0
n−µ0
n−1|+|λ0
n−λ0
n−1|)
≤C +C(γn(τ) + γn−1(τ))
|µ0
nCn−µ0
n−1Cn−1| ≤ |µ0
n−µ0
n−1||Cn|+|µ0
n−1||Cn−Cn−1|
≤C +Cγn−1(τ)
|a0
n−a0
n−1| ≤ C+ (|µ0
n−1−µ0
n|+|˙
λ0
n−1−˙
λ0
n|+|˜µ0
n−1−˜µ0
n|+|λ0
n−λ0
n−1|)
≤C +Cγn−1(τ)
|b0
n−b0
n−1| ≤ C +C|µ0
n−µ0
n−1| ≤ C +Cγn−1(τ)
|X0
n−X0
n−1|,|Y0
n−Y0
n−1| ≤ C(|˜g0
n−1−˜g0
n|+|˜
h0
n−1−˜
h0
n|)≤Cγn−1(τ)
Using this, we deduce from iii) that
|˜
C0
n+˜
C0
n−1| ≤ C +C(γn(τ) + γn−1(τ))
Combining all the necessary estimates, (2.66) follows. Similarly, we prove in-
equality (2.67).
78
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